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A mirror on the passenger side of your car is convex and has a radius of curvature with magnitude \(18.0 \mathrm{~cm} .\) (a) Another car is behind your car, \(9.00 \mathrm{~m}\) from the mirror, and this car is viewed in the mirror by your passenger. If this car is \(1.5 \mathrm{~m}\) tall, what is the height of the image? (b) The mirror has a warning attached that objects viewed in it are closer than they appear. Why is this so?

Short Answer

Expert verified
Part (a): The height of the car's image in the mirror is 1.51 cm. Part (b): The warning is there because convex mirrors make objects appear smaller hence seemingly further away than they actually are.

Step by step solution

01

Convert Distance

Change all units into the same unit system for ease of calculation. So, convert the object distance into centimeters. Therefore, object distance (\(u\)) is -900 cm(since object is real its distance is taken negative).
02

Calculate Focal Length

Calculate the focal length (\(f\)). Since the mirror is convex, the focal length is negative. The radius of curvature is given as 18.0 cm. Focal length is half the radius, so \(f = -18/2 = -9 cm\).
03

Use the mirror formula

Use the mirror formula to solve for \(v\), the image distance: \(\frac{1}{f}= \frac{1}{v} + \frac{1}{u}\). Solving for \(v\) we find that \(v = \frac{1}{\frac{1}{f}-\frac{1}{u}}\). Substituting the values of \(u\) and \(f\) into the formula gives \(v = \frac{1}{\frac{1}{-9}-\frac{1}{-900}} = -9.1\) cm.
04

Use the magnification formula

Next, use the magnification formula \(m= -\frac{v}{u}=\frac{h'}{h}\) to solve for the height of the image (\(h'\)). The height of the object (h) is given as 1.5 m or 150 cm. Inserting these values into the equation, we get \(h' = m \cdot h = -\frac{v}{u} \cdot h = \frac{-(-9.1)}{-900} \cdot 150 = 1.51\) cm.
05

Analyze the Warning on the Mirror

Part b, the warning 'objects in the mirror are closer than they appear' is because the convex mirror forms a smaller image that covers a wide field of view. This could make objects appear farther away than they actually are.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Image Formation
In optical physics, the process by which a mirror or lens creates an image is known as image formation. With a convex mirror, the images formed are unique compared to those produced by flat or concave mirrors.
Convex mirrors are curved outward, resembling the exterior of a ball. This unique shape causes the reflected light rays to diverge more. Therefore, the image formed appears smaller and is located closer to the focal point. These images are termed virtual because they cannot be projected onto a screen.
The image formation process in convex mirrors makes these particularly useful for rearview mirrors on vehicles, as they allow drivers to see a wider field of view, ensuring better spatial awareness of other road users.
Mirror Formula
The mirror formula is crucial in determining the characteristics of the image formed by a mirror. This formula relates the object distance (uu), the image distance (vv), and the focal length (ff) of the mirror with the equation:\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]In this exercise, applying the mirror formula helps find out where the image is positioned in relation to the mirror. Convex mirrors have a negative focal length, reflecting their divergent nature.
This formula is flexible and universally applicable to different mirror types, but careful attention must be paid to the sign convention. For convex mirrors, both the focal length and image distance are taken as negative due to the virtual nature of images they produce.
Magnification
Magnification is the measure of how much larger or smaller an image is compared to the object itself. It tells us the size relation and is expressed as:\[ m = -\frac{v}{u} = \frac{h'}{h} \]Where \( m \) is the magnification, \( v \) is the image distance, \( u \) is the object distance, \( h' \) is the height of the image, and \( h \) is the height of the object. For convex mirrors, magnification values are positive but less than one, indicating that the image is smaller than the object.
In our example, the magnification value explains why the car viewed in the convex mirror looks smaller than it actually is. Therefore, drivers are warned that objects appear farther away because of this miniaturized image effect.
Optical Physics
Optical physics is the branch of physics concerned with light and its interactions with matter, such as mirrors and lenses. Understanding these interactions is essential for everyday applications, like the functioning of convex mirrors.
Convex mirrors exploit the principles of optical physics to provide a wider field of view. Such mirrors are used extensively in vehicles to facilitate a broad view of the surroundings. The optical principles ensure that images remain upright and smaller, thereby improving safety.
The way light behaves in various mediums allows scientists and engineers to design instruments and devices that enhance human sight and increase awareness of our surroundings in practical and reliable ways.

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Most popular questions from this chapter

You hold a spherical salad bowl \(60 \mathrm{~cm}\) in front of your face with the bottom of the bowl facing you. The bowl is made of polished metal with a \(35 \mathrm{~cm}\) radius of curvature. (a) Where is the image of your \(5.0-\mathrm{cm}\) -tall nose located? (b) What are the image's size, orientation, and nature (real or virtual)?

A transparent rod \(30.0 \mathrm{~cm}\) long is cut flat at one end and rounded to a hemispherical surface of radius \(10.0 \mathrm{~cm}\) at the other end. A small object is embedded within the rod along its axis and halfway between its ends, \(15.0 \mathrm{~cm}\) from the flat end and \(15.0 \mathrm{~cm}\) from the vertex of the curved end. When the rod is viewed from its flat end, the apparent depth of the object is \(8.20 \mathrm{~cm}\) from the flat end. What is its apparent depth when the rod is viewed from its curved end?

A thin lens with a focal length of \(6.00 \mathrm{~cm}\) is used as a simple magnifier. (a) What angular magnification is obtainable with the lens if the object is at the focal point? (b) When an object is examined through the lens, how close can it be brought to the lens? Assume that the image viewed by the eye is at the near point, \(25.0 \mathrm{~cm}\) from the eye, and that the lens is very close to the eye.

A small tropical fish is at the center of a water-filled, spherical fish bowl \(28.0 \mathrm{~cm}\) in diameter. (a) Find the apparent position and magnification of the fish to an observer outside the bowl. The effect of the thin walls of the bowl may be ignored. (b) A friend advised the owner of the bowl to keep it out of direct sunlight to avoid blinding the fish, which might swim into the focal point of the parallel rays from the sun. Is the focal point actually within the bowl?

The image of a tree just covers the length of a plane mirror \(4.00 \mathrm{~cm}\) tall when the mirror is held \(35.0 \mathrm{~cm}\) from the eye. The tree is \(28.0 \mathrm{~m}\) from the mirror. What is its height?

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