/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 A projectile thrown from a point... [FREE SOLUTION] | 91Ó°ÊÓ

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A projectile thrown from a point \(P\) moves in such a way that its distance from \(P\) is always increasing. Find the maximum angle above the horizontal with which the projectile could have been thrown. Ignore air resistance.

Short Answer

Expert verified
The maximum angle above the horizontal with which the projectile could have been thrown is \(45^\circ\).

Step by step solution

01

Understand the given information

A object is projected from a point \(P\) such that its distance from \(P\) is always increasing. We need to find the maximum angle above the horizontal at which the object can be thrown under these conditions. Note that for a projectile thrown with an angle of \(45^\circ\), there is a point where the distance from \(P\) is no longer increases, thus, the maximum angle must be lower than \(45^\circ\).
02

Consider the sine function

Consider the sine function, which gives the ratio of the opposite side to the hypotenuse in a right triangle, and hence can be related to the angle and distance of projectile motion. In the first quadrant (which is the case here since we're only considering the upward throw), the sine function increases with the angle, reaches a maximum at \(90^\circ\) and then decreases. However, for our scenario, we're interested in the point where this function starts decreasing, as this will be the maximum angle to still have an increasing distance from origin. The sine function is at its peak at \(90^\circ\). However, our range is halved due to the constraint of the projectile motion, making the maximum at \(45^\circ\).
03

Finding the Maximum Angle

In the first quadrant, the sine function stops increasing at \(45^\circ\). Therefore, the maximum angle of projection under the given constraint is \(45^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Projectile Motion
Projectile motion describes the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory. The motion of a projectile can be understood as two separate, simultaneous movements: horizontal motion at a constant speed (since horizontal forces are typically ignored, including air resistance), and vertical motion, which is subject to gravity's acceleration.

For an object projected from a point, say point P, the distance from P will change as the object moves along its trajectory. The behaviour of this distance depends on the launch angle. To ensure the distance from P is always increasing, the angle needs to be optimized; too steep an angle would mean the projectile falls back toward P after reaching its peak height. This concept is crucial in various fields such as sports, where athletes need to optimize their launch angle for maximum distance, and in military applications where the angle of a projectile could determine its range and impact point.
Angle of Projection
The angle of projection is the angle at which a projectile is launched above the horizontal. This angle is vital as it significantly affects the projectile's range, height, and time of flight. The angle of projection interacts with the projectile’s initial velocity to determine the shape and length of its trajectory.

For any given initial velocity, there is a specific angle of projection that maximizes the range of the projectile - often, this angle is 45 degrees because it balances the vertical and horizontal components of the velocity equally. However, in scenarios with specific constraints, like the one in our exercise, it is not about finding the maximum range but about ensuring that the distance from the point of projection is always increasing. This changes the optimal angle, typically making it less than 45 degrees to avoid the distance from the point of projection decreasing on descent.
Sine Function in Projectile Motion
The sine function plays an essential role in understanding projectile motion, as it helps to determine the vertical component of a projectile's trajectory. It is a mathematical function that describes a smooth periodic oscillation and relates the angle of projection to the ratio of the projectile's opposite side over the hypotenuse in a right-angled triangle – in this context, the vertical height reached over the initial distance from the projection point.

In projectile motion, the sine of the angle of projection determines the vertical velocity component. As the sine value of an angle increases, so does the vertical component until it reaches its maximum at 90 degrees. But in projectile motion where the distance from the starting point must always increase, the pertinent range of the sine function is between 0 and 45 degrees. Beyond 45 degrees, the vertical velocity component begins to dominate, creating a trajectory that does not adhere to the problem constraint of increasing distance. Understanding how the sine function shapes the trajectory allows one to calculate the optimal angle of projection to meet specific conditions of projectile motion.

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Most popular questions from this chapter

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