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Compute the Fermi energy of potassium by making the simple approximation that each atom contributes one free electron. The density of potassium is \(851 \mathrm{~kg} / \mathrm{m}^{3},\) and the mass of a single potassium atom is \(6.49 \times 10^{-26} \mathrm{~kg}\)

Short Answer

Expert verified
The computation for Fermi energy involves first calculating the number density using given data, and then substituting this value with constants into Fermi Energy formula. Solve the resulting equation to obtain the Fermi Energy.

Step by step solution

01

Calculate the Number Density

First, calculate the number density \(n\), which is defined as the number of free electrons per unit volume. The formula to compute the number density is : \(n = \frac{\text{Density}}{\text{Atomic mass}}\times \text{Avogadro’s number}\). Using the given values, \(n = \frac{851}{6.49 \times 10^{-26}}\times 6.022 \times 10^{23}\).
02

Substitute in the Fermi Energy formula

Next, substitute this value of \(n\) in the formula for Fermi Energy. The Fermi Energy(\(E_F\)) formula is: \(E_F = \frac{\hbar^2(3\pi^2n)^{2/3}}{2m}\), where \(\hbar\) is Planck’s constant divided by \(2\pi\), \(n\) is number density calculated in step 1 and \(m\) is the electron mass. We know that \(\hbar = \frac{h}{2\pi} = \frac{6.626 \times 10^{-34}}{2\pi} \, Js\) and \(m = 9.11 \times 10^{-31} \, kg\). Substitute these constants, and the value of \(n\) calculated in step 1 into the fermi energy formula to compute the energy.
03

Solve for Fermi energy

Compute \(E_F\) by performing the calculation provided in the previous step.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Number Density
Number density is a measure of the number of free electrons present per unit volume in a material. In the context of potassium, each potassium atom contributes one free electron. The number density formula is vital to understand when calculating Fermi energy, as it gives us the concentration of electrons, which is used in the formula for Fermi energy.
To calculate the number density (), we use the formula:
  • \( n = \frac{\text{Density}}{\text{Atomic mass}} \times \text{Avogadro’s number} \).
Here, the density of potassium is 851 \( \mathrm{kg} / \mathrm{m}^{3} \), and the mass of a single potassium atom is \( 6.49 \times 10^{-26} \text{ kg} \). Avogadro's number is approximately \( 6.022 \times 10^{23} \), which is the number of atoms or molecules in one mole of a substance. This calculation provides a base for further calculations in quantum mechanics and solid-state physics.
Understanding how number density relates to electron movements gives insight into electrical conductivity and behavior of materials.
Fermi Energy Formula
The Fermi energy is a fundamental concept in physics, particularly in the realm of quantum mechanics and solid-state physics. It is the highest energy level that electrons can occupy at absolute zero temperature. The formula for Fermi energy is crucial for determining this energy level.
The Fermi Energy (E_F) formula is:
  • \( E_F = \frac{\hbar^2(3\pi^2n)^{2/3}}{2m} \),
where \(\hbar\) is Planck's constant divided by \(2\pi\), \(n\) is the number density, and \(m\) is the electron mass. Planck’s constant \(\hbar\) is approximately \(6.626 \times 10^{-34} \text{ Js} / 2\pi\) and the mass of an electron \(m\) is \(9.11 \times 10^{-31} \text{ kg}\).
This formula helps us understand the electron distribution in metal and semiconductor materials. It's particularly important in explaining properties such as electrical and thermal conductivity.
Potassium Atom
A potassium atom is an essential element in many scientific calculations, particularly in the computation of Fermi energy. Potassium is a soft, silver-white metal that belongs to the alkali group on the periodic table. It has a high reactivity and a relatively simple electronic structure, which makes it a fascinating subject of study in physics.
In this particular problem, the potassium atom is considered under the assumption that each atom contributes one free electron. This assumption simplifies the electronic interactions, allowing us to apply the free electron model efficiently. The calculated mass of a potassium atom is \(6.49 \times 10^{-26} \text{ kg}\), and the density is given as \(851 \mathrm{~kg} / \mathrm{m}^{3}\).
By understanding these properties of potassium, we can effectively incorporate them into broader scientific calculations and models, allowing us to predict the behavior of this substance under various conditions.
Free Electron Model
The free electron model is a simple yet powerful concept used to describe the behavior of electrons in a metal. It assumes that electrons move freely within the structure of the metal without being bound to any particular atom. This model is a fundamental approximation that helps explain various physical properties of metals.
In this model, the electrons are treated like a gas of particles that obey the laws of quantum mechanics. The free electron model aids in calculating the Fermi energy by simplifying the interactions within the metal. It applies particularly well to alkali metals like potassium, where each atom can be assumed to donate one free electron to the electron "sea." This is why we approximate that each potassium atom contributes one free electron in our calculations.
By using the free electron model, we gain insights into metallic properties such as electrical conductivity, and we can more easily calculate electron distribution characteristics such as the Fermi energy.

