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An airplane pilot wishes to fly due west. A wind of \(80.0 \mathrm{~km} / \mathrm{h}\) (about \(50 \mathrm{mi} / \mathrm{h}\) ) is blowing toward the south. (a) If the airspeed of the plane (its speed in still air) is \(320.0 \mathrm{~km} / \mathrm{h}\) (about \(200 \mathrm{mi} / \mathrm{h}),\) in which direction should the pilot head? (b) What is the speed of the plane over the ground? Draw a vector diagram.

Short Answer

Expert verified
The pilot should head at an angle equal to arctan\(\frac{-80.0}{320.0}\) + 360 degrees from the west in order to appropriately counteract the wind. The speed of the plane over the ground is \(\sqrt{(320.0)^2 + (-80.0)^2} \mathrm{km/h}\).

Step by step solution

01

Plane Speed Component

First, the plane's speed is considered. The plane is designed to fly due west, and its speed in still air is \(320.0 \mathrm{km/h}\). Therefore, in the absence of any wind, the plane would have a velocity component of \(320 \mathrm{km/h}\) every hour towards the west, set as the x-component of the velocity vector.
02

Wind Speed Component

Next, the wind's influence on the plane is taken into account. The wind is blowing south at a speed of \(80.0 \mathrm{km/h}\). This means the wind adds a velocity component in the southern direction, or downwards on a standard graph. This is set as the y-component of the velocity vector with a negative value because it is in the opposite direction, i.e., \(-80.0 \mathrm{km/h}\).
03

Calculation of Resultant Vector - Direction

Now that both vector components of the velocity (plane's speed and wind) are determined, the combined effect can be calculated. A vector's direction is given by the angle it makes with one of the axes. To find this angle \(\theta\), the tangent trigonometric function can be used. Tan \(\theta = \frac{opposite}{adjacent} = \frac{y-component}{x-component} = \frac{-80.0}{320.0}\). Calculating the arctan of this value gives the desired angle. However, because it is in the fourth quadrant, it is more accurate to add 360 degrees to the result.
04

Calculation of Resultant Vector - Magnitude

The magnitude of the resultant vector (which translates to the speed of the plane over the ground) is found using the Pythagorean theorem for right triangles. It states that the square of the hypotenuse (the resultant vector in this case) is equal to the sum of squares of the other two sides (the velocity components). Therefore, the magnitude \(R\) of the resultant vector is the square root of \((320.0)^2 + (-80.0)^2\).
05

Vector Diagram

Finally, to show all these relationships, a vector diagram is drawn. Put the vectors end to end and draw the resultant from the beginning of the first vector to the end of the second vector.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resultant Vector
In physics, finding the resultant vector is crucial when multiple forces or movements act in different directions. Imagine a scenario where two different vectors influence an object. For example, an airplane flying in the presence of wind will experience two velocity vectors: one from its own propulsion and another from the wind. The resultant vector would be the combination of these two vectors.

Here's how the process works:
  • Identify the vectors you must combine, such as the airplane's speed and the wind speed.
  • Break these vectors into components along the x (horizontal) and y (vertical) axes.
  • Add the components separately to find the resultant vector's components.
In the problem, the plane's speed is due west and the wind from the south creates an overall effect that needs to be resolved into a single vector. This is done geometrically using vector addition, often represented in a vector diagram, to see the overall effect on the object's movement.
Magnitude and Direction
When discussing vectors, two core properties are magnitude and direction. The magnitude gives the size or length of the vector and is often considered to be the 'speed' or 'force' if we're dealing with velocity vectors. The direction tells us where this magnitude is headed, like north, south, east, or west.

To find the magnitude of a resultant vector, apply the Pythagorean theorem if the vector components form a right triangle. Specifically, if the x-component and y-component are known, their squares can be added, and the square root of this sum will yield the magnitude:
\[ R = \sqrt{(x-component)^2 + (y-component)^2} \]
Direction is calculated using trigonometry, generally by finding the angle the vector makes with the horizontal. To find the direction, use:
\[ \theta = \arctan \left( \frac{y-component}{x-component} \right) \]
Correct placement on angle quadrants is essential in providing the actual bearing concerning cardinal directions, especially when the vector is in any other than the first quadrant.
Trigonometry in Physics
Trigonometry is an indispensable tool in physics, particularly when dealing with vector quantities such as velocity, force, and displacement. By understanding sine, cosine, and tangent, we can effectively break down complex problems into manageable parts. These functions allow us to resolve vectors into x and y components and to determine vital information such as angles and magnitudes.

Key trigonometric concepts include:
  • Sine and Cosine: These functions help determine the components of a vector, where the sine function typically relates to the opposite side and the cosine function relates to the adjacent side of a right triangle.
  • Tangent: The ratio of sine and cosine provides a method for finding angles. Utilized through the arctangent function, it reveals the angle a resultant vector makes with its axis.
  • Inverse Trigonometric Functions: Useful for calculating the angle of a vector given its components, particularly when determining its precise directional orientation.
In the case of an airplane navigating on a windy day, trigonometry is not just helpful—it's necessary. The pilot uses it to adjust the plane's direction to counteract wind influence and determine the resultant direction of travel.

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