/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 On a frictionless. horizuntal ai... [FREE SOLUTION] | 91Ó°ÊÓ

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On a frictionless. horizuntal air table, puck \(A\) (with mass \(0.250 \mathrm{~kg}\) ) is moving toward puck \(B\) (with mass \(0.350 \mathrm{~kg}\) ), which is initially at rest. After the collision, puck \(A\) has a velocity of \(0.120 \mathrm{~m} / \mathrm{s}\) to the left, and puck \(B\) has a velocity of \(0.650 \mathrm{~m} / \mathrm{s}\) to the right. (a) What was the speed of puck \(A\) before the collision? (b) Culculate the changc in the total kinctic cncrgy of the system that occurs during the collision.

Short Answer

Expert verified
The speed of puck A before the collision was approximately 0.65 m/s. The change in the total kinetic energy of the system during the collision was approximately \(0.1 \mathrm{~J}\)

Step by step solution

01

Calculate Initial Momentum

First, calculate the initial momentum. This equals the sum of the momenta of both pucks after the collision since momentum is conserved. The momentum of a body is given by the product of its mass and velocity. Thus, momentum of puck A after the collision is \(0.250 \mathrm{~kg} \times -0.120 \mathrm{~m/s}\) (negative because the direction is to the left) and that of puck B is \(0.350 \mathrm{~kg} \times 0.650 \mathrm{~m/s}\) (positive because the direction is to the right).
02

Find Initial Velocity of Puck A

Subtract the momentum of puck B from the total momentum to get the initial momentum of puck A which equals its mass times its initial velocity. Solve the resulting equation for the initial velocity of puck A.
03

Calculate Kinetic Energy before and after collision

Calculate the kinetic energy of the system before and after the collision. The kinetic energy is given by half the mass times the square of the velocity.
04

Find the Change in Kinetic Energy

Subtract the total kinetic energy after the collision from the total kinetic energy before the collision to find the change in kinetic energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
Understanding the laws of physics can often feel overwhelming, but by breaking down concepts such as momentum conservation, it becomes more digestible. In the realm of collision theory physics, momentum conservation is a fundamental principle stating that in the absence of external forces, the total momentum of a system remains constant before and after a collision.

For instance, when two hockey pucks glide and collide on a frictionless surface—like our air table example—it’s momentum conservation that underpins the solution to finding puck A's initial speed. During a collision, the combined momentum of both pucks remains unchanged from before they collided to after. It's crucial to distinguish that while velocities can change direction or magnitude upon impact, the vector sum of both objects' momentum will not vary, assuming no external forces are involved.

This principle is beautifully reliable in physics, allowing us to calculate unknown quantities, such as the velocity of puck A before the collision in our exercise. The equation is straightforward: add up the individual momenta after the impact and set it equal to the total momentum before the impact. This approach leads us straight to the answers we seek, all thanks to the dependable conservation of momentum.
Kinetic Energy
Now let's tackle kinetic energy, a concept that often buzzes around the topic of motion. Kinetic energy is the energy an object possesses due to its movement. It depends on both the mass of the object and the square of its velocity. In essence, the faster an object moves, or the more massive it is, the more kinetic energy it packs.

The formula for kinetic energy is given by \( KE = \frac{1}{2} mv^2 \) where \( m \) is mass and \( v \) is velocity. When solving physics problems such as our puck collision, calculating kinetic energy both before and after the event enables us to measure the effect of the collision in terms of energy transfer or transformation.

Especially when analyzing inelastic collisions, understanding how kinetic energy transforms is key. To illustrate, in our exercise, we use the kinetic energy formula to compute the total energy before and after the pucks collide, providing deep insights into the nature of the collision, including whether energy was lost, conserved, or transformed into other forms.
Inelastic Collision
In an inelastic collision, unlike an elastic collision, objects stick together or deform, and kinetic energy is not conserved (though momentum is). This concept is essential in understanding the outcome of many real-world collisions.

