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A solenoid is designed to produce a magnetic field of \(0.0270 \mathrm{~T}\) at its center. It has radius \(1.40 \mathrm{~cm}\) and length \(40.0 \mathrm{~cm},\) and the wire can carry a maximum current of 12.0 A. (a) What minimum number of turns per unit length must the solenoid have? (b) What total length of wire is required?

Short Answer

Expert verified
The minimum number of turns per unit length the solenoid must have is approximately \( 538605 \) turns per meter. The total length of wire required is approximately \( 150.77 \) meters.

Step by step solution

01

Calculate the number of turns per unit length

Firstly, we need to rearrange the formula for the magnetic field to solve for \( n = \frac{B}{\mu_0 * I} \). Here \( B = 0.0270 \mathrm{~T} \), \( \mu_0 = 4\pi * 10^{-7} \mathrm{Tm/A} \), and \( I = 12.0 \mathrm{A} \). By substituting these values into the rearranged formula, we find \( n = \frac{0.0270}{4\pi * 10^{-7} * 12.0} \) turns per meter.
02

Calculate the total length of wire

The total length of wire \( L \) equals the number of turns \( n \) times the circumference of the solenoid \( 2\pi r\), where \( r = 1.40 \mathrm{~cm} = 0.014 \mathrm{~m} \). So, \( L = n * 2\pi r \). Substituting for \( n \) from step 1, we find \( L = \frac{0.0270}{4\pi * 10^{-7} * 12.0} * 2\pi * 0.014 \) m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Strength
Understanding magnetic field strength is essential when dealing with electromagnetism. The magnetic field strength within a solenoid is a measure of the magnetizing force produced by an electric current flowing through the wire. This strength is directly proportional to the current, as well as the number of turns of wire per unit length of the solenoid. A key formula used to calculate this in a solenoid is given by: ewline ewline This mathematical representation elucidates that to achieve a desired magnetic field strength, one can adjust either the current through the wire or the density of the coil winding, measured in turns of wire per unit length. It is a pivotal concept for students to grasp, as it directly impacts the design and functionality of electromagnetic devices.
Turns Per Unit Length
The number of turns per unit length, often denoted by 'n', represents how tightly the wire is wound to form the solenoid. This density of turns is a critical parameter that has a direct impact on the magnetic field strength. The greater the number of turns per unit length, the stronger the magnetic field at the center of the solenoid, given a constant current. ewline ewline An increased number of turns per unit length indicates that more wire loops are packed into a given length, which enhances the magnetic field due to the additive effect of each loop's magnetic contribution. This concept underpins the calculations needed for designing a solenoid with particular magnetic properties and is essential for students to understand when determining the specifications for creating a strong magnetic field within a solenoid.
Solenoid Dimensions
The dimensions of a solenoid, which typically include its length and radius, play a vital role in determining its magnetic field strength and the amount of wire needed. The solenoid's length should be much greater than its radius to ensure a uniform magnetic field within its core, particularly near the center. ewline ewline A longer solenoid with a small radius maximizes the uniformity of the magnetic field inside. When calculating the total length of wire required to create a solenoid, dimensions are essential. The exercise demonstrates how the solenoid's circumference, which is derived from the radius, impacts the total wire length needed for winding. Students should appreciate how solenoid dimensions dictate both the physical construction and the resulting electromagnetic characteristics of the device.
Wire Current Capacity
Wire current capacity refers to the maximum electric current that a wire can safely carry without overheating and potentially causing damage or failure. This is a crucial safety and design consideration when creating a solenoid. ewline ewline The current passing through the solenoid's wire not only influences the magnetic field strength—as per the formula—but also must be maintained within the wire's tolerable limits. If a wire carries a current exceeding its capacity, it might lead to excessive heating, wire insulation damage, or even create a fire hazard. Hence, when solving for the solenoid design, as in the referenced problem, it is vital for students to understand that they must consider the wire's current capacity to ensure a safe and effective operating solenoid.

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Most popular questions from this chapter

A very long, straight horizontal wire carries a current such that \(8.20 \times 10^{18}\) electrons per second pass any given point going from west to east. What are the magnitude and direction of the magnetic field this wire produces at a point \(4.00 \mathrm{~cm}\) directly above it?

A long, straight wire with a circular cross section of radius \(R\) carries a current \(I\). Assume that the current density is not constant across the cross section of the wire, but rather varies as \(J=\alpha r,\) where \(\alpha\) is a constant. (a) \(\mathrm{By}\) the requirement that \(J\) integrated over the cross section of the wire gives the total current \(I,\) calculate the constant \(\alpha\) in terms of \(I\) and \(R .\) (b) Use Ampere's law to calculate the magnetic field \(B(r)\) for (i) \(r \leq R\) and (ii) \(r \geq R .\) Express your answers in terms of \(I\).

A closely wound, circular coil with radius \(2.40 \mathrm{~cm}\) has 800 turns. (a) What must the current in the coil be if the magnetic field at the center of the coil is \(0.0770 \mathrm{~T}\) ? (b) At what distance \(x\) from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center?

A \(+6.00 \mu\) C point charge is moving at a constant \(8.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) in the \(+y\) -direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic-field vector \(\overrightarrow{\boldsymbol{B}}\) it produces at the following points: (a) \(x=0.500 \mathrm{~m}, y=0, z=0\) (b) \(x=0, y=-0.500 \mathrm{~m}, z=0\) (c) \(x=0, \quad y=0, \quad z=+0.500 \mathrm{~m}\) (d) \(x=0, \quad y=-0.500 \mathrm{~m}\) \(z=+0.500 \mathrm{~m} ?\)

A wide, long, insulating belt has a uniform positive charge per unit area \(\sigma\) on its upper surface. Rollers at each end move the belt to the right at a constant speed \(v .\) Calculate the magnitude and direction of the magnetic field produced by the moving belt at a point just above its surface. (Hint: At points near the surface and far from its edges or ends, the moving belt can be considered to be an infinite current sheet like that in Problem \(28.69 .\)

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