/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A \(75.0 \mathrm{~kg}\) painter ... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(75.0 \mathrm{~kg}\) painter climbs a ladder that is \(2.75 \mathrm{~m}\) long and leans against a vertical wall. The ladder makes a \(30.0^{\circ}\) angle with the wall. (a) How much work does gravity do on the painter? (b) Does the answer to part (a) depend on whether the painter climbs at constant speed or accelerates up the ladder?

Short Answer

Expert verified
The work done by gravity on the painter is -1012.25 Joules. No, the answer does not depend on whether the painter ascends at constant speed or accelerates up the ladder.

Step by step solution

01

Calculate the Height

The height at which the painter climbs can be calculated using the sine of the given angle (30 degrees) times the length of the ladder. So, Height = Length of ladder x sin(30 degrees) = 2.75 m x sin(30) = 1.375 m.
02

compute the Work Done by Gravity

The painter's weight (mass x gravity) acts downwards while he climbs up, creating an angle of 180 degrees between the force and displacement. The work done by a force is given by the formula:Work = Force x distance x cos(θ) = mgh x cos(180 degrees),where m is the mass, g is the gravitational acceleration, and h is the height calculated in step 1, and θ is the angle between the direction of force and displacement, which is 180 degrees for this case. Thus, Work = 75 kg x 9.8 m/s² x 1.375 m x cos(180 degrees) = -1012.25 J.
03

Understand that gravity's Work Does not Depend on Speed or Acceleration

The amount of work gravity does on the painter is completely independent of whether the painter is climbing at a constant speed or is accelerating up the ladder. This is because the work done by gravity only depends on the vertical displacement of the object's center of mass. Whether the painter climbs slowly or quickly, the change in gravitational potential energy will be the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational Potential Energy (GPE) is the energy stored in an object due to its height above the ground. It is entirely due to the gravitational pull of the Earth acting on the object's mass. When you lift an object, you do work against gravity, thus the object gains potential energy. Understanding GPE is straightforward: consider the formula \( E_p = mgh \), where:
  • \(m\) is the mass of the object in kilograms.
  • \(g\) is the acceleration due to gravity \( (9.8 \, \text{m/s}^2) \).
  • \(h\) is the height in meters above the reference level.
This energy is crucial when discussing objects that move up or down, like our painter climbing the ladder. As the painter climbs, he gains gravitational potential energy because he's increasing height "h" in the formula. This potential energy would convert to kinetic energy if he fell, demonstrating energy conservation in physics.
Work Done by Gravity
The work done by gravity is a measure of the energy transferred by the gravitational force to the object as it moves through a displacement. Even though it might sound complex, it can be boiled down to a simple idea: gravity does work when it causes an object to move vertically.In scientific terms, the work formula is \( W = Fd \cos(\theta) \), where:
  • \(W\) is the work done by force.
  • \(F\) is the force applied which is the weight of the object (\(mg\)).
  • \(d\) is the displacement, in this case, vertical height (\(h\)).
  • \(\theta\) is the angle between force and displacement direction.
In our problem, gravity's work was calculated to be negative, \(-1012.25 \, J\) due to the angle \(180^{\circ}\), meaning that gravity opposed the movement of the painter. Key point to note: gravity's work is only determined by the change in vertical height—not by how fast or the path taken to reach that height.
Kinematics in Physics
Kinematics deals with motion without considering the forces that cause it. It encompasses concepts like speed, velocity, acceleration, and time. Though not directly used to calculate gravity's work in our problem, understanding kinematics helps grasp how motion affects energy changes. If the painter climbed up the ladder, his velocity, acceleration, or speed wouldn't influence the gravitational potential energy or work done by gravity. Why? Because both depend solely on the height reached and not on the temporal dynamics of the ascent:
  • Velocity: Would describe how fast the painter goes up but does not impact height gained.
  • Acceleration: Affects how quickly the painter reaches final velocity, irrelevant to gravitational calculations.
Kinematics aids in understanding the broader context of movement, allowing learners to see how time and speed relate to energy, even if they're not directly affecting gravitational potential energy calculations in cases like ours.

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Most popular questions from this chapter

Use the work-energy theorem to solve each of these problems. You can use Newton's laws to check your answers. (a) A skier moving at \(5.00 \mathrm{~m} / \mathrm{s}\) encounters a long, rough horizontal patch of snow having a coefficient of kinetic friction of 0.220 with her skis. How far does she travel on this patch before stopping? (b) Suppose the rough patch in part (a) was only \(2.90 \mathrm{~m}\) long. How fast would the skier be moving when she reached the end of the patch? (c) At the base of a frictionless icy hill that rises at \(25.0^{\circ}\) above the horizontal, a toboggan has a speed of \(12.0 \mathrm{~m} / \mathrm{s}\) toward the hill. How high vertically above the base will it go before stopping?

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