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A diffraction grating has 650 slits \(/ \mathrm{mm}\). What is the highest order that contains the entire visible spectrum? (The wavelength range of the visible spectrum is approximately \(380-750 \mathrm{nm}\).)

Short Answer

Expert verified
The highest order that contains the entire visible spectrum for a diffraction grating with 650 slits \(/ \mathrm{mm}\) is 2.

Step by step solution

01

Calculate the slit spacing

The slit spacing 'd' can be calculated by \(d=1\ /\ Number\ of\ slits\ per\ mm\). In this case, \(d=1\ /\ 650=0.00154\ mm\), or when converted to meters for consistency in units, \(d=0.00154 × 10^{-3}\ m\).
02

Calculate the maximum order for each extreme

Substitute 'd', λ (for each extreme of the visible spectrum) and 'θ = 90 degrees' (meaning that \(sinθ=1\)) into the diffraction grating formula. The results are \(m_{380} = d/λ_{380} = (0.00154 × 10^{-3}) / (380 × 10^{-9})\) and \(m_{750} = d/λ_{750} = (0.00154 × 10^{-3}) / (750 × 10^{-9})\), which calculate to \(m_{380}\) approximately equal to 4 and \(m_{750}\) approximately equal to 2.
03

Determine maximum order for entire visible spectrum

The highest order that will contain the entire visible spectrum is the smaller of \(m_{380}\) and \(m_{750}\). In this case, \(m_{750}\) is the smallest, so the highest order that contains the entire visible spectrum is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Visible Spectrum
The visible spectrum refers to the portion of the electromagnetic spectrum that is visible to the human eye. This spectrum includes a range of colors, spanning from violet to red. The visible spectrum is bounded by wavelengths from approximately 380 nanometers (nm) to 750 nm. These colors can be represented in a rainbow, with violet at the lower end and red at the upper end of the spectrum. When light passes through a medium such as a diffraction grating, its different wavelengths are bent by different amounts, allowing us to see the separate components of the light.
Understanding the visible spectrum is crucial in various fields like optics, astronomy, and even art. It helps in the study of light properties, enabling the measurement of wavelengths of emission and absorption lines.
Always remember, the visible spectrum forms a small part of the entire electromagnetic spectrum, which includes other types of waves like ultraviolet and infrared that are not visible to the naked eye.
Order of Diffraction
The order of diffraction essentially tells us how many times the wavelengths of light have been split by interference. When light interacts with a diffraction grating, it creates interference patterns at specific angles. These patterns are termed "orders." The zeroth-order is where the light does not get split, while the first-order is the first set of separated wavelengths.
To determine higher orders, we use the formula:
  • \( m = \frac{d}{\lambda} \sin \theta \)
where \( m \) is the order, \( d \) is the slit spacing, \( \lambda \) is the wavelength, and \( \theta \) is the angle of diffraction.
In practical terms, if the angle \( \theta \) gets too large, further orders overlap or disappear from sight, especially in a finite space. This is why calculating the maximum visible order is important. It ensures the entire visible spectrum can be observed without overlaps in a given setup.
Wavelength Range
The wavelength range defines the limits within which any wave, particularly light, can be observed. For the visible light spectrum, this range is from 380 nm to 750 nm. Each color in the visible spectrum corresponds to a specific wavelength range within these limits.
For instance, violet light is found at the lower wavelength limit (around 380 nm), while red light occurs nearer to the upper limit (around 750 nm). This range is critical when it comes to calculations involving diffraction gratings, like in determining the order of diffraction.
A diffraction grating separates light into its component wavelengths, and knowing the range helps in understanding and anticipating how light will behave when passed through the grating. The maximum order that contains this entire range is dictated by the largest of these orders calculated from the wavelength extremes.
Therefore, comprehending the wavelength range not only helps in describing colors seen in various light but also plays a role in designing experiments and tools that manipulate light.

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Most popular questions from this chapter

Monochromatic light with wavelength \(490 \mathrm{nm}\) passes through a circular aperture, and a diffraction pattern is observed on a screen that is \(1.20 \mathrm{~m}\) from the aperture. If the distance on the screen between the first and second dark rings is \(1.65 \mathrm{~mm}\), what is the diameter of the aperture?

Light of wavelength \(633 \mathrm{nm}\) from a distant source is incident on a slit \(0.750 \mathrm{~mm}\) wide, and the resulting diffraction pattern is observed on a screen \(3.50 \mathrm{~m}\) away. What is the distance between the two dark fringes on either side of the central bright fringe?

The Hubble Space Telescope has an aperture of \(2.4 \mathrm{~m}\) and focuses visible light \((380-750 \mathrm{nm})\). The Arecibo radio telescope in Puerto Rico is \(305 \mathrm{~m}(1000 \mathrm{ft})\) in diameter (it is built in a mountain valley) and focuses radio waves of wavelength \(75 \mathrm{~cm}\). (a) Under optimal viewing conditions, what is the smallest crater that each of these telescopes could resolve on our moon? (b) If the Hubble Space Telescope were to be converted to surveillance use, what is the highest orbit above the surface of the earth it could have and still be able to resolve the license plate (not the letters, just the plate) of a car on the ground? Assume optimal viewing conditions, so that the resolution is diffraction limited.

The wavelength range of the visible spectrum is approximately \(380-750 \mathrm{nm} .\) White light falls at normal incidence on a diffraction grating that has 350 slits \(/ \mathrm{mm} .\) Find the angular width of the visible spectrum in (a) the first order and (b) the third order. (Note: An advantage of working in higher orders is the greater angular spread and better resolution. A disadvantage is the overlapping of different orders, as shown in Example \(36.4 .\) )

Coherent electromagnetic waves with wavelength \(\lambda=500 \mathrm{nm}\) pass through two identical slits. The width of each slit is \(a,\) and the distance between the centers of the slits is \(d=9.00 \mathrm{~mm}\). (a) What is the smallest possible width \(a\) of the slits if the \(m=3 \max -\) imum in the interference pattern is not present? (b) What is the next larger value of the slit width for which the \(m=3\) maximum is absent?

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