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An observer in frame \(S^{\prime}\) is moving to the right \((+x\) -direction \()\) at speed \(u=0.600 c\) away from a stationary observer in frame \(S .\) The observer in \(S^{\prime}\) measures the speed \(v^{\prime}\) of a particle moving to the right away from her. What speed \(v\) does the observer in \(S\) measure for the particle if (a) \(v^{\prime}=0.400 c ;\) (b) \(v^{\prime}=0.900 c ;\) (c) \(v^{\prime}=0.990 c ?\)

Short Answer

Expert verified
The speed v measured by the observer in S for the particle is: (a) approximately 0.806c, (b) approximately 0.972c and (c) approximately 0.996c.

Step by step solution

01

Understand Lorentz Transformation

The Lorentz transformation, or velocity addition formula, can be applied to relate the velocities in two different frames (S and S'). The formula is: \(v = \frac{v' + u}{1 + \frac{v'u}{c^2}}\), where: \n- \(v'\) is the velocity of the particle according to the observer in frame S'. \n- \(u\) is the relative velocity between the two frames. \n- \(c\) is the speed of light. \n- \(v\) is the velocity of the particle according to the stationary observer in frame S.
02

Insert provided values and solve (a)

Insert the provided values into the formula: \(u= 0.600c\) and \(v'= 0.400c\). \nThen we get: \(v = \frac{0.400c + 0.600c}{1 + \frac{0.400c \cdot 0.600c}{c^2}}\). Simplify to get \(v = \frac{1.000c}{1 + 0.240}\), which calculates to \(v \approx 0.806c\).
03

Insert provided values and solve (b)

Again, insert the values into the above formula, but this time, \(v'= 0.900c\). So we get: \(v = \frac{0.900c + 0.600c}{1 + \frac{0.900c \cdot 0.600c}{c^2}}\). Simplify and solve to get \(v = \frac{1.500c}{1 + 0.540}\), which calculates to \(v \approx 0.972c\).
04

Insert provided values and solve (c)

Finally, insert the values into the formula, but now \(v'= 0.990c\). Hence: \(v = \frac{0.990c + 0.600c}{1 + \frac{0.990c \cdot 0.600c}{c^2}}\). Simplify it to: \(v = \frac{1.590c}{1 + 0.594}\), which calculations gives \(v \approx 0.996c\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
The concept of special relativity, introduced by Albert Einstein in 1905, revolutionized the way we understand time, space, and motion. Central to special relativity is the idea that the laws of physics are the same for all non-accelerating observers, regardless of their relative motion. It also postulates that the speed of light in a vacuum is constant and an absolute cosmic speed limit, which cannot be exceeded by any object with mass.

One of the most fascinating consequences of this theory is time dilation, where time can pass at different rates for observers in different states of motion. This means that clocks in a fast-moving spaceship would tick more slowly compared to those on Earth. Similarly, lengths can contract along the direction of motion — an effect known as length contraction — making objects appear shorter to a stationary observer as their speed approaches the speed of light.

These seemingly strange phenomena are not readily apparent in our everyday experiences because they only become significant at velocities close to the speed of light, denoted by the symbol 'c'. Special relativity has been confirmed by many experiments and has crucial implications for the understanding of the universe, including the need to adjust satellite clocks for global positioning systems to function accurately.
Velocity Addition
Velocity addition in special relativity is quite different from our intuitive understanding based on classical mechanics. In classical mechanics, to find the velocity of an object as observed from another moving frame, we can simply add or subtract the velocities depending on their direction. This approach does not work when dealing with velocities that are a significant fraction of the speed of light.

In special relativity, the velocity addition formula, also known as the Lorentz velocity transformation, must be used. It takes into account the constant speed of light and the limitations it imposes on adding velocities. The formula \[\begin{equation}v = \frac{v' + u}{1 + \frac{v'u}{c^2}}\end{equation}\]is used to calculate the velocity 'v' of an object as observed in one frame (S), based on its velocity 'v'' in another moving frame (S') and their relative velocity 'u'. As shown in the exercise solutions, applying the correct relativistic formula yields answers that differ from classical expectations, particularly as the speeds approach 'c'.

