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At the surface of Jupiter's moon Io, the acceleration due to gravity is \(g=1.81 \mathrm{~m} / \mathrm{s}^{2}\). A watermelon weighs \(44.0 \mathrm{~N}\) at the surface of the earth. (a) What is the watermelon's mass on the earth's surface? (b) What would be its mass and weight on the surface of Io?

Short Answer

Expert verified
The mass of the watermelon on Earth would be approximately 4.48 kg. The same watermelon would still have a mass of 4.48 kg on Io, but its weight would decrease to 8.11 N due to the lower gravity.

Step by step solution

01

Calculate the mass on Earth

We know that weight = mass * gravity. Rearranging this formula we can find the mass on Earth. \(Mass = Weight/g\). Given the weight on Earth is 44.0 N and g on Earth is \(9.81 \mathrm{~m} / \mathrm{s}^{2}\). We substitute these values into the formula.
02

Calculate the weight on Io

Now that we know the mass of the object, we can find the weight of the object on Io using the formula weight = mass * gravity. Given that g on Io is \(1.81 \mathrm{~m} / \mathrm{s}^{2}\), we substitute these values in to determine the weight on Io.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Understanding the concept of acceleration due to gravity is foundational in gravitational physics. This acceleration is a measure of how quickly an object picks up speed as it falls toward the surface of a celestial body, due to the body’s gravitational pull. On Earth, this acceleration is approximately 9.81 meters per second squared (\(9.81 \text{ m/s}^{2}\)), and it is denoted by the symbol 'g'.

Importantly, this value is not constant across all celestial bodies—it varies based on the body's mass and radius. For instance, on Jupiter's moon Io, 'g' is 1.81 meters per second squared (\(1.81 \text{ m/s}^{2}\)). This means that an object on Io would accelerate at a slower rate compared to Earth because Io's gravitational pull is weaker.
Weight and Mass Relationship
The relationship between weight and mass is one of the pivotal ideas in physics. Mass is a measure of the amount of matter in an object, typically measured in kilograms. It remains constant regardless of location. Weight, on the other hand, is the force exerted on an object due to gravity and is measured in newtons. The formula that connects these quantities is simple: Weight = Mass × Gravity (\(W = m \times g\)).

In our exercise, to find the mass of a 44.0 newton watermelon on Earth, we rearrange the formula to Mass = Weight ÷ Gravity (\(m = W/g\)). This formula is key for converting weight (a force) to mass (a scalar quantity), provided we know the value of 'g'. The watermelon’s mass doesn’t change when it is transported to Io; however, its weight does because Io’s 'g' is less than Earth's.
Gravitational Acceleration on Different Celestial Bodies
Gravitational acceleration on different celestial bodies is an enthralling topic because it so clearly demonstrates the diversity of our solar system. Each celestial body has its own value of 'g', influenced by its mass and the distance from its center to the surface. Larger planets like Jupiter have a higher 'g' compared to smaller planets like Mars or moons such as Io. This variance has practical implications, such as how much a spacecraft needs to accelerate to escape a planet’s gravity or how much an astronaut can lift on a different planet or moon.

For example, the watermelon that weighs 44.0 N on Earth would have a different weight on Io. After finding the mass, as we did in the exercise, we use that same mass to calculate the new weight on Io (\(W = m \times g\text{ on Io}\)). Weight on Io is less because of its lower 'g', not because the watermelon's mass has changed. This illustrates how gravity not only shapes the weight of objects but also profoundly affects the surface conditions on various celestial bodies.

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Most popular questions from this chapter

A small rocket with mass \(20.0 \mathrm{~kg}\) is moving in free fall toward the earth. Air resistance can be neglected. When the rocket is \(80.0 \mathrm{~m}\) above the surface of the earth, it is moving downward with a speed of \(30.0 \mathrm{~m} / \mathrm{s}\). At that instant the rocket engines start to fire and produce a constant upward force \(F\) on the rocket. Assume the change in the rocket's mass is negligible. What is the value of \(F\) if the rocket's speed becomes zero just as it reaches the surface of the earth, for a soft landing? (Hint: The net force on the rocket is the combination of the upward force \(F\) from the engines and the downward weight of the rocket.)

A \(68.5 \mathrm{~kg}\) skater moving initially at \(2.40 \mathrm{~m} / \mathrm{s}\) on rough horizontal ice comes to rest uniformly in \(3.52 \mathrm{~s}\) due to friction from the ice. What force does friction exert on the skater?

A chair of mass \(12.0 \mathrm{~kg}\) is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force \(F=40.0 \mathrm{~N}\) that is directed at an angle of \(37.0^{\circ}\) below the horizontal, and the chair slides along the floor. (a) Draw a clearly labeled free-body diagram for the chair. (b) Use your diagram and Newton's laws to calculate the normal force that the floor exerts on the chair.

Estimate the mass in kilograms and the weight in pounds of a typical sumo wrestler. How do your estimates for the wrestler compare to your estimates of the average mass and weight of the students in your physics class? Do a web search if necessary to help make the estimates. In your solution list what values you assume for the quantities you use in making your estimates.

(a) An ordinary flea has a mass of \(210 \mu \mathrm{g}\). How many newtons does it weigh? (b) The mass of a typical froghopper is 12.3 mg. How many newtons does it weigh? (c) A house cat typically weighs \(45 \mathrm{~N}\). How many pounds does it weigh, and what is its mass in kilograms?

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