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A light bulb is \(3.00 \mathrm{~m}\) from a wall. You are to use a concave mirror to project an image of the bulb on the wall, with the image 3.50 times the size of the object. How far should the mirror be from the wall? What should its radius of curvature be?

Short Answer

Expert verified
The mirror should be \(2.33 m\) from the wall and its radius of curvature should be \(5.25 m\).

Step by step solution

01

Understand the Problem and Identify the known and unknown parameters

The distance of the object from the mirror is given as \(3.00 m\). The magnification (size of the image / size of the object) is given as \(3.50\). The task is to find the image distance from the mirror (\(d_i\)) and the radius of curvature of the mirror (\(R\)).
02

Apply the mirror equation

The mirror equation is \(1/d_o + 1/d_i = 1/f\) where \(d_o\) is the object distance, \(d_i\) is the image distance, and \(f\) is the focal length. But we don't know the focal length yet. So another equation is needed which is the magnification equation: \(m = -d_i / d_o = 3.5\). Multiply \(d_o\) to both sides to obtain \(d_i = -3.5d_o\).
03

Substitute \(d_i\) into the mirror equation

Substitute \(d_i = -3.5d_o\) into the mirror equation: \(1/d_o - 1/(-3.5d_o) = 1/f\). Solve for \(f\), the focal length. \(f = 0.875d_o\).
04

Calculate the focal length and image distance

Substitute \(d_o = 3.00 m\) into the equation \(f = 0.875d_o\) to get \(f\). Then, substitute \(f\) and \(d_o\) into the mirror equation to solve for \(d_i\).
05

Calculate the radius of curvature

For a mirror, the radius of curvature \(R = 2f\). Calculate \(R\) by substituting the value of \(f\).
06

Determine the location of the mirror

Identify the distance from the wall to the mirror. This is the difference between the distance from the wall to the image and the distance from the image to the mirror.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concave Mirror
A concave mirror is a type of spherical mirror with a reflective surface that curves inward, resembling a portion of a sphere or a bowl. These mirrors are known for their ability to converge light rays that strike their surface parallel to the principal axis.
Concave mirrors are used in various applications, ranging from telescopes to shaving mirrors. The central point on the surface of this mirror is known as the vertex, and the line passing through the vertex and the center of curvature is the principal axis. When an object is placed in front of a concave mirror, it can form different types of images depending on the object's distance from the mirror:
  • Real and inverted images when the object is beyond the focal point.
  • Virtual and upright images when the object is between the focal point and mirror.
The ability to focus light to a point makes concave mirrors particularly useful in focusing light beams.
Magnification
Magnification in optics refers to the process of enlarging or reducing the size of an image compared to the size of the original object. In the context of mirrors, magnification is a measure of how much larger or smaller the image of an object will appear when seen through a mirror. Magnification, denoted as \( m \), can be expressed mathematically as:\[m = \frac{\text{Height of Image}}{\text{Height of Object}}\]For spherical mirrors, magnification is also related to the distances of the object and image from the mirror:\[m = -\frac{d_i}{d_o}\]where \( d_i \) is the image distance and \( d_o \) is the object distance from the mirror.
The negative sign indicates that a positive magnification corresponds to an inverted image, while a negative magnification signifies an upright image.
Understanding magnification helps in determining the scale of the image produced by optical devices, which is crucial in applications such as photography, microscopy, and image projection.
Radius of Curvature
The radius of curvature, often denoted as \( R \), is a fundamental characteristic of spherical mirrors. It is defined as the distance from the mirror's surface to its center of curvature, which is the point around which the reflective surface of the mirror is sectioned from a sphere.
This radius effectively determines the "curviness" of the mirror.
For a concave mirror, the radius of curvature is twice the focal length:\[ R = 2f \]This relationship provides us with a crucial link between the mirror's focal length and radius.
Understanding the radius of curvature helps us to picture how the mirror directs light rays and forms images, impacting focal properties and focal length calculations.
Mirror Equation
The mirror equation is a formula crucial to the study and application of spherical mirrors, such as concave mirrors. It correlates the distances of the object and the image from the mirror with the focal length:\[ \frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} \]where:
  • \( d_o \) is the object distance (the distance from the mirror to the object).
  • \( d_i \) is the image distance (the distance from the mirror to the image).
  • \( f \) is the focal length of the mirror.
The mirror equation is an essential tool in optics, allowing for the determination of unknown distances when two of the distances are given.
By using the equation along with the magnification formula, one can solve for both the image location and the characteristics of the images formed by such mirrors. This is vital in designing and utilizing optical devices.

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Most popular questions from this chapter

A person swimming \(0.80 \mathrm{~m}\) below the surface of the water in a swimming pool looks at the diving board that is directly overhead and sees the image of the board that is formed by refraction at the surface of the water. This image is a height of \(5.20 \mathrm{~m}\) above the swimmer. What is the actual height of the diving board above the surface of the water?

An object with height \(4.00 \mathrm{~mm}\) is placed \(28.0 \mathrm{~cm}\) to the left of a converging lens that has focal length \(8.40 \mathrm{~cm} .\) A second lens is placed \(8.00 \mathrm{~cm}\) to the right of the converging lens. (a) What is the focal length of the second lens if the final image is inverted relative to the \(4.00-\mathrm{mm}\) -tall object and has height \(5.60 \mathrm{~mm} ?\) (b) What is the distance between the original object and the final image?

The image of a tree just covers the length of a plane mirror \(4.00 \mathrm{~cm}\) tall when the mirror is held \(35.0 \mathrm{~cm}\) from the eye. The tree is \(28.0 \mathrm{~m}\) from the mirror. What is its height?

To determine the focal length \(f\) of a converging thin lens, you place a \(4.00-\mathrm{mm}\) -tall object a distance \(s\) to the left of the lens and measure the height \(h^{\prime}\) of the real image that is formed to the right of the lens. You repeat this process for several values of \(s\) that produce a real image. After graphing your results as \(1 / h^{\prime}\) versus \(s\), both in \(\mathrm{cm}\), you find that they lie close to a straight line that has slope \(0.208 \mathrm{~cm}^{-2}\). What is the focal length of the lens?

You want to view through a magnifier an insect that is \(2.00 \mathrm{~mm}\) long. If the insect is to be at the focal point of the magnifier, what focal length will give the image of the insect an angular size of 0.032 radian?

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