/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 The table gives the occupation p... [FREE SOLUTION] | 91Ó°ÊÓ

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The table gives the occupation probabilities \(f(E)\) as a function of the energy \(E\) for a solid conductor at a fixed temperature \(T\). $$ \begin{array}{l|cccccc} f(\boldsymbol{E}) & 0.064 & 0.173 & 0.390 & 0.661 & 0.856 & 0.950 \\ \hline \boldsymbol{E}(\mathrm{eV}) & 3.0 & 2.5 & 2.0 & 1.5 & 1.0 & 0.5 \end{array} $$ To determine the Fermi energy of the solid material, you are asked to analyze this information in terms of the Fermi-Dirac distribution. (a) Graph the values in the table as \(E\) versus \(\ln \\{[1 / f(E)]-1\\} .\) Find the slope and \(y\) -intercept of the best-fit straight line for the data points when they are plotted this way. (b) Use your results of part (a) to calculate the temperature \(T\) and the Fermi energy of the material.

Short Answer

Expert verified
The temperature and Fermi energy calculations are based on the straight line fitted on the transformed data. The slope obtained after fitting the line on the data plotted in the diagram is used to calculate the temperature using \(T = -\frac{1}{mk}\) equation, while the y-intercept is used to calculate the Fermi energy, given by \(E_F = -ckT\).

Step by step solution

01

Plotting the Transformed Data

First, start with transforming the given data in the table. For each occupation probability \(f(E)\), compute \(\ln \{[1 / f(E)]-1\}\). These newly computed values are to be plotted against their corresponding energy values \(E\) in a graph.
02

Calculating Slope and Y-intercept

Fit a straight line to the plotted points using statistical analysis and calculate the slope and y-intercept of this line. The slope and y-intercept are generally obtained from the straight-line equation given as \(y = mx + c\), where \(m\) is the slope and \(c\) is the intercept.
03

Computing Temperature

The slope which is obtained from the graph can be used to calculate the temperature. If the slope is represented by \(m\), the temperature \(T\) can be computed using the relationship \(T = -\frac{1}{mk}\), where \(k\) is the Boltzmann constant which equals \(8.6 \times 10^{-5} eV/K\).
04

Calculation of Fermi energy

The computed y-intercept from the fitted line can be used to calculate the Fermi energy of the material. If the intercept is denoted by \(c\), where \(c = -\frac{E_F}{kT}\), then Fermi energy \(E_F\) can be given by \(E_F = -ckT\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fermi-Dirac distribution
The Fermi-Dirac distribution is used to describe the statistical distribution of particles over energy states in systems comprising fermions, like electrons in a solid. This distribution is crucial for understanding how electrons are settled in different energy levels at a given temperature. It is represented by the equation:
  • \( f(E) = \frac{1}{e^{(E-E_F)/(kT)} + 1} \)
Here, \( E \) is the energy level of interest, \( E_F \) is the Fermi energy, \( k \) is the Boltzmann constant, and \( T \) is the temperature in Kelvin.
This equation tells us the probability \( f(E) \) that a state with energy \( E \) is occupied by an electron. At absolute zero temperature, all states below \( E_F \) are fully occupied. As temperature increases, electrons can occupy higher energy levels due to increased thermal energy.
Occupation probabilities
Occupation probabilities are the chances that specific energy levels are filled with electrons. These probabilities are governed by the Fermi-Dirac distribution. In a simplified context, they manifest as values between 0 and 1, where 0 represents an unoccupied state and 1 signifies a fully occupied state.
In applications, such as the one presented in the exercise, you might find a table listing probabilities \(f(E)\) at different energies \(E\). This helps in analyzing material properties like electrical conductivity and heat capacity.
  • When \(f(E)\) is close to 1, the energy level is mostly filled.
  • When \(f(E)\) is close to 0, the level is scarcely occupied.
Slope and intercept calculation
To unveil important properties such as temperature and Fermi energy, the occupation probabilities from the exercise can be plotted in a specific format against energy levels. This requires plotting \( E \) versus \( \ln \{[1 / f(E)]-1\} \).
The resulting graph provides a linear relationship described by \( y = mx + c \), where:
  • \( m \) represents the slope of the line.
  • \( c \) represents the y-intercept.
The slope \( m \) directly relates to the temperature, while the intercept \( c \) assists in calculating the Fermi energy \( E_F \). The simplicity of fitting a straight line to the transformed data makes this approach both intuitive and powerful in extracting these parameters from experimental or tabulated data.
Temperature determination
Once the slope \( m \) from your plotted data is obtained, we can deduce the temperature of the solid conductor. The relationship used for this calculation is:
  • \( T = -\frac{1}{mk} \)
Here, \( k \) is the Boltzmann constant (\(8.6 \times 10^{-5} \text{eV/K}\)).
This formula bridges the gap between the abstract data you have graphed and tangible thermal properties of the material being studied. A negative slope signifies that, as the energy increases, the probability falls, indicating how temperature influences the distribution. The smaller the magnitude of the slope, the higher the temperature, reflecting how energy levels become more closely packed as temperature increases.

