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A charged capacitor with \(C=590 \mu \mathrm{F}\) is connected in series to an inductor that has \(L=0.330 \mathrm{H}\) and negligible resistance. At an instant when the current in the inductor is \(i=2.50 \mathrm{~A},\) the current is increasing at a ratc of \(d i / d t=73.0 \mathrm{~A} / \mathrm{s}\). During the current oscillations. what is the maximum voltage across the capacitor?

Short Answer

Expert verified
After performing the calculations from the above steps, you will find the maximum voltage across the capacitor.

Step by step solution

01

Apply Ampere's Law to relate the magnetic field to current

By Ampere's Law, in a circuit with inductance \(L\), the back emf in the inductor, \(V_L\), is given by \(V_L = L(di/dt)\). Substituting the given values \(L = 0.330H\) and \(di/dt = 73.0A/s\), we calculate \(V_L\).
02

Apply Kirchhoff’s Voltage Law

According to Kirchhoff’s voltage law, the algebraic sum of all the potential differences around any closed loop or mesh in a network is always equal to zero. Therefore, the voltage across the capacitor (\(V_c\)) is equal to the back emf (\(V_L\)) in the inductor at any instant. Thus, \(V_c = V_L\).
03

Calculate the maximum voltage across the capacitor

From above steps, the maximum voltage across the capacitor is simply the voltage across the inductor, which can be calculated from \(V_c = L(di/dt)\). Substitute \(L\) and \(di/dt\) with the given values and solve for \(V_c\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampere's Law
Ampere's Law is integral in understanding how magnetic fields are produced by electric currents.

It's one of Maxwell’s equations, and it describes the relation between current and magnetism. In essence, Ampere's Law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability of free space times the electric current enclosed in the loop. Mathematically, it's expressed as \[\begin{equation}\bigcirc B \bullet dl = \text{μ0}\times I_{enc}\end{equation}\] where B is the magnetic field, dl is a differential element of the path length, \text{μ0} is the permeability of free space, and \text{I}_{enc} is the enclosed current.

In a practical sense, when we have an inductor with a current changing over time, Ampere's Law can be used to understand how this changing current generates a magnetic field, which then, according to Faraday's Law of Electromagnetic Induction, induces an electromotive force (emf) in the opposite direction, known as the back emf. This is crucial for the operation of an LC circuit, where changes in electric current and magnetic fields are intimately connected.
Kirchhoff's Voltage Law
Kirchhoff's Voltage Law (KVL) is a fundamental principle used in circuit analysis. It's based on the conservation of energy principle applied to electrical circuits. Kirchhoff's Voltage Law states that the algebraic sum of all potential differences (voltages) around any closed loop in a circuit must equal zero.

In more elaborate terms, as you move around a loop, the increases in electric potential (coming from emf sources like batteries or induced emf in inductors) are exactly balanced by the drops in potential (like the voltage across resistors, capacitors, or inductors). Mathematically, the principle is expressed as \[\begin{equation}\sum V = 0\end{equation}\] where V represents the voltage drops or gains.

This law underlies the calculation of the maximum voltage across a capacitor in an LC circuit. Since the energy within the loop is conserved, the voltage developed across the capacitor must equal the voltage drop across the inductor, which allows us to solve for one knowing the other.
Capacitor Voltage Calculation
Understanding capacitor voltage calculations requires a grasp of what a capacitor is and how it behaves in a circuit. A capacitor is a device that stores charge and energy in the electric field between its plates. The voltage across a capacitor is proportional to the amount of charge it has stored.

The voltage across a capacitor in an LC circuit can be calculated using the formula \[\begin{equation}V_C = \frac{q}{C}\end{equation}\] where V_C is the capacitor voltage, q is the charge on the capacitor, and C is the capacitance.

In an LC oscillating circuit, the capacitor’s voltage and charge vary over time. As the circuit oscillates, energy is transferred back and forth between the capacitor's electric field and the inductor's magnetic field. The maximum capacitor voltage occurs when all the energy is stored in the electric field, which is the point of maximum charge on the capacitor plates.
Inductor Back Emf
The phenomenon of inductor back emf (electromotive force) is essential for the operation of LC circuits. An inductor is a coil of wire that resists changes in the current passing through it due to the magnetic field created by the current itself. When the current in an inductor changes, the magnetic field does too, creating a voltage across the inductor that opposes the change in current. This is known as back emf or counter emf.

The induced emf in an inductor can be calculated with the formula \[\begin{equation}V_L = L\frac{di}{dt}\end{equation}\] where V_L is the back emf, L is the inductance, di is the change in current, and dt is the change in time.

This back emf is particularly significant during the initial charging and discharging of the LC circuit, where it can cause oscillations if it's not dissipated. In the context of the textbook exercise, understanding inductor back emf helps to determine the voltage across the inductor at any point in time, which thanks to Kirchhoff's Voltage Law, is the same as the voltage across the capacitor at that instant.

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Most popular questions from this chapter

(a) What would have to be the self-inductance of a solenoid for it to store \(10.0 \mathrm{~J}\) of energy when a \(2.00 \mathrm{~A}\) current runs through it? (b) If this solenoid's cross-sectional diameter is \(4.00 \mathrm{~cm}\), and if you could wrap its coils to a density of 10 coils \(/ \mathrm{mm}\), how long would the solenoid be? (See Exercise \(30.11 .)\) Is this a realistic length for ordinary laboratory use?

In a proton accelerator used in clementary particle physics experiments, the trajectories of protons are controlled by bending magnets that produce a magnetic field of \(4.80 \mathrm{~T}\). What is the magnetic-field cnergy in a \(10.0 \mathrm{~cm}^{3}\) volume of space where \(B=4.80 \mathrm{~T} ?\)

{A} 6.40 \mathrm{nF} \text { capacitor is charged to } 24.0 \mathrm{~V} \text { and then discon- } nected from the battery in the circuit and connected in series with a coil that has \(L=0.0660 \mathrm{H}\) and negligible resistance. After the circuit has been completed, there are current oscillations. (a) At an instant when the charge of the capacitor is \(0.0800 \mu \mathrm{C}\), how much cnergy is stored in the capacitor and in the inductor, and what is the current in the inductor? (b) At the instant when the charge on the capacitor is \(0.0800 \mu \mathrm{C},\) what are the voltages across the capacitor and across the inductor, and what is the rate at which current in the inductor is changing?

C Consider a coil of wire that has radius \(3.00 \mathrm{~cm}\) and carries a sinusoidal current given by \(i(t)=I_{0} \sin (2 \pi f t),\) where the frequency \(f=60.0 \mathrm{IIz}\) and the initial current \(I_{0}=1.20 \mathrm{~A}\). (a) Estimate the magnetic flux through this coil as the product of the magnetic field at the center of the coil and the area of the coil. Use this magnctic flux to estimate the sclf-inductance \(L\) of the coil. (b) Use the value of \(L\) that you cstimated in part (a) to calculate the magnitudc of the maximum emf induced in the coil.

An \(L-C\) circuit consists of a \(60.0 \mathrm{mII}\) inductor and a \(250 \mu \mathrm{F}\) capacitor. The initial charge on the capacitor is \(6.00 \mu \mathrm{C},\) and the initial current in the inductor is zero. (a) What is the maximum voltage across the capacitor? (b) What is the maximum current in the inductor? (c) What is the maximum energy stored in the inductor? (d) When the current in the inductor has half its maximum value, what is the charge on the capacitor and what is the energy stored in the inductor?

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