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If a sodium chloride \((\mathrm{NaCl})\) molecule could undergo an \(n \rightarrow n-1\) vibrational transition with no change in rotational quantum number, a photon with wavelength \(20.0 \mu \mathrm{m}\) would be emitted. The mass of a sodium atom is \(3.82 \times 10^{-26} \mathrm{~kg},\) and the mass of a chlorine atom is \(5.81 \times 10^{-26} \mathrm{~kg}\). Calculate the force constant \(k^{\prime}\) for the interatomic force in \(\mathrm{NaCl}\).

Short Answer

Expert verified
To find the force constant, start by determining the frequency of the light. Then, calculate the energy difference using the Planck relation. After that, find the reduced mass of the sodium and chlorine atoms. Finally, use these values to calculate the force constant through the given relation.

Step by step solution

01

Determine the Frequency of the Light

We start by determining the frequency of the light that is emitted during the transition. Frequency (\( \nu \)) can be calculated from wavelength (\( \lambda \)) using the speed of light (\( c \)) equation: \[ \nu = \frac{c}{\lambda} \]Given that: \( \lambda = 20.0 \mu m = 20.0 \times 10^{-6} m \) and \( c = 3.0 \times 10^8 m/s \), we substitute these values to determine the frequency.
02

Compute the Energy Difference

Having determined the frequency, the next step is to calculate the energy involved in the transition. We can use Planck’s relation which connects the energy (\( E \)) of a photon with its frequency:\[ E = h \nu \]where \( h \) is Planck’s constant, \( h = 6.626 \times 10^{-34} J \cdot s \). Substitute the calculated frequency (\( \nu \)) into the equation to calculate the energy.
03

Calculate the Reduced Mass

The reduced mass (\( \mu \)) of the two-atom system can be calculated using the formula:\[ \mu = \frac{m_{\mathrm{Na}} \times m_{\mathrm{Cl}}}{m_{\mathrm{Na}} + m_{\mathrm{Cl}}} \]where \( m_{Na} = 3.82 \times 10^{-26} kg \) is the mass of sodium and \( m_{Cl} = 5.81 \times 10^{-26} kg \) is the mass of chlorine. Substituting the respective masses into the equation will give the value of the reduced mass.
04

Compute the Force Constant

The force constant (\( k' \)) provides a measure of the stiffness of a bond and can be calculated using the energy \( E \), reduced mass \( \mu \), and known constants from the following relation:\[ E = \frac{1}{2} k' \mu \]Solving for \( k' \), we get:\[ k' = \frac{2E}{\mu} \]Insert the calculated energy and reduced mass into the equation, to find the force constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vibrational Transition
In molecular physics, vibrational transition refers to the change in a molecule's vibrational energy level. When a molecule like sodium chloride (\( \mathrm{NaCl} \)) undergoes a transition from one vibrational level \( n \) to another \( n-1 \), it emits or absorbs energy in the form of photons. These transitions are quantized, meaning they occur at specific energy levels, making them useful in molecular spectroscopy.
During a vibrational transition, the molecule's nucleus changes its position about its equilibrium, rather like a mass on a spring. This results in an energy exchange, which is most often observed as an emission of a photon. The wavelength of the emitted photon can tell us a lot about the energy levels of the molecule and the properties of the bond like its strength and force constant. In our exercise, calculating this transition provides insight into the interatomic force constant \( k^{\prime} \).
Reduced Mass Calculation
Reduced mass is a concept used to simplify the mathematics of two-body systems, such as diatomic molecules like \( \mathrm{NaCl} \). It accounts for the distribution of mass between the two atoms and is crucial when analyzing vibrational motions. The reduced mass \( \mu \) is calculated using the formula:
\[\mu = \frac{m_{\text{Na}} \times m_{\text{Cl}}}{m_{\text{Na}} + m_{\text{Cl}}}\]Here, \( m_{\text{Na}} \) and \( m_{\text{Cl}} \) are the masses of sodium and chlorine atoms, respectively.
Calculating the reduced mass allows for a better understanding of how two masses interact in a molecular bond. It modifies equations, so they resemble that of a single particle, simplifying further calculations such as those for the force constant. This essentially reduces the complexity of a two-body problem to something more manageable.
Photonic Emission
Photonic emission is a process where a photon is released by a molecule during a transition between energy levels. This process is central to the exercise as it reflects the change in vibrational energy levels we see when sodium chloride emits a photon in moving from \( n \) to \( n-1 \).
This emission occurs because energy must be conserved during transitions, and the excess energy, released as a photon, carries away this difference in energy. The properties of this emitted photon, such as its wavelength and frequency, can be measured, providing insight into the energy levels of the molecule.
  • Wavelength impact: Longer wavelength photons have less energy compared to shorter wavelengths.
  • Frequency determination: Related inversely to wavelength, providing energy quantification via\( E = hu \).
The wavelength provided (\(20.0 \mu \mathrm{m}\)) ties directly to the energy of the transition and offers a clue into the force constant at the atomic level.
Energy Calculation in Transitions
Determining the energy involved in vibrational transitions is essential to understanding molecular dynamics. This energy can be calculated using Planck's relation, which connects photon energy \( E \) with frequency \( u \):
\[ E = h u \]where \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \text{ J} \cdot \text{s} \)). To find the frequency, you use the relation \( u = \frac{c}{\lambda} \), where \( c \) is the speed of light.
In vibrational spectroscopy, using this energy relation helps researchers adjust their understanding of molecular behavior during transitions. Calculating \( E \) is not just about knowing the photon's energy; it is also a stepping stone for calculating the interatomic force constant \( k^{\prime} \).
  • This makes it possible to infer the bond stiffness and predict potential molecular responses to external forces.
  • The calculation of \( k^{\prime} \) using \( E \) and the reduced mass \( \mu \):\[ k^{\prime} = \frac{2E}{\mu} \]helps us better understand the bond's characteristics and strength.
This calculation serves as an essential tool for chemists and physicists in probing fundamental molecular properties.

