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(a) A high-energy beam of alpha particles collides with a stationary helium gas target. What must the total energy of a beam particle be if the available energy in the collision is \(16.0 \mathrm{GeV} ?\) (b) If the alpha particles instead interact in a colliding-beam experiment, what must the energy of each beam be to produce the same available energy?

Short Answer

Expert verified
Part (a): The total energy of the beam particle is \(16.0 \mathrm{GeV}\). Part (b): The energy of each beam in a colliding-beam experiment should be \(8.0 \mathrm{GeV}\).

Step by step solution

01

Information and Plan

In this exercise, alpha particles are considered. An alpha particle is the same as a helium-4 nucleus, which consists of 2 protons and 2 neutrons. Firstly, we'll calculate the total energy of the beam particle in a stationary target scenario. In the second part, we'll determine the energy of each beam in the colliding-beam scenario for the same available energy.
02

Calculate total energy for the stationary target

We need to calculate the total energy of a beam particle when the available energy in the collision is \(16.0 \mathrm{GeV}\). Here, the total energy is equal to the available energy as all the energy is transferred into the collision. So, the total energy of the beam particle is \(16.0 \mathrm{GeV}\).
03

Calculate energy for each beam in the colliding-beam scenario

In a colliding-beam experiment, the total available energy is the sum of the kinetic energies of the two particles. If both beams contain alpha particles of identical energy \(E\), the available energy \(16.0 \mathrm{GeV}\) will be \(2E\). So, to find the energy of each beam, we divide the total available energy by 2. Thus, each beam should have an energy of \(8.0 \mathrm{GeV}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alpha Particles
Understanding alpha particles is crucial for comprehending various nuclear processes, including those involved in collision experiments. An alpha particle is essentially a helium-4 nucleus, comprised of two protons and two neutrons bound together. This structure explains much of their behavior during collisions.

Being relatively heavy compared to other subatomic particles like electrons, alpha particles tend to have substantial kinetic energy even at lower speeds. However, when we talk about high-energy collisions in physics, we're often discussing particles that are moving at speeds close to the speed of light, imbuing them with even greater energy.

Alpha particles are frequently used in experimental physics because they are stable, can be easily produced and detected, and because their charge and mass are well-known, allowing precise calculations in experiments like the ones described in the given exercise.
Total Energy in Collisions
Total energy in collisions is a term that refers to the sum of all energy types present during a collision event. In physics, especially when considering particle collisions, this typically includes kinetic energy, potential energy, and rest mass energy.

It's important to note that according to the theory of relativity, mass itself is a form of energy. The famous equation, \( E = mc^2 \), expresses the energy-mass equivalence, where \( m \) is the rest mass and \( c \) is the speed of light. Therefore, even particles at rest have energy - their rest mass energy. This becomes particularly significant in high-energy collisions, where the total energy is often much greater than the rest mass energy of the particles involved.

In the context of a high-energy beam of alpha particles colliding with a stationary target, as in the example, the 'total energy' refers to the energy the beam particle must have to create a specified amount of available energy for the reaction (in this case, 16.0 GeV).
Colliding-beam Experiment
A colliding-beam experiment is an advanced scientific technique used in particle physics to study subatomic particles. Unlike fixed-target experiments, where a moving particle hits a stationary target, in colliding-beam experiments, two beams of particles are accelerated to high speeds and then made to collide with each other.

This approach has a major advantage: when two particles collide head-on, their kinetic energies add up, making a much higher amount of energy available to create new particles than in a fixed-target experiment. This is because in the latter, the stationary target's mass results in a lot of the projectile's energy going into recoil rather than into the collision itself.

To achieve the same available energy in a colliding-beam experiment as in a fixed-target experiment, the energies of the individual beams are halved, since the two colliding particles contribute equally to the total energy. For instance, to reach an available energy of 16.0 GeV, as mentioned in the exercise, each beam of alpha particles would only need to be 8.0 GeV, combining to give the required total energy when they collide.

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Most popular questions from this chapter

The strong nuclear force can be crudely modeled as a Hooke's-law spring force, increasing linearly with the quark scparation distance. The energy stored in this "spring" corresponds to the energy content of the gluon field. In this picture, as quarks are further separated, increasing energy is stored between them. At a critical separation distance, the energy converts to matter, and a new quark-antiquark pair is generated, guaranteeing that there can never be a free quark. (a) A proton has a diameter of about \(1.5 \mathrm{fm}\). Fstimate the repulsive Coulomb force between two up quarks separated by \(0.5 \mathrm{fm}\). (b) Model the strong force as \(F_{\mathrm{s}}=k s,\) where \(s\) is the distance between two quarks. If this force balances the electrostatic repulsion between two up quarks when \(s=0.5 \mathrm{fm},\) what is the effective spring constant \(k,\) in \(\mathrm{SI}\) units? (c) Convert \(k\) into units of \(\mathrm{MeV} / \mathrm{fm}^{2}\). (d) How much energy is stored in the gluon field when \(s=0.5 \mathrm{fm} ?\) The mass of an up quark is thought to be about \(2.3 \mathrm{MeV} / \mathrm{c}^{2}\). (e) How much energy is needed to produce an up quark and an antiup quark? (f) How far would two up quarks need to be separated so that the gluon energy \(\frac{1}{2} k s^{2}\) matches the rest energy of an up-antiup quark pair?

Consider the following hypothetical universe: The Nibiruvians and the Xibalbans are minuscule "flat" societies located at an angular separation of \(\theta=60^{\circ}\) on the surface of a two-dimensional spherical universe with radius \(R\), as shown in Fig. \(P 44.55\). (a) What is the distance \(D\) between the two societies in terms of \(R\) and \(\theta ?\) (b) If \(R\) is increas- ing in time, what is the speed \(V=d D / d t\) at which the civilizations are separating. as a function of \(R, d R / d t,\) and \(D ?\) (c) The separation velocity and the distance \(D\) are related by \(\underline{V}=B D\). Determine the "Bubble parameter" \(B\) in terms of \(R(t) .\) Note that \(B\) is not constant. (Similarly, the Hubble "constant" \(H_{0}\) is presumed to be changing with time.) (d) The radius of this universe was \(R_{0}=500.0 \mathrm{~m}\) upon its creation at time \(t=0,\) and it has been increasing at a constant rate of \(1.00 \mu \mathrm{m} / \mathrm{s}\). What was the Bubble parameter exactly four years after creation? (e) What is the distance between Nibiru and Xibalba four years after creation? (f) At what speed are they separating at that time? (g) At that time, the Nibiruvians transmit isotropic ripple waves with their "light speed" of \(c=6.35 \mu \mathrm{m} / \mathrm{s}\) and wavelength \(1.00 \mathrm{nm}\). How long does it take these waves to reach Xibalba? (Hint: In time \(d t\) the waves travel an angular distance \(d \theta=c d t / R(t) .\) Integrate to obtain an expression for the total angular distance traveled as a function of time. Solve for the time needed to travel a given angular distance.) (h) At what wavelength will the Xibalbans observe these waves? (Hint: Use Eq. \((44.16) .)\)

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