/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 In the earth's rest frame, two p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the earth's rest frame, two protons are moving away from each other at equal speed. In the frame of each proton, the other proton has a speed of \(0.700 c\). What does an observer in the rest frame of the earth measure for the speed of each proton?

Short Answer

Expert verified
The speed of each proton, as measured from the earth's rest frame, is \(0.94 c\).

Step by step solution

01

Identifying Given Information

From the problem, the speed of each proton from each other's perspective (in their frame of reference) is \(0.700 c\). The aim is to find the speed of each proton in the earth's rest frame.
02

Understanding Relative Velocity in Special Relativity

In special relativity, adding velocities is not as straightforward as in classical physics. The Einstein's velocity addition formula states that if an object moves at a speed \(v_1\) in one frame, and that frame is moving at a speed \(v_2\) in a second frame, the object's speed in the second frame (v) is given by \(v = \frac{v_1 + v_2}{1 + \frac{v_1 v_2}{c^2}}\).
03

Calculating the Proton Speed in Earth's Frame

From the proton's frame, the other proton is moving away at a speed of \(0.700 c\). By symmetry, in the earth's frame, the protons are moving away from a common point in opposite directions, and have equal speeds \(v\). Therefore, use the Einstein's velocity addition formula with \(v_1 = v_2 = 0.700 c\) to solve for \(v\): \[v = \frac{0.700c + 0.700c}{1 + \frac{(0.700c)(0.700c)}{c^2}} = \frac{1.4c}{1 + 0.49} = 0.94c\]
04

Interpreting the Result

The calculated value is less than \(c = 1.0 c\), which is the maximum possible speed in physics (the speed of light). This demonstrates one of the key results from special relativity: No object can exceed the speed of light, regardless of relative velocities.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Einstein's Velocity Addition Formula
When we discuss motion in the context of special relativity, we cannot simply add velocities as we would in classical mechanics. Instead, we use Einstein's velocity addition formula, which accounts for the fact that the speed of light is the same in all inertial frames of reference.

This formula states that if we have an object moving at a speed of \(v_1\) in one frame, and that frame itself moves at speed \(v_2\) relative to another frame; the object's velocity \(v\) in the second frame is given by:\[v = \frac{v_1 + v_2}{1 + \frac{v_1 v_2}{c^2}}\]

Here, \(c\) represents the speed of light, which is approximately \(299,792,458\) meters per second. No matter how fast the speeds \(v_1\) and \(v_2\) are, if they are below the speed of light, their sum according to this formula could never exceed \(c\). This is a key concept that vastly differs from our everyday experiences with speeds and inherently demonstrates the revolutionary ideas brought forth by Einstein.
Relative Velocity in Special Relativity
The principle of relative velocity in special relativity illustrates that motion is not absolute but relative to the observer's frame of reference. Unlike in Newtonian mechanics, where velocities are added linearly, relative velocity in special relativity becomes increasingly non-linear as the speeds approach that of light.

As seen in the exercise involving two protons, we had to account for each proton's perspective and then translate that into the Earth's rest frame. This process was made possible by applying the Einstein velocity addition formula. It is important to understand the symmetry involved in such problems: both protons are moving apart in opposite directions at equal speeds when observed from the earth's frame, simplifying the use of the formula.

This introduces a fascinating consequence: speeds close to the speed of light result in unexpected and counter-intuitive outcomes, such as time dilation and length contraction, which are beyond our everyday experiences.
Speed of Light in Physics
The speed of light, denoted as \(c\), is a fundamental constant of the universe and is crucial in both theories of relativity and quantum mechanics. In the vacuum of space, it is exactly \(299,792,458\) meters per second and does not change regardless of the motion of the source or the observer.

This unchanging speed sets the maximum limit for how fast any information, energy, or matter can travel through space-time. Therefore, it serves as a cosmic speed limit. Interestingly, in the proton exercise, even though the protons appear to be moving away from each other at speeds that would suggest a simple sum greater than the speed of light, the relativistic velocity addition formula ensures that their actual speeds, when calculated in any inertial frame, do not surpass this universal limit. Einstein's theory of special relativity, which is built around this constant speed 'c', modifies our understanding of space and time, leading to groundbreaking conclusions about the universe we inhabit.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The negative pion \(\left(\pi^{-}\right)\) is an unstable particle with an average lifetime of \(2.60 \times 10^{-8} \mathrm{~s}\) (measured in the rest frame of the pion). (a) If the pion is made to travel at very high speed relative to a laboratory, its average lifetime is measured in the laboratory to be \(4.20 \times 10^{-7} \mathrm{~s}\). Calculate the speed of the pion expressed as a fraction of \(c\). (b) What distance, measured in the laboratory, does the pion travel during its average lifetime?

One way to strictly enforce a speed limit would be to alter the laws of nature. Suppose the speed of light were \(65 \mathrm{mph}\) and your workplace was 30 miles from your home. Assume you travel to work at a typical driving speed of 60 mph. (a) If you drove at that speed for the round trip to and from work, light, how much would your wristwatch lag your kitchen clock each day? (b) Estimate the length of your car. (c) If you were driving at your estimated driving speed, how long would your car be when viewed from the roadside? (d) What would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you? (e) How long would you measure those cars to be? (f) If the total mass of you and your car was \(2000 \mathrm{~kg}\), how much work would be required to get you up to speed? (Note: Your rest mass energy in this world is \(m c^{2}\), where \(c=65\) mph. ) (g) How much work would be required in the real world, where the speed of light is \(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s},\) to get you up to speed?

\(\mathrm{As}\) you pilot your space utility vehicle at a constant speed toward the moon, a race pilot flies past you in her spaceracer at a constant speed of \(0.800 c\) relative to you. At the instant the spaceracer passes you, both of you start timers at zero. (a) At the instant when you measure that the spaceracer has traveled \(1.20 \times 10^{8} \mathrm{~m}\) past you, what does the race pilot read on her timer? (b) When the race pilot reads the value calculated in part (a) on her timer, what does she measure to be your distance from her? (c) At the instant when the race pilot reads the value calculated in part (a) on her timer, what do you read on yours?

If a muon is traveling at \(0.999 c,\) what are its momentum and kinetic energy? (The mass of such a muon at rest in the laboratory is 207 times the electron mass.)

Inside a spaceship flying past the earth at three-fourths the speed of light, a pendulum is swinging. (a) If each swing takes \(1.80 \mathrm{~s}\) as measured by an astronaut performing an experiment inside the spaceship, how long will the swing take as measured by a person at mission control (on earth) who is watching the experiment? (b) If each swing takes \(1.80 \mathrm{~s}\) as measured by a person at mission control, how long will it take as measured by the astronaut in the spaceship?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.