/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 A steel ball with mass \(m\) is ... [FREE SOLUTION] | 91Ó°ÊÓ

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A steel ball with mass \(m\) is suspended from the ceiling at the bottom end of a light, 15.0 -m-long rope. The ball swings back and forth like a pendulum. When the ball is at its lowest point and the rope is vertical, the tension in the rope is three times the weight of the ball, so \(T=3 m g .\) (a) What is the speed of the ball as it swings through this point? (b) What is the speed of the ball if \(T=m g\) at this point, where the rope is vertical?

Short Answer

Expert verified
For the first case, where the tension is three times the weight of the ball, the speed of the ball is \(\sqrt{2rg}\). For the second case, where the tension equals the weight, the speed of the ball is zero.

Step by step solution

01

First scenario: Tension equals three times the weight

Recall Newton's second law in circular motion: the net force towards the center of the circle equals \(m v^2/r\). In this case, at the bottom of the swing, the net force is the tension of the rope minus the weight of the ball, so: \(T - mg = m v^2/r\). Given that \(T = 3mg\), you can substitute this into the equation and solve for \(v\): \[3mg - mg = m v^2/r\] which simplifies to: \[2mg = m v^2/r\] Solve this equation for \(v\), to find the speed of the ball.
02

Second scenario: Tension equals the weight

Going through a similar process, you start again from the formula: \(T - mg = m v^2/r\). Now, given that \(T = mg\), you substitute this into the equation, obtaining: \[mg - mg = m v^2/r\] Which simplifies to \[0 = m v^2/r\] From this, it follows directly that \(v = 0\). This makes sense, given that, if the tension is equal to the weight of the ball, there's no extra force to provide the circular motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in a Pendulum
When a pendulum swings, there's a tension force in the rope that acts on the object. This tension changes as the pendulum moves through different points of its path. At the lowest point of the swing, the tension is at its maximum.

Why? Because the tension must counteract not just the weight of the object but also provide the centripetal force required to change the direction of velocity as well. In our exercise, the tension is described as three times the weight of the ball, represented by the equation: \(T = 3mg\).

  • Here, \(T\) is the tension in the rope.
  • \(mg\) is the gravitational force acting on the ball.
  • The difference \(T - mg\) gives us the centripetal force needed to keep the ball moving in a circular path.
Understanding how tension varies and affects the pendulum's motion is crucial. Remember, tension isn't constant but depends on the position in the pendulum's arc.
Circular Motion
In circular motion, forces responsible for maintaining the curved path are crucial to understanding how objects move. For a pendulum at its lowest point, the acceleration is directed towards the center of its circular path, which is the pivot point.

*Accelerating in a Circle*
For an object in circular motion, an inward force, known as centripetal force, ensures that the object continues to move along the circular path rather than a straight line.

  • This force is calculated as \( F = \frac{m v^2}{r} \), where \(m\) is mass, \(v\) is velocity, and \(r\) is the radius of the circular path.
  • In the pendulum example, the tension minus the weight of the ball gives us this force.
Thus, solving these equations helps us find the speed of the ball at any point in its swing. This interplay of forces is what allows the pendulum to maintain its motion without simply dropping or flying off along a tangent.
Newton's Second Law
Newton's Second Law is fundamental in understanding the dynamics of motion in a pendulum. It tells us how the velocity of an object changes when it is subjected to external forces.

The law is expressed as \( F = ma \), where:
  • \(F\) is the net force acting on the object,
  • \(m\) is its mass, and
  • \(a\) is the acceleration.
*Applying the Law*
For the pendulum, when at its lowest point, the net force is the difference between the tension in the rope and the gravitational pull. This net force leads to the centripetal acceleration necessary for circular motion.

In the scenario where the tension is just equal to the weight (\(T = mg\)), there isn't any net force to change the motion of the pendulum. This results in a velocity of zero at this particular point, as derived from the equation \(0 = m v^2/r\), showcasing how pivotal Newton's Second Law is in predicting motion outcomes.

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