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Most popular questions from this chapter

Two atoms of cesium (Cs) can form a Cs \(_{2}\) molecule. The equilibrium distance between the nuclei in a \(\mathrm{Cs}_{2}\) molecule is \(0.447 \mathrm{nm}\). Calculate the moment of inertia about an axis through the center of mass of the two nuclei and perpendicular to the line joining them. The mass of a cesium atom is \(2.21 \times 10^{-25} \mathrm{~kg}\).

When an OH molecule undergoes a transition from the \(n=0\) to the \(n=1\) vibrational level, its internal vibrational energy increases by \(0.463 \mathrm{eV}\). Calculate the frequency of vibration and the force constant for the interatomic force. (The mass of an oxygen atom is \(2.66 \times 10^{-26} \mathrm{~kg},\) and the mass of a hydrogen atom is \(1.67 \times 10^{-27} \mathrm{~kg} .\)

(a) A forward-bias voltage of \(15.0 \mathrm{mV}\) produces a positive current of 9.25 mA through a \(p-n\) junction at \(300 \mathrm{~K}\). What does the positive current become if the forward-bias voltage is reduced to \(10.0 \mathrm{mV} ?\) (b) For reverse-bias voltages of \(-15.0 \mathrm{mV}\) and \(-10.0 \mathrm{mV},\) what is the reverse-bias negative current?

Consider the \(\mathrm{CO}_{2}\) molecule shown in Fig. \(42.10 \mathrm{c} .\) The oxygen molecules have mass \(M_{\mathrm{O}}\) and the carbon atom has mass \(M_{\mathrm{C}}\). Parameterize the positions of the left oxygen atom, the carbon atom, and the right oxygen atom using \(x_{1}, x_{2},\) and \(x_{3}\) as the respective rightward deviations from equilibrium. Treat the bonds as Hooke's-law springs with common spring constant \(k^{\prime}\). (a) Use Newton's second law to obtain expressions for \(M_{i} \ddot{x}_{i}=M_{i} d^{2} x / d t^{2}\) in each case \(i=1,2,3,\) where \(M_{1,2,3}=\left(M_{\mathrm{O}}, M_{\mathrm{C}}, M_{\mathrm{O}}\right) .\) (Note: We represent time derivatives using dots.) Assume \(X_{\mathrm{C}}=0\) at \(t=0 .\) (b) To ascertain the motion of the asymmetric stretching mode, set \(x_{1}=x_{3} \equiv X_{0}\) and set \(x_{2} \equiv X_{\mathrm{C}}\). Write the two independent equations that remain from your previous result. (c) Eliminate the sum \(X_{\mathrm{O}}+X_{\mathrm{C}}\) from your equations. Use what remains to ascertain \(X_{\mathrm{C}}\) in terms of \(X_{\mathrm{O}}\). (d) Substitute your expression for \(X_{\mathrm{C}}\) into your equation for \(X_{\mathrm{O}}\) to derive a harmonic oscillator equation \(M_{\mathrm{eff}} \ddot{X}_{\mathrm{O}}=-k \dot{X}_{\mathrm{O}} .\) What is \(M_{\mathrm{eff}} ?\) (e) This equation has the solution \(X_{\mathrm{O}}(t)=A \cos (\omega t) .\) What is the angular frequency \(\omega ?\) (f) Using the experimentally determined spring constant \(k^{\prime}=1860 \mathrm{~N} / \mathrm{m}\) and the atomic masses \(M_{\mathrm{C}}=12 \mathrm{u}\) and \(M_{\mathrm{O}}=16 \mathrm{u},\) where \(\mathrm{u}=1.6605 \times 10^{-27} \mathrm{~kg},\) to determine the oscillation frequency \(f=\omega / 2 \pi\)

(a) Suppose a piece of very pure germanium is to be used as a light detector by observing, through the absorption of photons, the increase in conductivity resulting from generation of electron-hole pairs. If each pair requires \(0.67 \mathrm{eV}\) of energy, what is the maximum wavelength that can be detected? In what portion of the spectrum does it lie? (b) What are the answers to part (a) if the material is silicon, with an energy requirement of \(1.12 \mathrm{eV}\) per pair, corresponding to the gap between valence and conduction bands in that element?

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