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Chemists use infrared absorption spectra to identify chemicals in a sample. In one sample, a chemist finds that light of wavelength \(5.8 \mu \mathrm{m}\) is absorbed when a molecule makes a transition from its ground harmonic oscillator level to its first excited level. (a) Find the energy of this transition. (b) If the molecule can be treated as a harmonic oscillator with mass \(5.6 \times 10^{-26} \mathrm{~kg},\) find the force constant.

Short Answer

Expert verified
The energy of the absorbed light is \(3.43 x 10^{-20} J\) and the force constant of the harmonic oscillator is \(1801 N/m\).

Step by step solution

01

Calculate the frequency of the absorbed light

First, convert the given wavelength from micrometers to meters: \(5.8 \mu m = 5.8 x 10^{-6} m\). Next, use the formula \(c = \lambda v\) (where c is the speed of light, \(\lambda\) is wavelength, and v is frequency) and solve for v: \(v = c / \lambda = (3.0 x 10^8 m/s) / (5.8 x 10^{-6} m) = 5.17 x 10^{13} Hz\).
02

Calculate the Energy of the absorbed light

Use the formula \(E=hv\) (where h is Planck's constant) to find the energy (E) absorbed by the molecule: \(E= (6.63 x 10^{-34} J*s) * (5.17 x 10^{13} Hz) = 3.43 x 10^{-20} J\). This energy corresponds to the energy difference between the ground and first excited state of the molecule.
03

Calculate the Force Constant

The energy states of a quantum harmonic oscillator are given by the formula \(E = (n+1/2)hfv\), where n is the quantum number (0 for the ground state, 1 for the first excited state, etc.). Set this expression equal to the calculated energy and solve for the force constant k: First, rearrange the equation to solve for frequency: \(fv = 2*(E/h) - 1\). Next, replace frequency using \(fv = sqrt(k/m)\), where m is the given mass of the molecule: \(sqrt(k/m) = 2*(E/h) - 1\). Square both sides and solve for k: \(k = m * (2*(E/h) - 1)^2 = (5.6 x 10^{-26} kg)*(2*(3.43 x 10^{-20} J/6.63 x 10^{-34} J*s) - 1)^2 = 1801 N/m\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Harmonic Oscillator in Quantum Mechanics
In quantum mechanics, the concept of a harmonic oscillator is a fundamental and simple model for understanding more complex systems. A harmonic oscillator is a system that, when displaced from its equilibrium position, experiences a restoring force proportional to the displacement, similar to a spring. Imagine you have a ball attached to a spring; if you pull it and release it, the ball oscillates back and forth. That's the physical picture of a harmonic oscillator.

Now, let's translate this image into quantum mechanics: In this realm, we can't talk about specific trajectories because of the uncertainty principle. Instead, quantum harmonic oscillators have discrete energy levels. Each level corresponds to a quantum state, which is like an allowed step on an energy ladder. You cannot find the system at energy levels between these rungs. When an oscillator, like a molecule, absorbs a quantum of light (a photon), it can jump from one quantum level to the next.
  • The ground state is the lowest energy state (think of it as the bottom rung of the ladder).
  • When a molecule absorbs light and moves to an excited state, it's as if it's hopping up to a higher rung.
These steps or transitions between energy levels are what we find in infrared absorption spectra. The energy difference between these levels gives us valuable information about the molecule.
Diving Into Quantum Energy Levels
The concept of quantum energy levels can be pictorially understood as a building with distinct floors. Electrons or other quantum entities can only exist on these floors, not between them, and the energy required to 'climb' up to each floor is quantized. In practical terms:
  • In our specific example, the molecule absorbs light and gains energy to move from the ground state to the first excited state.
  • The frequency of the light absorbed, which is linked to its energy via Planck's constant, dictates the energy of the transition (using the equation E = hv, with E representing energy and v frequency).
  • By calculating the energy associated with the transition, we can also understand the properties of the molecule in question, such as its vibrational modes.
These energy levels are essential for chemists and physicists to understand how molecules interact with light, a principle that underpins spectroscopy and allows us to uncover a molecule's structural composition and other properties simply by studying its interaction with light.
Calculating the Force Constant from Absorption Data
In relating light absorption to the mechanical properties of a molecule, the force constant (k) plays a central role. Think of the force constant as a measure of the 'stiffness' of a bond within a molecule, like the stiffness of our spring in the harmonic oscillator model: the stiffer the spring, the more force is required to compress or extend it.