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Most popular questions from this chapter

To determine the equilibrium separation of the atoms in the HCl molecule, you measure the rotational spectrum of \(\mathrm{HCl}\). You find that the spectrum contains these wavelengths (among others): \(60.4 \mu \mathrm{m}, 69.0 \mu \mathrm{m}, 80.4 \mu \mathrm{m}, 96.4 \mu \mathrm{m},\) and \(120.4 \mu \mathrm{m} .\) (a) Use your measured wavelengths to find the moment of inertia of the HCl molecule about an axis through the center of mass and perpendicular to the line joining the two nuclei. (b) The value of \(l\) changes by ±1 in rotational transitions. What value of \(l\) for the upper level of the transition gives rise to each of these wavelengths? (c) Use your result of part (a) to calculate the equilibrium separation of the atoms in the HCl molecule. The mass of a chlorine atom is \(5.81 \times 10^{-26} \mathrm{~kg},\) and the mass of a hydrogen atom is \(1.67 \times 10^{-27} \mathrm{~kg} .\) (d) What is the longest-wavelength line in the rotational spectrum of \(\mathrm{HCl} ?\)

A \(p-n\) junction includes \(p\) -type silicon, with donor atom density \(N_{\mathrm{D}},\) adjacent to \(n\) -type silicon, with acceptor atom density \(N_{\mathrm{A}}\). Near the junction, free electrons from the \(n\) side have diffused into the \(p\) side while free holes from the \(p\) side have diffused into the \(n\) side, leaving a "depletion region" of width \(W\) where there are no free charge carriers (Fig. \(\mathbf{P} \mathbf{4 2 . 5 0}\) ). The width of the depletion region on the \(n\) side is \(a_{n}\), and the width of the depletion region on the \(p\) side is \(a_{p} .\) Each depleted region has a constant charge density with magnitude equal to the corresponding donor atom density. Assume there is no net charge outside the depleted regions. Define an \(x\) -axis pointing from the \(p\) side toward the \(n\) side with the origin at the center of the junction. An electric field \(\vec{E}=-E \hat{\imath}\) has developed in the depletion region, stabilizing the diffusion. (a) Use Gauss's law to determine the electric field on the \(p\) side of the junction, for \(-a_{p} \leq x \leq 0 .\) (Hint: Use a cylindrical Gaussian surface parallel to the \(x\) -axis, with the left end outside the depletion region (where \(\overrightarrow{\boldsymbol{E}}=0\) ) and the right side inside the region.) Note that the dielectric constant of silicon is \(K=11.7\). (b) Determine the electric field on the \(n\) side of the junction, for \(0 \leq x \leq a_{n}\) (c) Use continuity at \(x=0\) to determine a relationship between the depths \(a_{p}\) and \(a_{n}\) and in terms of \(N_{\mathrm{A}}\) and \(N_{\mathrm{D}}\). (d) The electric potential \(V(x)\) may be obtained by integrating the electric field, as shown in Eq. \((23.18) .\) Determine \(V(x)\) in the region \(-a_{p} \leq x \leq 0\) using the convention that \(V(x)=0\) for \(x<-a_{p}\). (e) Similarly, determine \(V(x)\) in the region \(0 \leq x \leq a_{n}\). (f) What is the "barrier potential" \(V_{b}=V\left(a_{n}\right)-V\left(-a_{p}\right) ?(\mathrm{~g})\) The \(p\) side is doped with boron atoms with density \(N_{\mathrm{A}}=1.00 \times 10^{16} \mathrm{~cm}^{-3} .\) The \(n\) side is doped with arsenic atoms with density \(N_{\mathrm{D}}=5.00 \times 10^{16} \mathrm{~cm}^{-3} .\) The \(n\) side depletion depth is \(a_{n}=55.0 \mathrm{nm} .\) What is the \(p\) side depletion depth \(a_{p} ?\) (h) What is the peak magnitude of the electric field, at \(x=0 ?\) (i) What is the value of the barrier potential \(V_{\mathrm{b}}\) ?