When puck A strikes puck B on the air table, the pucks do not stick together, but the principle still applies because some kinetic energy is transformed into other forms, like thermal energy or sound. During an inelastic collision, the main takeaway is that while the total energy of the system is conserved, not all of the energy remains as kinetic.

The exercise we’re examining asks us to calculate the change in the total kinetic energy. This calculation highlights whether the collision is perfectly elastic (no change in total kinetic energy), perfectly inelastic (maximum loss of kinetic energy), or somewhere in between. By calculating the kinetic energies before and after and observing a reduction, we can determine the collision is indeed inelastic. Exploring concepts like inelastic collision not only provides answers to physics problems but also gives insights into the energy changes that occur during everyday occurrences like car crashes or sporting activities.

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Most popular questions from this chapter

A block with mass \(0.500 \mathrm{~kg}\) sits at rest on a light but not long vertical spring that has spring constant \(80.0 \mathrm{~N} / \mathrm{m}\) and one end on the floor. (a) How much clastic potential cnergy is stored in the spring when the block is sitting at rest on it? (b) A second identical block is dropped onto the first from a height of \(4.00 \mathrm{~m}\) above the first block and sticks to it. What is the maximum elastic potential energy stored in the spring during the motion of the blocks after the collision? (c) What is the maximum distance the first block moves down after the second block has landed on it?

Just before it is struck by a racket, a tennis ball weighing \(0.560 \mathrm{~N}\) has a velocity of \((20.0 \mathrm{~m} / \mathrm{s}) \hat{\imath}-(4.0 \mathrm{~m} / \mathrm{s}) \hat{\jmath} .\) During the \(3.00 \mathrm{~ms}\) that the racket and ball are in contact, the net external force on the ball is constant and equal to \(-(380 \mathrm{~N}) \hat{\imath}+(110 \mathrm{~N}) \hat{\jmath}\). What are the \(x\) - and \(y\) -components (a) of the impulse of the net external force applied to the ball; (b) of the final velocity of the ball?

Jonathan and Jane are sitting in a sleigh that is at rest on frictionless ice. Jonathan's wcight is \(800 \mathrm{~N}\), Jane's weight is \(600 \mathrm{~N}\), and that of the sleigh is \(1000 \mathrm{~N}\). They see a poisonous spider on the floor of the sleigh and immediately jump off. Jonathan jumps to the left with a velocity of \(5.00 \mathrm{~m} / \mathrm{s}\) at \(30.0^{\circ}\) above the horizontal (relative to the ice), and Jane jumps to the right at \(7,00 \mathrm{~m} / \mathrm{s}\) at \(36.9^{\circ}\) above the horizontal (relative to the ice). Calculate the sleigh's horizontal velocity (magnitude and direction) after they jump out.

A rifle bullet with mass \(8.00 \mathrm{~g}\) strikes and embeds itself in a block with mass \(0.992 \mathrm{~kg}\) that rests on a frictionless, horizontal surface and is attached to an ideal spring (Fig. \(\mathrm{P} 8.79\) ). The impact compresses the spring \(15.0 \mathrm{~cm} .\) Calibration of the spring shows that a force of 0.750 \(\mathrm{N}\) is required to compress the spring \(0.250 \mathrm{~cm}\). (a) Find the magnitude of the block's velocity just after impact. (b) What was the initial speed of the bullct?

Automobile Accident Analysis. You are called as an expent witness to analyre the following auto accident: Car \(B\), of mass \(1900 \mathrm{~kg}\), was stopped at a red light when it was hit from bchind by car \(A\), of mass \(1500 \mathrm{~kg}\). The cars locked bumpers during the collision and slid to a stop with hrakes locked on all wheels. Measurements of the skid marks left by the tires showed them to be \(7.15 \mathrm{~m}\) long. The coeflicient of kinetic friction between the tires and the road was 0.65 . (a) What was the speed of car \(A\) just before the collision? (b) If the speed limit was \(35 \mathrm{mph}\), was car \(A\) spceding, and if so, by how many milcs per hour was it exceeding the speed limit?

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