/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A box rests on a frozen pond, wh... [FREE SOLUTION] | 91Ó°ÊÓ

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A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude \(48.0 \mathrm{~N}\) to the box and produces an acceleration of magnitude \(2.20 \mathrm{~m} / \mathrm{s}^{2}\), what is the mass of the box?

Short Answer

Expert verified
The mass of the box is approximately 21.82 kg.

Step by step solution

01

Identify Given Variables

In this exercise, the force \(F\) is 48.0 N and the acceleration \(a\) is 2.20 m/s\(^2\).
02

Apply Newton's Second Law

Knowing that \(F = ma\), you can rearrange this formula to \(m = F/a\).
03

Calculate the Mass

By inserting the given values the force and acceleration to the equation \(m = F/a\) which is \(m = 48.0\,N / 2.20\,m/s^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
Understanding the relationship between force and acceleration is vital to comprehending the motion of objects. According to Newton's Second Law of Motion, the force applied to an object is directly proportional to the acceleration it gains, if the mass remains constant. This is often encapsulated in the equation
\( F = ma \), where \( F \) is the force in newtons, \( m \) is the mass in kilograms, and \( a \) is the acceleration in meters per second squared.

When a force is applied to an object, like the horizontal push given to the box resting on the ice in our exercise, the object will accelerate in the direction of the force. The greater the force applied, the greater the acceleration, if we keep the mass constant. Conversely, for the same force, a heavier object will accelerate less than a lighter one. This concept is fundamental in correctly predicting how objects will move under different forces.
Mass Calculation
Calculating mass becomes a straightforward process once we've understood Newton's Second Law. To find the mass of an object, we can rearrange the \( F = ma \) equation to \( m = \frac{F}{a} \). In our exercise, we were given the force applied and the acceleration produced. This allows us to perform a simple computation to determine the mass.

Inserting the provided values into the rearranged equation gives us \( m = \frac{48.0\,N}{2.20\,m/s^{2}} \), which will yield the mass of the box in kilograms. It's important to remember that the units of force and acceleration are crucial for getting the correct mass unit, which is typically kilograms in the metric system. With this approach to mass calculation, we can solve a variety of problems involving motion and force.
Frictionless Motion
Frictionless motion is a theoretical concept where there is no frictional force to resist the movement of an object. In reality, all surfaces exert some friction, but for certain scenarios, like our textbook exercise with the box on a frozen pond, assuming a frictionless surface simplifies the problem and focuses our attention on how forces affect motion in an idealized situation.

Without friction, the only force at play in the horizontal direction is the one applied by the fisherman. This means that the entire force contributes to the acceleration of the box, without any part of it being 'lost' to overcoming friction. When calculating the effects of forces in a frictionless scenario, it helps students focus on grasping the essential principles of dynamics — an object in motion will stay in motion at constant velocity unless acted upon by an unbalanced force, as per Newton's First Law. This simplification can make it easier to understand the foundational mechanics at work.

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Most popular questions from this chapter

The position of a training helicopter (weight \(2.75 \times 10^{5} \mathrm{~N}\) ) in a test is given by \(\hat{r}=\left(0.020 \mathrm{~m} / \mathrm{s}^{3}\right) t^{3} \hat{\imath}+\) \((2.2 \mathrm{~m} / \mathrm{s}) t \hat{\jmath}-\left(0.060 \mathrm{~m} / \mathrm{s}^{2}\right) t^{2} \hat{k} .\) Find the net force on the helicopter at \(t=5.0 \mathrm{~s}\)

A mysterious rocket-propelled object of mass \(45.0 \mathrm{~kg}\) is initially at rest in the middle of the horizontal, frictionless surface of an ice- covered lake. Then a force directed east and with magnitude \(F(t)=(16.8 \mathrm{~N} / \mathrm{s}) t\) is applied. How far does the object travel in the first \(5.00 \mathrm{~s}\) after the force is applied?

An advertisement claims that a particular automobile can "stop on a dime." What net force would be necessary to stop a \(850 \mathrm{~kg}\) automobile traveling initially at \(45.0 \mathrm{~km} / \mathrm{h}\) in a distance equal to the diameter of a dime, \(1.8 \mathrm{~cm} ?\)

A block of mass \(2.00 \mathrm{~kg}\) is initially at rest at \(x=0\) on a slippery horizontal surface for which there is no friction. Starting at time \(t=0,\) a horizontal force \(F_{x}(t)=\beta-\alpha t\) is applied to the block, where \(\alpha=6.00 \mathrm{~N} / \mathrm{s}\) anwd \(\beta=4.00 \mathrm{~N}\). (a) What is the largest positive value of \(x\) reached by the block? How long does it take the block to reach this point, starting from \(t=0,\) and what is the magnitude of the force when the block is at this value of \(x ?\) (b) How long from \(t=0\) does it take the block to return to \(x=0,\) and what is its speed at this point?

A batter swings at a baseball (mass \(0.145 \mathrm{~kg}\) ) that is moving horizontally toward him at a speed of \(40.0 \mathrm{~m} / \mathrm{s} .\) He hits a line drive with the ball moving away from him horizontally at \(50.0 \mathrm{~m} / \mathrm{s}\) just after it leaves the bat. If the bat and ball are in contact for \(8.00 \mathrm{~ms}\), what is the average force that the bat applies to the ball?

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