/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A box rests on a frozen pond, wh... [FREE SOLUTION] | 91Ó°ÊÓ

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A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude \(48.0 \mathrm{~N}\) to the box and produces an acceleration of magnitude \(2.20 \mathrm{~m} / \mathrm{s}^{2}\), what is the mass of the box?

Short Answer

Expert verified
The mass of the box is approximately 21.82 kg.

Step by step solution

01

Identify Given Variables

In this exercise, the force \(F\) is 48.0 N and the acceleration \(a\) is 2.20 m/s\(^2\).
02

Apply Newton's Second Law

Knowing that \(F = ma\), you can rearrange this formula to \(m = F/a\).
03

Calculate the Mass

By inserting the given values the force and acceleration to the equation \(m = F/a\) which is \(m = 48.0\,N / 2.20\,m/s^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
Understanding the relationship between force and acceleration is vital to comprehending the motion of objects. According to Newton's Second Law of Motion, the force applied to an object is directly proportional to the acceleration it gains, if the mass remains constant. This is often encapsulated in the equation
\( F = ma \), where \( F \) is the force in newtons, \( m \) is the mass in kilograms, and \( a \) is the acceleration in meters per second squared.

When a force is applied to an object, like the horizontal push given to the box resting on the ice in our exercise, the object will accelerate in the direction of the force. The greater the force applied, the greater the acceleration, if we keep the mass constant. Conversely, for the same force, a heavier object will accelerate less than a lighter one. This concept is fundamental in correctly predicting how objects will move under different forces.
Mass Calculation
Calculating mass becomes a straightforward process once we've understood Newton's Second Law. To find the mass of an object, we can rearrange the \( F = ma \) equation to \( m = \frac{F}{a} \). In our exercise, we were given the force applied and the acceleration produced. This allows us to perform a simple computation to determine the mass.

Inserting the provided values into the rearranged equation gives us \( m = \frac{48.0\,N}{2.20\,m/s^{2}} \), which will yield the mass of the box in kilograms. It's important to remember that the units of force and acceleration are crucial for getting the correct mass unit, which is typically kilograms in the metric system. With this approach to mass calculation, we can solve a variety of problems involving motion and force.
Frictionless Motion
Frictionless motion is a theoretical concept where there is no frictional force to resist the movement of an object. In reality, all surfaces exert some friction, but for certain scenarios, like our textbook exercise with the box on a frozen pond, assuming a frictionless surface simplifies the problem and focuses our attention on how forces affect motion in an idealized situation.

Without friction, the only force at play in the horizontal direction is the one applied by the fisherman. This means that the entire force contributes to the acceleration of the box, without any part of it being 'lost' to overcoming friction. When calculating the effects of forces in a frictionless scenario, it helps students focus on grasping the essential principles of dynamics — an object in motion will stay in motion at constant velocity unless acted upon by an unbalanced force, as per Newton's First Law. This simplification can make it easier to understand the foundational mechanics at work.

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Most popular questions from this chapter

A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of \(20.0^{\circ},\) and the man pulls upward with a force \(\vec{F}\) whose direction makes an angle of \(30.0^{\circ}\) with the ramp (Fig. E4.4). (a) How large a force \(\vec{F}\) is necessary for the component \(F_{x}\) parallel to the ramp to be \(90.0 \mathrm{~N} ?\) (b) How large will the component \(F_{y}\) perpendicular to the ramp be then?

A block of mass \(2.00 \mathrm{~kg}\) is initially at rest at \(x=0\) on a slippery horizontal surface for which there is no friction. Starting at time \(t=0,\) a horizontal force \(F_{x}(t)=\beta-\alpha t\) is applied to the block, where \(\alpha=6.00 \mathrm{~N} / \mathrm{s}\) anwd \(\beta=4.00 \mathrm{~N}\). (a) What is the largest positive value of \(x\) reached by the block? How long does it take the block to reach this point, starting from \(t=0,\) and what is the magnitude of the force when the block is at this value of \(x ?\) (b) How long from \(t=0\) does it take the block to return to \(x=0,\) and what is its speed at this point?

At the surface of Jupiter's moon Io, the acceleration due to gravity is \(g=1.81 \mathrm{~m} / \mathrm{s}^{2}\). A watermelon weighs \(44.0 \mathrm{~N}\) at the surface of the earth. (a) What is the watermelon's mass on the earth's surface? (b) What would be its mass and weight on the surface of Io?

Starting at time \(t=0\), net force \(F_{1}\) is applied to an object that is initially at rest. (a) If the force remains constant with magnitude \(F_{1}\) while the object moves a distance \(d\), the final speed of the object is \(v_{1} .\) What is the final speed \(v_{2}\) (in terms of \(v_{1}\) ) if the net force is \(F_{2}=2 F_{1}\) and the object moves the same distance \(d\) while the force is being applied? (b) If the force \(F_{1}\) remains constant while it is applied for a time \(T,\) the final speed of the object is \(v_{1} .\) What is the final speed \(v_{2}\) (in terms of \(v_{1}\) ) if the applied force is \(F_{2}=2 F_{1}\) and is constant while it is applied for the same time \(T ?\) In a later chapter we'll call force times distance work and force times time impulse and associate work and impulse with the change in speed.)

Boxes \(A\) and \(B\) are in contact on a horizontal, frictionless surface (Fig. E4.23). Box A has mass \(20.0 \mathrm{~kg}\) and box \(B\) has mass \(5.0 \mathrm{~kg} .\) A horizontal force of \(250 \mathrm{~N}\) is exerted on box \(A\). What is the magnitude of the force that box \(A\) exerts on box \(B ?\)

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