At a temperature of \(290 \mathrm{~K},\) a certain \(p-n\) junction has a saturation current \(I_{\mathrm{S}}=0.500 \mathrm{~mA}\). (a) Find the current at this temperature when the voltage is (i) \(1.00 \mathrm{mV}\), (ii) \(-1.00 \mathrm{mV}\), (iii) \(100 \mathrm{mV}\), and (iv) \(-100 \mathrm{mV}\). (b) Is there a region of applied voltage where the diode obeys Ohm's law?

The one-dimensional calculation of Example 42.4 (Section 42.3 ) can be extended to three dimensions. For the threedimensional fce \(\mathrm{NaCl}\) lattice, the result for the potential energy of a pair of \(\mathrm{Na}^{+}\) and \(\mathrm{Cl}^{-}\) ions due to the electrostatic interaction with all of the ions in the crystal is \(U=-\alpha e^{2} / 4 \pi \epsilon_{0} r,\) where \(\alpha=1.75\) is the Madelung constant. Another contribution to the potential energy is a repulsive interaction at small ionic separation \(r\) due to overlap of the electron clouds. This contribution can be represented by \(A / r^{8},\) where \(A\) is a positive constant, so the expression for the total potential energy is $$ U_{\mathrm{tot}}=-\frac{\alpha e^{2}}{4 \pi \epsilon_{0} r}+\frac{A}{r^{8}} $$ (a) Let \(r_{0}\) be the value of the ionic separation \(r\) for which \(U_{\text {tot }}\) is a minimum. Use this definition to find an equation that relates \(r_{0}\) and \(A,\) and use this to write \(U_{\text {tot }}\) in terms of \(r_{0}\). For \(\mathrm{NaCl}, r_{0}=0.281 \mathrm{nm}\). Obtain a numerical value (in electron volts) of \(U_{\text {tot }}\) for \(\mathrm{NaCl}\). (b) The quantity \(-U_{\text {tot }}\) is the energy required to remove an \(\mathrm{Na}^{+}\) ion and a \(\mathrm{Cl}^{-}\) ion from the crystal. Forming a pair of neutral atoms from this pair of ions involves the release of \(5.14 \mathrm{eV}\) (the ionization energy of \(\mathrm{Na}\) ) and the expenditure of \(3.61 \mathrm{eV}\) (the electron affinity of \(\mathrm{Cl}\) ). Use the result of part (a) to calculate the energy required to remove a pair of neutral Na and \(\mathrm{Cl}\) atoms from the crystal. The experimental value for this quantity is \(6.39 \mathrm{eV} ;\) how well does your calculation agree?

The Fermi energy of sodium is \(3.23 \mathrm{eV}\). (a) Find the average energy \(E_{\mathrm{av}}\) of the electrons at absolute zero. (b) What is the speed of an electron that has energy \(E_{\mathrm{av}} ?\) (c) At what Kelvin temperature \(T\) is \(k T\) equal to \(E_{\mathrm{F}} ?\) (This is called the Fermi temperature for the metal. It is approximately the temperature at which molecules in a classical ideal gas would have the same kinetic energy as the fastest-moving electron in the metal.)

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