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Most popular questions from this chapter

To determine the equilibrium separation of the atoms in the HCl molecule, you measure the rotational spectrum of \(\mathrm{HCl}\). You find that the spectrum contains these wavelengths (among others): \(60.4 \mu \mathrm{m}, 69.0 \mu \mathrm{m}, 80.4 \mu \mathrm{m}, 96.4 \mu \mathrm{m},\) and \(120.4 \mu \mathrm{m} .\) (a) Use your measured wavelengths to find the moment of inertia of the HCl molecule about an axis through the center of mass and perpendicular to the line joining the two nuclei. (b) The value of \(l\) changes by ±1 in rotational transitions. What value of \(l\) for the upper level of the transition gives rise to each of these wavelengths? (c) Use your result of part (a) to calculate the equilibrium separation of the atoms in the HCl molecule. The mass of a chlorine atom is \(5.81 \times 10^{-26} \mathrm{~kg},\) and the mass of a hydrogen atom is \(1.67 \times 10^{-27} \mathrm{~kg} .\) (d) What is the longest-wavelength line in the rotational spectrum of \(\mathrm{HCl} ?\)

When a hypothetical diatomic molecule having atoms \(0.8860 \mathrm{nm}\) apart undergoes a rotational transition from the \(l=2\) state to the next lower state, it gives up a photon having energy \(8.841 \times 10^{-4} \mathrm{eV} .\) When the molecule undergoes a vibrational transition from one energy state to the next lower energy state, it gives up \(0.2560 \mathrm{eV} .\) Find the force constant of this molecule.

The gap between valence and conduction bands in silicon is \(1.12 \mathrm{eV} .\) A nickel nucleus in an excited state emits a gamma-ray photon with wavelength \(9.31 \times 10^{-4} \mathrm{nm}\). How many electrons can be excited from the top of the valence band to the bottom of the conduction band by the absorption of this gamma ray?

Germanium has a band gap of \(0.67 \mathrm{eV}\). Doping with arsenic adds donor levels in the gap \(0.01 \mathrm{eV}\) below the bottom of the conduction band. At a temperature of \(300 \mathrm{~K},\) the probability is \(4.4 \times 10^{-4}\) that an electron state is occupied at the bottom of the conduction band. Where is the Fermi level relative to the conduction band in this case?

(a) Suppose a piece of very pure germanium is to be used as a light detector by observing, through the absorption of photons, the increase in conductivity resulting from generation of electron-hole pairs. If each pair requires \(0.67 \mathrm{eV}\) of energy, what is the maximum wavelength that can be detected? In what portion of the spectrum does it lie? (b) What are the answers to part (a) if the material is silicon, with an energy requirement of \(1.12 \mathrm{eV}\) per pair, corresponding to the gap between valence and conduction bands in that element?

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