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If a fish is attached to a vertical spring and slowly lowered to its equilibrium position, it is found to stretch the spring by an amount \(d\). If the same fish is attached to the end of the unstretched spring and then allowed to fall from rest, through what maximum distance does it stretch the spring? (Hint: Calculate the force constant of the spring in terms of the distance \(d\) and the mass \(m\) of the fish.)

Short Answer

Expert verified
The maximum distance the spring stretches is given by \(d \cdot \sqrt{2}\).

Step by step solution

01

Find Force Constant

Find the spring constant \(k\) by setting up the equation, \(mg = k \cdot d\), solving for \(k\) gives \(k=m \cdot g / d\) where \(m\) is the mass of the fish, \(g\) is acceleration due to gravity, and \(d\) is the initial stretch of the spring caused by fish's weight.
02

Equating Potential Energy to Elastic Potential Energy

The energy conservation principle states that the initial potential energy equals the elastic potential energy when the spring is stretched to its maximum. Formulate this by \(mgh = 1/2 \cdot k \cdot x^2\) where \(h\) is the height the fish falls from (the same as \(d\) in this case) and \(x\) is the maximum stretch.
03

Solve for Maximum Stretch of Spring

Substitute \(k\) from Step 1 into the equation from Step 2, to get \(m \cdot g \cdot d = 1/2 \cdot (m \cdot g / d) \cdot x^2\). This equation simplifies to \(2d^2 = x^2\). Therefore \(x = d \cdot \sqrt{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hooke's Law
Imagine a spring, the kind you might find in a pen or a toy. When you apply a force to stretch or compress it, the spring reacts with a force of its own to restore its original shape. This is where Hooke's Law comes into play, which can be stated in a simple equation:
\( F = -kx \)
Here's what each symbol means:
  • \(F\) is the restoring force exerted by the spring, measured in newtons (N).
  • \(k\) is the spring constant, which tells us how stiff the spring is. It's measured in newtons per meter (N/m).
  • \(x\) is the displacement from the spring's original length, measured in meters (m).
The negative sign indicates that the force exerted by the spring is in the opposite direction of the displacement. By understanding this law, we create a foundation for exploring how springs behave and how they store energy, which is particularly useful in problems like the textbook exercise on the spring and fish.
Elastic Potential Energy
When you stretch a spring, you're doing work against the spring's natural force. This work gets stored as elastic potential energy (EPE), and it's ready to spring back into action—quite literally! In mathematical terms, this energy can be calculated using the formula:
\( EPE = \frac{1}{2} kx^2 \)
This equation links directly to Hooke's Law:
  • \(k\) still represents the spring constant—a measure of the spring's stiffness.
  • \(x\) is the displacement, meaning how far the spring has been stretched or compressed from its natural length.
The beauty of EPE is its role in many physics problems involving springs, including our textbook example. By calculating it, students can understand how energy transforms and is conserved when forces act on a spring.
Conservation of Energy
A principle that's as sure as the ground beneath our feet is the conservation of energy. It says that the total energy in an isolated system remains constant—it can neither be created nor destroyed, only transformed from one form to another. Let's put this into context with the falling fish: As the fish falls, its gravitational potential energy is converted into elastic potential energy of the spring. Using the conservation of energy, we can equate the fish's initial potential energy when it's held at height \(d\) to the spring's elastic potential energy at its maximum stretch. The idea is that the energy content of the fish-plus-spring system remains unchanged throughout the process, hence allowing us to set up an equation to find the maximum distance the spring stretches. This is a crucial concept, not just in physics puzzles, but in understanding the natural universe.
Simple Harmonic Motion
The up and down bobbing of a fish on a spring or the to-and-fro swing of a pendulum are examples of simple harmonic motion (SHM)—a type of periodic movement that is particularly predictable. A system in SHM will oscillate back and forth over the same path, within the same amount of time for each cycle, provided there’s no external force causing it to lose energy (like friction or air resistance).
The most important aspect of SHM is that it's governed by a restoring force directly proportional to the displacement and directed towards the equilibrium position—the very principle laid out by Hooke's Law. In the case of our textbook's fish, if we disregard air resistance and other non-conservative forces, it would oscillate around the equilibrium position in a simple harmonic manner once it has been dropped and stretched the spring, adding a layer of real-world complexity and application to the basic principles of physics.

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Most popular questions from this chapter

BIO Tendons. Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laboratory tests on a particular tendon, it was found that, when a \(250 \mathrm{~g}\) object was hung from it, the tendon stretched \(1.23 \mathrm{~cm}\). (a) Find the force constant of this tendon in \(\mathrm{N} / \mathrm{m}\). (b) Because of its thickness, the maximum tension this tendon can support without rupturing is 138 N. By how much can the tendon stretch without rupturing. and how much energy is stored in it at that point?

You are designing a delivery ramp for crates containing exercise equipment. The \(1470 \mathrm{~N}\) crates will move at \(1.8 \mathrm{~m} / \mathrm{s}\) at the top of a ramp that slopes downward at \(22.0^{\circ} .\) The ramp exerts a \(515 \mathrm{~N}\) kinctic friction force on cach crate, and the maximum static friction force also has this value. Each crate will compress a spring at the bottom of the ramp and will come to rest after traveling a total distance of \(5.0 \mathrm{~m}\) along the ramp. Once stopped, a crate must not rebound back up the ramp. Calculate the largest force constant of the spring that will be needed to meet the design criteria.

A system of two paint buckets connected by a lightweight rope is released from rest with the \(12.0 \mathrm{~kg}\) bucket \(2.00 \mathrm{~m}\) above the floor (Fig. \(\mathbf{P 7 . 5 1}\) ). Use the principle of conservation of energy to find the speed with which this bucket strikes the floor. Ignore friction and the mass of the pulley.

Tarzan and Jane. Tarzan, in one tree, sights Jane in another tree. He grabs the end of a vine with length \(20 \mathrm{~m}\) that makes an angle of \(45^{\circ}\) with the vertical, steps off his tree limb, and swings down and then up to Jane's open arms. When he arrives, his vine makes an angle of \(30^{\circ}\) with the vertical. Determine whether he gives her a tender embrace or knocks her off her limb by calculating Tarzan's speed just before he reaches Jane. Ignore air resistance and the mass of the vine.

An ideal spring stores potential energy \(U_{0}\) when it is compressed a distance \(x_{0}\) from its uncompressed length. (a) In terms of \(U_{0}\). how much energy does the spring store when it is compressed (i) twice as much and (ii) half as much? (b) In terms of \(x_{0}\). how much must the spring be compressed from its uncompressed length to store (i) twice as much energy and (ii) half as much energy?

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