/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Two ropes are connected to a ste... [FREE SOLUTION] | 91Ó°ÊÓ

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Two ropes are connected to a steel cable that supports a hanging weight (Fig. P5.59). (a) Draw a freebody diagram showing all of the forces acting at the knot that connects the two ropes to the steel cable. Based on your diagram, which of the two ropes will have the greater tension? (b) If the maximum tension either rope can sustain without breaking is \(5000 \mathrm{~N},\) determine the maximum value of the hanging weight that these ropes can safely support. Ignore the weight of the ropes and of the steel cable.

Short Answer

Expert verified
The rope making a smaller angle with the vertical will face greater tension. The maximum weight these ropes can safely support will depend on the angles they make with the vertical, and can be calculated as the smallest maximum tension (5000N) divided by the sine of the bigger angle.

Step by step solution

01

Drawing a Free Body Diagram

Identify and illustrate all of the forces acting at the knot connecting the two ropes to the steel cable. Label all the forces appropriately.
02

Analyzing Forces

From the freebody diagram, consider the forces on the knot. If we assume the system is in equilibrium, the net forces in both horizontal and vertical directions should be zero. This means that the sum of the horizontal forces equals zero, and the same goes for the vertical forces.
03

Determining Tensions

Analyze the drawing to determine which of the two ropes will face greater tension. If one rope makes a smaller angle with the vertical direction, that rope will support a larger portion of the vertical force (weight) and therefore have a greater tension.
04

Calculating Maximum Load

To determine the maximum hanging weight the ropes can safely support, take the smallest maximum tension the ropes can safely support (5000N), and divide this by the sine of the angle for the rope with the larger angle to the vertical. The result is the maximum weight that can be supported.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium of Forces
Understanding the equilibrium of forces is crucial when analyzing problems in mechanics. The concept revolves around Newton's First Law of Motion which asserts that an object remains at rest or in uniform motion in a straight line unless acted upon by an external force.

In the context of the textbook exercise, ropes connected to a weight are in a static equilibrium, meaning the sum of all forces acting upon the system is zero. This condition requires that both the horizontal and vertical components of the forces balance each other out.

To properly analyze the equilibrium of a system:
  • Identify all forces acting on the object.
  • Determine the direction of each force.
  • Resolve each force into its horizontal and vertical components.
  • Set up equations that sum these components along each axis to zero.
Applying this to the knot where the ropes attach, we consider the gravitational pull of the weight and the tensions in the ropes that counteract this force.
Tension in Ropes
The concept of tension in ropes is typically analogous to a pulling force within strings, ropes, or cables that is transmitted along the length of the object. In mechanics, this tension is a force and is measured in newtons (N) in the International System of Units (SI).

For a rope in equilibrium:
  • The tension is uniform along the rope if the rope's weight is negligible and there are no other forces acting on it except at the endpoints.
  • The tension adjusts to match the external forces, ensuring the rope does not accelerate.
Determining the tension in each rope is essential in this exercise to ensure the safety factor. The tension can vary across ropes depending on the angle at which they are attached. A key point to remember is that a rope at a sharper angle with respect to the vertical will carry a higher proportion of the vertical load, yielding greater tension.
Force Analysis
The process of force analysis involves breaking down forces into understandable and calculable components to predict the behavior of physical systems. Effective force analysis often employs the use of a free body diagram, which shows all the external forces acting upon a single object.

For the exercise in discussion, the free body diagram aids in visualizing the forces at the knot connecting the ropes to the weight. Here's how we systematically perform force analysis:
  • Create a comprehensive free-body diagram, indicating all forces
  • Resolve complex forces into simple, component vectors
  • Apply equilibrium conditions to solve for unknowns
By calculating the vector sum of these forces, and setting them to zero for a system at rest, we can solve for unknowns such as the maximum weight the system can support without breaking the ropes. Such analysis is not only fundamental in this context but across various fields like engineering, physics, and even biomechanics.

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Most popular questions from this chapter

You are sitting on the edge of a horizontal disk (for example, a playground merry-go-round) that has radius \(3.00 \mathrm{~m}\) and is rotating at a constant rate about a vertical axis. (a) If the coefficient of static friction between you and the surface of the disk is \(0.400,\) what is the minimum time for one revolution of the disk if you are not to slide off? (b) Your friend's weight is half yours. If the coefficient of static friction for him is the same as for you, what is the minimum time for one revolution if he is not to slide off?

BIO Force During a Jump. When jumping straight up from a crouched position, an average person can reach a maximum height of about \(60 \mathrm{~cm} .\) During the jump, the person's body from the knees up typically rises a distance of around \(50 \mathrm{~cm} .\) To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump. (a) With what initial speed does the person leave the ground to reach a height of \(60 \mathrm{~cm} ?\) (b) Draw a free-body diagram of the person during the jump. (c) In terms of this jumper's weight \(w\), what force does the ground exert on him or her during the jump?

An \(8.00 \mathrm{~kg}\) block of ice, released from rest at the top of a 1.50-m-long friction less ramp, slides downhill, reaching a speed of \(2.50 \mathrm{~m} / \mathrm{s}\) at the bottom. (a) What is the angle between the ramp and the horizontal? (b) What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of \(10.0 \mathrm{~N}\) parallel to the surface of the ramp?

A block with mass \(m_{1}\) is placed on an inclined plane with slope angle \(\alpha\) and is connected to a hanging block with mass \(m_{2}\) by a cord passing over a small, friction less pulley (Fig. P5.74). The coefficient of static friction is \(\mu_{\mathrm{s}}\), and the coefficient of kinetic friction is \(\mu_{\mathrm{k}}\). (a) Find the value of \(m_{2}\) for which the block of mass \(m_{1}\) moves up the plane at constant speed once it is set in motion. (b) Find the value of \(m_{2}\) for which the block of mass \(m_{1}\) moves down the plane at constant speed once it is set in motion. (c) For what range of values of \(m_{2}\) will the blocks remain at rest if they are released from rest?

You are lowering two boxes, one on top of the other, down a ramp by pulling on a rope parallel to the surface of the ramp (Fig. E5.33). Both boxes move together at a constant speed of \(15.0 \mathrm{~cm} / \mathrm{s}\). The coefficient of kinetic friction between the ramp and the lower box is 0.444 , and the coefficient of static friction between the two boxes is 0.800 . (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?

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