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A parallel beam of unpolarized light in air is incident at an angle of \(54.5^{\circ}\) (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?

Short Answer

Expert verified
The refractive index of the glass is approximately the value of \(tan(54.5°)\). The angle of refraction can be obtained by calculating \(sin^{-1}(\frac{sin(54.5°)}{n_{glass}})\), using the refractive index calculated in part (a).

Step by step solution

01

Utilize Brewster's Law

Brewster's law states that the tangent of the polarizing angle (which here is the angle of incidence) equals to the refractive index \(n\). Therefore, we can write: \(n = tan(54.5°)\).
02

Calculate the Refractive Index

Calculate the value of \(tan(54.5°)\) to obtain the refractive index. This is the solution for part (a).
03

Utilize Snell's Law

Snell's law relates the angle of incidence, angle of refraction and the refractive indices of the two media. It can be represented as \(n_{air} sin(θ_{incidence}) = n_{glass} sin(θ_{refraction})\). Considering that the refractive index of air is approximately 1, and replacing \(n_{glass}\) with the previously calculated refractive index, we can solve the equation for \(θ_{refraction}\).
04

Calculate the Angle of Refraction

To calculate the angle of refraction, calculate the value of \(sin^{-1}(\frac{sin(54.5°)}{n_{glass}})\). This is the solution for part (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Refractive Index
The refractive index, often denoted as \( n \), is a crucial concept when discussing light and optics. It describes how much the speed of light is reduced inside a medium compared to its speed in a vacuum. Light travels slower in dense materials compared to air, meaning these materials have a higher refractive index.
A refractive index also indicates how much the light will bend, or refract, as it moves between different media. This bending occurs due to the change in speed of the light. For example, glass has a refractive index usually larger than air, thus causing the light to bend more when entering or exiting glass.
  • A higher refractive index means more significant bending of light.
  • The refractive index of air is about 1, while for glass it can range between 1.5 and 1.9 depending on the glass type.
Understanding refractive index is vital for many applications, such as designing lenses for eyeglasses, cameras, and other optical devices.
Snell's Law
Snell's Law is a fundamental principle in optics, which explains how light behaves when moving between different media. It connects the angles of incidence and refraction with the refractive indices of the two media involved. The law can be mathematically written as:\[n_{1}\sin(θ_{1}) = n_{2}\sin(θ_{2})\]where \( n_{1} \) and \( n_{2} \) are the refractive indices of medium 1 and medium 2, and \( θ_{1} \) and \( θ_{2} \) are the angles of incidence and refraction, respectively.
This formula allows us to predict how much a ray of light will bend when it passes from one medium to another.
  • If light travels from a less dense medium to a more dense medium, it bends towards the normal.
  • Conversely, if it travels from a more dense to a less dense medium, it bends away from the normal.
This law is used extensively in designing optical devices, such as lenses, prisms, and fiber optic cables.
Polarization of Light
Polarization of light refers to the orientation of the oscillations of the light waves. Unpolarized light, such as sunlight, vibrates in multiple directions, whereas polarized light vibrates in just one plane. This concept is important in many areas of optics and can be achieved by various methods, including reflection, refraction, or using special filters.
Brewster's Law is directly related to polarization by reflection. It tells us that at a certain angle, known as Brewster's angle, the reflected light will be perfectly polarized. This occurs when the reflected and refracted rays are perpendicular to each other.
  • The angle of incidence, where this happens, is called Brewster's angle and is given by \( \theta_B = \tan^{-1}(n) \), where \( n \) is the refractive index.
  • This is the principle utilized in polarizing sunglasses to reduce glare.
Understanding polarization helps in designing optical components, such as polarizing filters used in photography and in liquid crystal displays.

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Most popular questions from this chapter

Given \(\quad\) small samples of three liquids, you are asked to determine their refractive indexes. However, you do not have enough of each liquid to measure the angle of refraction for light refracting from air into the liquid. Instead, for each liquid, you take a rectangular block of glass \((n=1.52)\) and place a drop of the liquid on the top surface of the block. You shine a laser beam with wavelength \(638 \mathrm{nm}\) in vacuum at one side of the block and measure the largest angle of incidence \(\theta_{a}\) for which there is total internal reflection at the interface between the glass and the liquid (Fig. \(\mathbf{P 3 3 . 5 6}\) ). Your results are given in the table: $$ \begin{array}{l|lll} \text { Liquid } & A & B & C \\ \hline \boldsymbol{\theta}_{\boldsymbol{a}}\left({ }^{\circ}\right) & 52.0 & 44.3 & 36.3 \end{array} $$ What is the refractive index of each liquid at this wavelength?

When linearly polarized light passes through a polarizer, its polarizing axis may be rotated by any angle \(\phi<90^{\circ}\) at the expense of a loss of intensity, as determined by Malus's law. By using sequential polarizers, you can achieve a similar axis rotation but retain greater intensity. In fact, if you use many intermediate polarizers, the polarization axis can be rotated by \(90^{\circ}\) with virtually undiminished intensity. (a) Derive an equation for the resulting intensity if linearly polarized light passes through successive \(N\) polarizers, each with the polarizing axis rotated by an angle \(90^{\circ} / 2 N\) larger than the preceding polarizer. (b) By making a table of the resulting intensity for various values of \(N\), estimate the minimum number \(N\) of polarizers needed so that the light will have its polarization axis rotated by \(90^{\circ}\) while maintaining more than \(90 \%\) of its intensity. (c) Estimate the minimum number of polarizers needed to maintain more than \(95 \%\) and \(99 \%\) intensity.

A beam of light is traveling inside a solid glass cube that has index of refraction 1.62 . It strikes the surface of the cube from the inside. (a) If the cube is in air, at what minimum angle with the normal inside the glass will this light \(n o t\) enter the air at this surface? (b) What would be the minimum angle in part (a) if the cube were immersed in water?

The critical angle for total internal reflection at a liquid-air interface is \(42.5^{\circ} .\) (a) If a ray of light traveling in the liquid has an angle of incidence at the interface of \(35.0^{\circ},\) what angle does the refracted ray in the air make with the normal? (b) If a ray of light traveling in air has an angle of incidence at the interface of \(35.0^{\circ},\) what angle does the refracted ray in the liquid make with the normal?

(a) A tank containing methanol has walls \(2.50 \mathrm{~cm}\) thick made of glass of refractive index \(1.550 .\) Light from the outside air strikes the glass at a \(41.3^{\circ}\) angle with the normal to the glass. Find the angle the light makes with the normal in the methanol. (b) The tank is emptied and refilled with an unknown liquid. If light incident at the same angle as in part (a) enters the liquid in the tank at an angle of \(20.2^{\circ}\) from the normal, what is the refractive index of the unknown liquid?

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