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If a photon of wavelength \(0.04250 \mathrm{nm}\) strikes a free electron and is scattered at an angle of \(35.0^{\circ}\) from its original direction, find (a) the change in the wavelength of this photon; (b) the wavelength of the scattered light; (c) the change in energy of the photon (is it a loss or a gain?); (d) the energy gained by the electron.

Short Answer

Expert verified
The change in the wavelength is found to be about \(2.44 \times 10^{-12} m\), the scattered photon’s new wavelength to be \(0.0450 nm\), the change in energy of the photon (and the energy gained by the electron) to be approximately \(7.33 \times 10^{-16} J\). The photon loses energy and the electron gains energy.

Step by step solution

01

Calculate the Compton Wavelength Shift

First, use the Compton scattering formula to calculate the change in wavelength (\(\Delta \lambda\)) of the photon. The formula is: \(\Delta \lambda = \lambda' - \lambda = h/(m_e c) \cdot (1 - \cos{\theta}) = \lambda_c \cdot (1 - \cos{\theta})\), where \(\lambda_c\) is the Compton wavelength of the electron (\(2.43 \times 10^{-12} m\)), \(m_e\) is the electron mass (\(9.11 \times 10^{-31} kg\)), \(c\) is the speed of light (\(3.0 \times 10^{8} m/s\)), \(\lambda\) is the initial wavelength of the photon (\(0.04250 nm\) or \(0.04250 \times 10^{-9} m\)) and \(\theta\) is the scattering angle (\(35.0^{\circ}\)). Convert the angle to radian because trigonometric functions in calculators use radian measure.
02

Calculate the Scattered Photon’s Wavelength

The new, scattered wavelength (\(\lambda'\)) of the photon after the interaction is simply the initial wavelength (\(\lambda\)) plus the change in wavelength (\(\Delta \lambda\)): \(\lambda' = \lambda + \Delta \lambda\).
03

Compute the Change in Energy of the Photon

To find out the change in energy of the photon, we have to convert the change in wavelength from Step 1 to energy using the Planck-Einstein relation (\(E = hc/\lambda\)). Since \(\Delta E = E' - E\), we have \(\Delta E = hc / (\lambda + \Delta \lambda) - hc/\lambda\).
04

Determine the Energy Gained by the Electron

The energy gained by the electron is equal to the energy lost by the photon. Thus, the energy gained by the electron is equivalent to the change in energy of the photon from Step 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Photon Wavelength
The concept of photon wavelength is central to understanding how electromagnetic waves interact with matter. A photon's wavelength is the distance over which the wave's shape repeats. It is usually measured in nanometers (nm) for visible and near-visible light.

In a Compton scattering scenario, a photon with an initial wavelength interacts with a free electron. The key equation here is the Compton wavelength shift formula, which predicts how the wavelength changes post-collision. This formula is: \[\Delta \lambda = \lambda_c \cdot (1 - \cos{\theta})\]where:
  • \(\Delta \lambda\) is the change in wavelength,
  • \(\lambda_c\) is the Compton wavelength for an electron,
  • and \(\theta\) is the scattering angle.
This formula tells us how the photon's wavelength increases due to the scattering. Remember, the increase in wavelength indicates a shift to lower energy, which reveals how energy is transferred during the scattering process.
Scattering Angle
The scattering angle, represented as \(\theta\), is crucial in understanding the direction change of a photon after interaction. It defines the angle between the original path of the photon and its path after the collision with an electron.

The angle plays a vital role in determining how much the photon's wavelength will change post-collision. A larger angle typically results in a more significant wavelength shift, hinting at more energy being transferred to the electron. This relationship is encapsulated in the cosine term in the Compton shift formula \(1 - \cos{\theta}\).

Remember that in calculations, this angle needs to be converted from degrees to radians because trigonometric functions in formulas require angles in radians. Using the correct unit is pivotal to accurately calculating the wavelength shift and understanding how scattering redistributes the photon's energy.
Energy Change
Scattered photons experience energy changes, which are directly linked to changes in their wavelengths. To calculate this energy change, the Planck-Einstein relation is used. This relation describes energy as inversely proportional to wavelength:\[E = \frac{hc}{\lambda}\]where:
  • \(E\) is the energy of the photon,
  • \(h\) represents Planck's constant,
  • \(c\) is the speed of light,
  • and \(\lambda\) is the photon's wavelength.
The change in the photon's energy due to scattering is calculated using its initial and final wavelengths:\[\Delta E = \frac{hc}{\lambda + \Delta \lambda} - \frac{hc}{\lambda}\]This equation shows that the photon's energy decreases when its wavelength increases, transferring energy from the photon to the electron. Thus, in Compton scattering, the photon always loses energy, which the electron gains through this interaction.
Electron Wavelength
While photons have wavelengths, electrons can also be described using a wavelength – albeit not in the same way as light. After a photon scatters, the electron it collides with gains energy and momentum. This energy manifests itself in the electron's movement, which is characterized by its own wavelength known as the de Broglie wavelength.

