/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 You have a special light bulb wi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds \(1.50 \mathrm{~A}\), even for an instant. What is the largest root-mean-square current you can run through this bulb?

Short Answer

Expert verified
The largest root-mean-square current that can be run through the bulb is approximately \(1.06 \mathrm{~A}\).

Step by step solution

01

Understanding Root-Mean-Square (RMS) Current

The root-mean-square current is a measure of the effective value of an alternating current, which is equal to the direct current that would produce the same amount of heat in a resistor.
02

Relationship between Peak and RMS Current

The relationship between the maximum or peak current (\(I_{max}\)) and the root-mean-square current (\(I_{rms}\)) in a sinusoidal waveform is given by the formula: \(I_{rms} = I_{max} / \sqrt{2}\).
03

Substitute given values into the formula

Substitute \(1.50 \mathrm{~A}\) for \(I_{max}\) in: \(I_{rms} = 1.50 \mathrm{~A} / \sqrt{2}\)
04

Calculate RMS Current

Calculate \(I_{rms}\) by dividing \(1.50 \mathrm{~A}\) by \(\sqrt{2}\). Remember to keep units consistent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Current
Electric current is the flow of electric charge carried by moving electrons in a wire. It's an important concept in electrical engineering and physics, and understanding it is crucial for working with any electrical system. There are two types of current: direct current (DC) and alternating current (AC). Direct current flows in only one direction, while alternating current reverses direction periodically.
In mathematical terms, electric current (I) is defined by the equation: \( I = \frac{Q}{t} \), where \( Q \) is the electric charge measured in coulombs (C), and \( t \) is the time in seconds (s). The unit of electric current is the ampere (A), which represents one coulomb of charge passing through a point in a circuit every second.
When dealing with electrical circuits, it's also important to consider electrical resistance, which opposes the flow of current. Ohm's law relates current (I), voltage (V), and resistance (R) in a simple equation: \( V = IR \). This shows that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.
Alternating Current
Alternating current (AC) is the type of electric current commonly found in homes and businesses. Unlike direct current (DC), where electrons flow in a single direction, the electrons in an AC circuit move back and forth rapidly. This reversal of direction happens at a frequency that depends on the power system; for example, it's 60 Hz in North America and 50 Hz in Europe.
AC is used for power transmission over long distances because it can be easily transformed into higher or lower voltages with a transformer, which reduces power loss. The root-mean-square (RMS) value of an AC current is particularly significant because it gives a measure of the current's effective power. RMS is calculated by taking the square root of the average of the squares of the instantaneous current over one cycle.
With RMS, we can equate an AC current to a corresponding DC current that would produce the same heating effect in a resistor. This is crucial for designing electrical systems and ensuring the safety of components that are sensitive to current, like the delicate wire filament in our light bulb example.
Electrical Resistance
Electrical resistance is a measure of the opposition that a material presents to the flow of electric current. It's a fundamental property felt when electrons collide with atoms as they pass through a conducting material. The resistance of a material is determined by its shape, size, and the type of material.
Resistance is measured in ohms (\( \Omega \)), and according to Ohm’s law, it's found using the formula: \( R = \frac{V}{I} \), where \( R \) is resistance, \( V \) is voltage, and \( I \) is the current through the material. This relationship between voltage, current, and resistance is critical in understanding how electric circuits operate. High resistance in a component means less current will flow for a given voltage, and vice versa.
Materials with very low resistance, such as metals like copper or aluminum, are excellent conductors of electricity and are commonly used in wiring. On the other hand, materials with high resistance, like rubber or glass, are used as insulators to prevent unwanted flow of current.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(\operatorname{An} L-R-C\) series circuit has \(R=60.0 \Omega, L=0.800 \mathrm{H},\) and \(C=3.00 \times 10^{-4} \mathrm{~F}\). The ac source has voltage amplitude \(90.0 \mathrm{~V}\) and angular frequency \(120 \mathrm{rad} / \mathrm{s}\). (a) What is the maximum energy stored in the inductor? (b) When the energy stored in the inductor is a maximum, how much energy is stored in the capacitor? (c) What is the maximum energy stored in the capacitor?

You plan to take your hair dryer to Europe, where the electrical outlets put out \(240 \mathrm{~V}\) instead of the \(120 \mathrm{~V}\) seen in the United States. The dryer puts out \(1600 \mathrm{~W}\) at \(120 \mathrm{~V}\). (a) What could you do to operate your dryer via the \(240 \mathrm{~V}\) line in Europe? (b) What current will your dryer draw from a European outlet? (c) What resistance will your dryer appear to have when operated at \(240 \mathrm{~V}\) ?

If the frequency at which the electrode is oscillated is increased to a very large value, the electrode's impedance (a) approaches infinity; (b) approaches zero; (c) approaches a constant but nonzero value; (d) does not change.

(a) Compute the reactance of a \(0.450 \mathrm{H}\) inductor at frequencies of \(60.0 \mathrm{~Hz}\) and \(600 \mathrm{~Hz}\). (b) Compute the reactance of a \(2.50 \mu \mathrm{F}\) capacitor at the same frequencies. (c) At what frequency is the reactance of a \(0.450 \mathrm{H}\) inductor equal to that of a \(2.50 \mu \mathrm{F}\) capacitor?

An \(L-R-C\) series circuit is constructed using a \(175 \Omega\) resistor, a \(12.5 \mu \mathrm{F}\) capacitor, and an \(8.00 \mathrm{mH}\) inductor, all connected across an ac source having a variable frequency and a voltage amplitude of \(25.0 \mathrm{~V}\). (a) At what angular frequency will the impedance be smallest, and what is the impedance at this frequency? (b) At the angular frequency in part (a), what is the maximum current through the inductor? (c) At the angular frequency in part (a), find the potential difference across the ac source, the resistor, the capacitor, and the inductor at the instant that the current is equal to one-half its greatest positive value. (d) In part (c), how are the potential differences across the resistor, inductor, and capacitor related to the potential difference across the ac source?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.