Furthermore, these calculations reveal that no matter how we combine velocities, the resultant speed will not surpass the speed of light, thus respecting the fundamental tenet of special relativity.
Frame of Reference
A frame of reference is a set of coordinates that a physicist or observer uses to measure positions and motions of objects. In simple terms, it's like using a ruler and a clock to describe where and when something is and how it's moving. In classical physics, frames of reference could be inertial, meaning they move at a constant velocity and are not accelerating, or they could be accelerating, each with its own rules for describing motion.

In the context of special relativity, inertial frames are of particular interest. They allow us to apply the Lorentz transformations and understand how different observers will view the same event differently. Depending on their relative motion, time intervals between events, spatial measurements, and even simultaneousness of events could differ dramatically from one frame to another.

For example, if a teacher in one classroom (frame S) sees two balloons pop simultaneously, a teacher in another classroom that is whizzing past at a high speed (frame S') might see one balloon pop before the other. This is not just a trick of the light; it is a real effect of how motion alters the measurement of time intervals and distances, emphasizing the relative nature of simultaneity in special relativity.

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Most popular questions from this chapter

Spaceship \(A\) moves past the earth at \(0.80 c\) to the west. Spaceship \(B\) approaches \(A,\) moving to the east. Both spaceship crews measure their relative speed of approach to be \(0.98 c .\) What mass would the crews of both spaceships measure for the standard kilogram, kept at rest on the earth, (a) according to classical physics and (b) according to the special theory of relativity?

(a) How much work must be done on a particle with mass \(m\) to accelerate it (a) from rest to a speed of \(0.090 c\) and (b) from a speed of \(0.900 c\) to a speed of \(0.990 c ?\) (Express the answers in terms of \(\left.m c^{2} .\right)\) (c) How do your answers in parts (a) and (b) compare?

Quarks and gluons are fundamental particles that will be discussed in Chapter \(44 .\) A proton, which is a bound state of two up quarks and a down quark, has a rest mass of \(m_{\mathrm{p}}=1.67 \times 10^{-27} \mathrm{~kg}\). This is significantly greater than the sum of the rest mass of the up quarks, which is \(m_{\mathrm{u}}=4.12 \times 10^{-30} \mathrm{~kg}\) each, and the rest mass of the down quark, which is \(m_{\mathrm{d}}=8.59 \times 10^{-30} \mathrm{~kg} .\) Suppose we (incorrectly) model the rest energy of the proton \(m_{\mathrm{p}} c^{2}\) as derived from the kinetic energy of the three quarks, and we split that energy equally among them. (a) Estimate the Lorentz factor \(\gamma=\left(1-v^{2} / c^{2}\right)^{-1 / 2}\) for each of the up quarks using Eq. \((37.36) .\) (b) Similarly estimate the Lorentz factor \(\gamma\) for the down quark. (c) Are the corresponding speeds \(v_{\mathrm{u}}\) and \(v_{\mathrm{d}}\) greater than \(99 \%\) of the speed of light? (d) More realistically, the quarks are held together by massless gluons, which mediate the strong nuclear interaction. Suppose we model the proton as the three quarks, each with a speed of \(0.90 c,\) with the remainder of the proton rest energy supplied by gluons. In this case, estimate the percentage of the proton rest energy associated with gluons. (e) Model a quark as oscillating with an average speed of \(0.90 c\) across the diameter of a proton, \(1.7 \times 10^{-15} \mathrm{~m}\). Estimate the frequency of that motion.

Two particles in a high-energy accelerator experiment approach each other head-on with a relative speed of \(0.890 c .\) Both particles travel at the same speed as measured in the laboratory. What is the speed of each particle, as measured in the laboratory?

Calculate the magnitude of the force required to give a \(0.145 \mathrm{~kg}\) baseball an acceleration \(a=1.00 \mathrm{~m} / \mathrm{s}^{2}\) in the direction of the baseball's initial velocity when this velocity has a magnitude of (a) \(10.0 \mathrm{~m} / \mathrm{s} ;\) (b) \(0.900 c ;\) (c) \(0.990 c\) (d) Repeat parts (a), (b), and (c) if the force and acceleration are perpendicular to the velocity.

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