To find the force constant from absorption data, we must first understand how the energy of absorbed light (determined by its frequency) can be related to the properties of the molecular oscillator. The equation E = (n+1/2)hv helps us relate the energy of light absorbed (E) to the molecular characteristics. More specifically:
  • We manipulate the equation to express the vibrational frequency in terms of the mass of the molecule and the force constant.
  • Through some algebraic rearrangement, we can extract the force constant from the observed transition's energy.
By doing so, we gain insight into the rigidity of molecular bonds, which is critical in understanding chemical reactions, material properties, and even designing new materials and drugs. This kind of analysis bridges the gap between quantum mechanics and real-world applications.

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Most popular questions from this chapter

In your research on new solid-state devices, you are studying a solid-state structure that can be modeled accurately as an electron in a one-dimensional infinite potential well (box) of width \(L\). In one of your experiments, electromagnetic radiation is absorbed in transitions in which the initial state is the \(n=1\) ground state. You measure that light of frequency \(f=9.0 \times 10^{14} \mathrm{~Hz}\) is absorbed and that the next higher absorbed frequency is \(16.9 \times 10^{14} \mathrm{~Hz}\). (a) What is quantum number \(n\) for the final state in each of the transitions that leads to the absorption of photons of these frequencies? (b) What is the width \(L\) of the potential well? (c) What is the longest wavelength in air of light that can be absorbed by an electron if it is initially in the \(n=1\) state?

A particle is confined to move on a circle with radius but is otherwise free. We can parameterize points on this circle by using the distance \(x\) from a reference point or by using the angle \(\theta=x / R .\) since \(x=0\) and \(x=2 \pi R\) describe the same point, the wave function must satisfy \(\psi(x)=\psi(x+2 \pi R)\) and \(\psi^{\prime}(x)=\psi^{\prime}(x+2 \pi R)\) (a) Solve the free-particle time-independent Schrödinger equation subject to these boundary conditions. You should find solutions \(\psi_{n}^{\pm}\), where \(n\) is a positive integer and where lower \(n\) corresponds to lower energy. Express your solutions in terms of \(\theta\) using unspecified normalization constants \(A_{n}^{+}\) and \(A_{n}^{-}\) corresponding, respectively, to modes that move "counterclockwise" toward higher \(x\) and "clockwise" toward lower \(x\). (b) Normalize these functions to determine \(A_{n}^{\pm}\). (c) What are the energy levels \(E_{n} ?\) (d) Write the time-dependent wave functions \(\Psi_{n}^{\pm}(x, t)\) corresponding to \(\Psi_{n}^{\pm}(x) .\) Use the symbol \(\omega\) for \(E_{1} / \hbar .\) (e) Consider the nonstationary state defined at \(t=0\) by \(\Psi(x, 0)=\frac{1}{\sqrt{2}}\left[\Psi_{1}^{+}(x)+\Psi_{2}^{+}(x)\right] .\) Determine the probability density \(|\Psi(x, t)|^{2}\) in terms of \(R, \omega,\) and \(t .\) Simplify your result using the identity \(1+\cos \alpha=2 \cos ^{2}(\alpha / 2) .\) (f) With what angular speed does the density peak move around the circle? (g) If the particle is an electron and the radius is the Bohr radius, then with what speed does its probability peak move?

Ground-Level Billiards. (a) Find the lowest energy level for a particle in a box if the particle is a billiard ball \((m=0.20 \mathrm{~kg})\) and the box has a width of \(1.3 \mathrm{~m}\), the size of a billiard table. (Assume that the billiard ball slides without friction rather than rolls; that is, ignore the to what speed does this correspond? How much time would it take at this speed for the ball to move from one side of the table to the other? (c) What is the difference in energy between the \(n=2\) and \(n=1\) levels? (d) Are quantum- mechanical effects important for the game of billiards?

(a) Show by direct substitution in the Schrödinger equation for the one- dimensional harmonic oscillator that the wave function \(\psi_{1}(x)=A_{1} x e^{-\alpha^{2} x^{2} / 2},\) where \(\alpha^{2}=m \omega / \hbar,\) is a solution with energy corresponding to \(n=1\) in Eq. \((40.46) .\) (b) Find the normalization constant \(A_{1}\). (c) Show that the probability density has a minimum at \(x=0\) and maxima at \(x=\pm 1 / \alpha,\) corresponding to the classical turning points for the ground state \(n=0\).

A particle is described by a wave function \(\psi(x)=A e^{-\alpha x^{2}}\) where \(A\) and \(\alpha\) are real, positive constants. If the value of \(\alpha\) is increased, what effect does this have on (a) the particle's uncertainty in position and (b) the particle's uncertainty in momentum? Explain your answers.

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