/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 A closely wound, circular coil w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A closely wound, circular coil with radius \(2.40 \mathrm{~cm}\) has 800 turns. (a) What must the current in the coil be if the magnetic field at the center of the coil is \(0.0770 \mathrm{~T}\) ? (b) At what distance \(x\) from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center?

Short Answer

Expert verified
The current necessary in the coil is approximately 0.0402 A. The magnetic field is half of its center value at a distance about 2.72 cm from the center of the coil.

Step by step solution

01

Compute Current

The magnetic field at the center of current carrying coil is given by \(B = \frac{{\mu_0}}{2} * \frac{{NI}}{r}\), where \(\mu_0 = 4\pi * 10^{-7} T.m/A\) is the permeability of free space, \(N\) is the number of turns, \(I\) is the current and \(r\) is the radius. We are given \(B = 0.0770 T\), \(N = 800\) and \(r = 2.40 cm\). We can rearrange to find the current \(I\), thus \(I = \frac{{2Br}}{\mu_0N}.\)
02

Compute Distance

The magnetic field at a distance \(x\) along the central axis of a circular coil is given by \(B_x = \frac{{\mu_0}}{4\pi} * \frac{{2\pi NIA^2}}{(x^2 + A^2)^{3/2}}\), where \(A\) is the area of the circle and \(A = \pi r^2\). We also know from the problem that \(B_x = B/2\). Substituting the values and simplifying we get \(x = \sqrt{(8*A^2)-r^2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot-Savart Law
Understanding the Biot-Savart Law is fundamental for calculating the magnetic field produced by a steady current. This law relates the magnetic field \textbf{B} to the magnitude, direction, length, and proximity of the electric current. Essentially, it states that for a small segment of current-carrying wire, the magnetic field at a point in space is directly proportional to the current, inversely proportional to the square of the distance from the wire, and depends on the angle between the wire and the point in question.

The mathematical expression for Biot-Savart Law is \( dB = \frac{{\mu_0}}{{4\pi}} \frac{{Id\vec{s} \times \hat{r}}}{{r^2}} \) where \( Id\vec{s} \) is the vector representing the infinitesimal current element in both magnitude and direction, \( \hat{r} \) is the unit vector from the current element to the point of interest, \( r \) is the distance from the current element to the point, and \( \mu_0 \) is the permeability of free space.

This law provides the basis for the derivation of the magnetic field for various geometries, including a circular coil, as students must consider in this exercise.
Permeability of Free Space
The permeability of free space, denoted \( \mu_0 \), is a fundamental physical constant which characterizes the ability of a vacuum to support the formation of a magnetic field. Specifically, \( \mu_0 \) is the measure of the amount of resistance encountered when forming a magnetic field in a classical vacuum. The value of \( \mu_0 \) is approximately \( 4\pi \times 10^{-7} \) tesla meter per ampere (T·m/A).

The significance of \( \mu_0 \) is not only in its value but also in how it relates electric and magnetic field constants in the vacuum of space. In problems involving magnetic fields produced by currents, such as the magnetic field at a coil's center, it serves as a proportionality constant within the Biot-Savart Law and other electromagnetic equations.
Magnetic Field at Coil's Center
When dealing with the magnetic fields of coils, students need to pay particular attention to the field at the center of the coil, which is of interest in various practical applications, including electromagnets and induction coils. For a circular coil, the magnetic field at its center is given by a simplified version of the Biot-Savart Law.

The formula for the magnetic field at the center of a circular coil carrying a current \(I\) is given by:
\( B = \frac{{\mu_0}}{{2}} * \frac{{NI}}{{r}} \) where \(N\) is the number of turns, and \(r\) is the radius of the coil. The reliance on \(N\) and \(r\) indicates that the field strength is directly proportional to the current and number of turns, and inversely proportional to the coil's radius. Knowing this helps in understanding why, for instance, adding more turns to a coil or increasing the current leads to a stronger magnetic field at its center.
Circular Coil Current Calculation
In exercises such as the given problem, calculating the current in a circular coil involves rearranging the equation for the magnetic field at the coil's center to solve for the current \(I\). Using the given magnetic field \(B\), the number of turns \(N\), and the coil radius \(r\), we apply
\(I = \frac{{2Br}}{{\mu_0N}}\).

This formula indicates that the required current \(I\) is directly proportional to the desired magnetic field \(B\) and the radius of the coil \(r\), and inversely proportional to the permeability of free space \(\mu_0\) and the number of turns \(N\). Students can use this relationship to calculate the necessary current to produce a specific magnetic field at the center of a coil, which is a common exercise in both theoretical and practical contexts involving electromagnetism.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A closed curve encircles several conductors. The line integral \(\oint \overrightarrow{\boldsymbol{B}} \cdot d \overrightarrow{\boldsymbol{\imath}}\) around this curve is \(3.83 \times 10^{-4} \mathrm{~T} \cdot \mathrm{m} .\) (a) What is the net cur- rent in the conductors? (b) If you were to integrate around the curve in the opposite direction, what would be the value of the line integral? Explain.

The Magnetic Field from a Lightning Bolt. Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, straight wire. (a) If you were unfortunate enough to be \(5.0 \mathrm{~m}\) away from such a lightning bolt, how large a magnetic field would you experience? (b) How does this field compare to one you would experience by being \(5.0 \mathrm{~cm}\) from a long, straight household current of \(10 \mathrm{~A}\) ?

A long, straight wire carries a current of 8.60 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is \(4.50 \mathrm{~cm}\) from the wire and traveling at a speed of \(6.00 \times 10^{4} \mathrm{~m} / \mathrm{s}\) directly toward the wire, what are the magnitude and direction (relative to the direction of the current) of the force that the magnetic field of the current exerts on the electron?

An electron is moving in the vicinity of a long, straight wire that lies along the \(x\) -axis. The wire has a constant current of 9.00 A in the \(-x\) -direction. At an instant when the electron is at point \((0,0.200 \mathrm{~m}, 0)\) and the electron's velocity is \(\overrightarrow{\boldsymbol{v}}=\left(5.00 \times 10^{4} \mathrm{~m} / \mathrm{s}\right) \hat{\imath}-\left(3.00 \times 10^{4} \mathrm{~m} / \mathrm{s}\right) \hat{\jmath},\) what is the force that the wire exerts on the electron? Express the force in terms of unit vectors, and calculate its magnitude.

Two concentric circular loops of wire lie on a tabletop, one inside the other. The inner wire has a diameter of \(20.0 \mathrm{~cm}\) and carries a clockwise current of \(12.0 \mathrm{~A}\), as viewed from above, and the outer wire has a diameter of \(30.0 \mathrm{~cm} .\) What must be the magnitude and direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.