Electron wavelength is calculated using the de Broglie hypothesis, which states that every moving particle has a wavelength \(\lambda_e\) given by:\[\lambda_e = \frac{h}{p}\]where \(p\) is the momentum of the electron. After scattering, the momentum reflects the energy the electron gained from the photon. This principle highlights how matter wave concepts apply to particles like electrons, especially when they interact at atomic and subatomic levels.

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Most popular questions from this chapter

A pulsed dye laser emits light of wavelength \(585 \mathrm{nm}\) in \(450 \mu \mathrm{s}\) pulses. Because this wavelength is strongly absorbed by the hemoglobin in the blood, the method is especially effective for removing various types of blemishes due to blood, such as portwine-colored birthmarks. To get a reasonable estimate of the power required for such laser surgery, we can model the blood as having the same specific heat and heat of vaporization as water \(\left(4190 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, 2.256 \times 10^{6} \mathrm{~J} / \mathrm{kg}\right)\) Suppose that each pulse must remove \(2.0 \mu \mathrm{g}\) of blood by evaporating it, starting at \(33^{\circ} \mathrm{C}\). (a) How much energy must each pulse deliver to the blemish? (b) What must be the power output of this laser? (c) How many photons does each pulse deliver to the blemish?

A horizontal beam of laser light of wavelength \(585 \mathrm{nm}\) passes through a narrow slit that has width \(0.0620 \mathrm{~mm}\). The intensity of the light is measured on a vertical screen that is \(2.00 \mathrm{~m}\) from the slit. (a) What is the minimum uncertainty in the vertical component of the momentum of each photon in the beam after the photon has passed through the slit? (b) Use the result of part (a) to estimate the width of the central diffraction maximum that is observed on the screen.

An \(x\) -ray photon is scattered from a free electron (mass \(m\) ) at rest. The wavelength of the scattered photon is \(\lambda^{\prime},\) and the final speed of the struck electron is \(v\). (a) What was the initial wavelength \(\lambda\) of the photon? Express your answer in terms of \(\lambda^{\prime}, v,\) and \(m .\) (Hint: Use the relativistic expression for the electron kinetic energy.) (b) Through what angle \(\phi\) is the photon scattered? Express your answer in terms of \(\lambda, \lambda^{\prime},\) and \(m .\) (c) Evaluate your results in parts (a) and (b) for a wavelength of \(5.10 \times 10^{-3} \mathrm{nm}\) for the scattered photon and a final electron speed of \(1.80 \times 10^{8} \mathrm{~m} / \mathrm{s} .\) Give \(\phi\) in degrees.

We can estimate the number of photons in a room using the following reasoning: The intensity of the sun's rays at the earth's surface is roughly \(1000 \mathrm{~W} / \mathrm{m}^{2}\). A typical room is illuminated by indirect light or by light bulbs so that its light intensity is some fraction of that value. (a) Estimate the intensity of the light that enters your room. (b) Model the light as entering uniformly at the ceiling and exiting uniformly at the floor. Estimate the area \(A\) of the floor and ceiling, and the height \(H\) of your room. (c) Estimate how long it takes light to travel from the ceiling to the floor of your room by dividing \(H\) by the speed of light. (d) Estimate the total power of the light that enters your room \(P\) by multiplying your estimated intensity \(I\) by the area of your ceiling \(A\). (e) Estimate the total light energy in your room \(E_{\text {room }}\) by multiplying the power \(P\) by the length of time it takes light to travel from ceiling to floor. (f) An average wavelength for light is in the middle of the visible spectrum, at roughly \(500 \mathrm{nm}\). What is the energy of a \(500 \mathrm{nm}\) photon? (g) The total number of photons in your room \(N\) is the ratio of the energy \(E_{\text {room }}\) to the energy per photon. What is your estimate for \(N ?\)

A photon has momentum of magnitude \(8.24 \times 10^{-28} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\) (a) What is the energy of this photon? Give your answer in joules and in electron volts. (b) What is the wavelength of this photon? In what region of the electromagnetic spectrum does it lie?

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