/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 A coil with magnetic moment \(1.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A coil with magnetic moment \(1.45 \mathrm{~A} \cdot \mathrm{m}^{2}\) is oriented initially with its magnetic moment antiparallel to a uniform 0.835 T magnetic field. What is the change in potential energy of the coil when it is rotated \(180^{\circ}\) so that its magnetic moment is parallel to the field?

Short Answer

Expert verified
The change in potential energy of the coil when it is rotated 180 degrees is -2.42 J.

Step by step solution

01

Compute Initial Potential Energy

Calculate the initial potential energy when the magnetic moment is antiparallel to the magnetic field using the formula for potential energy in a magnetic field, \(-\mathbf{M} \cdot \mathbf{B}\). Here, \(M = 1.45 \mathrm{~A} \cdot \mathrm{m}^{2}\) and \(B = 0.835 \mathrm{~T}\), hence the potential energy is \(-1.45 \mathrm{~A} \cdot \mathrm{m}^{2} \times -0.835 \mathrm{~T} = 1.21 \mathrm{~J}\).
02

Compute Final Potential Energy

Calculate the final potential energy when the magnetic moment is parallel to the magnetic field. The magnetic field direction is in line with magnetic moment. Therefore, \(M = 1.45 \mathrm{~A} \cdot \mathrm{m}^{2}\) and \(B = 0.835 \mathrm{~T}\), the potential energy is \(-1.45 \mathrm{~A} \cdot \mathrm{m}^{2} \times 0.835 \mathrm{~T} = -1.21 \mathrm{~J}\).
03

Change in Potential Energy

Finally, calculate the change in potential energy, which is the difference between the final and initial potential energy. Therefore, \(-1.21 \mathrm{~J} - 1.21 \mathrm{~J} = -2.42 \mathrm{~J}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Moment
The magnetic moment is a vector quantity that represents the magnetic strength and orientation of a magnet or other object that produces a magnetic field. Specifically, it's the torque that a magnetic object experiences in the presence of an external magnetic field. Imagine holding a compass; the needle, when freely suspended, aligns with Earth's magnetic field because it has a magnetic moment.

In our exercise, the coil's magnetic moment of \(1.45 \text{ A} \text{ m}^2\) tells us about its magnetic 'power' and which way it points. When it is antiparallel to the magnetic field, it's like the compass needle pointing south while Earth's field points north; it's in a high-energy state, storing potential energy that can be released if the coil is allowed to flip. This flipping to a parallel state with the field would then take the system to a lower energy state.
Uniform Magnetic Field
A uniform magnetic field is constant in magnitude and direction at all points in the area it covers. Such consistency is ideal for examining basic magnetic interactions without the complexity of varying field strength or direction. Take a flashlight beam shining evenly on a wall as an analogy; it illuminates the surface uniformly, just as a uniform magnetic field 'covers' an area consistently in terms of magnetic influence.

In our example, the coil is within a uniform 0.835 T (Tesla) magnetic field, offering us a stable environment to analyze how the coil's potential energy changes when its magnetic moment flips direction. Understanding how objects behave in uniform fields is often helpful before moving to non-uniform, more complex fields.
Potential Energy Calculation
Potential energy represents stored energy, which can be calculated in different contexts like gravity, spring systems, and, as in our case, magnetic systems. For a magnet in a uniform magnetic field, potential energy depends on the strength of both the magnetic moment and the field, and their relative orientations.

We calculate it using the formula \(-\textbf{M} \times \textbf{B}\), where \(M\) is the magnetic moment, and \(B\) is the magnetic field. The negative sign indicates that the lowest potential energy (most stable state) occurs when \(M\) and \(B\) are in the same direction. When we compute changes in this energy, we assess the system's energetic 'journey' from one configuration to another, as seen in the exercise when flipping the coil affects its energy by \(-2.42 \text{ J}\). Understanding this change helps us predict how the system might behave dynamically under different conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A small particle with positive charge \(q=+3.75 \times 10^{-4} \mathrm{C}\) and mass \(m=5.00 \times 10^{-5} \mathrm{~kg}\) is moving in a region of uniform electric and magnetic fields. The magnetic field is \(B=4.00 \mathrm{~T}\) in the \(+z\) -direction. The electric field is also in the \(+z\) -direction and has magnitude \(E=60.0 \mathrm{~N} / \mathrm{C}\). At time \(t=0\) the particle is on the \(y\) -axis at \(y=+1.00 \mathrm{~m}\) and has velocity \(v=30.0 \mathrm{~m} / \mathrm{s}\) in the \(+x\) -direction. Neglect gravity. (a) What are the \(x\) -, \(y\) and \(z\) -coordinates of the particle at \(t=0.0200 \mathrm{~s} ?\) (b) What is the speed of the particle at \(t=0.0200 \mathrm{~s} ?\)

In a 1.25 T magnetic field directed vertically upward, a particle having a charge of magnitude \(8.50 \mu \mathrm{C}\) and initially moving northward at \(4.75 \mathrm{~km} / \mathrm{s}\) is deflected toward the east. (a) What is the sign of the charge of this particle? Make a sketch to illustrate how you found your answer. (b) Find the magnetic force on the particle.

A straight, vertical wire carries a current of 2.60 A down- ward in a region between the poles of a large superconducting electromagnet, where the magnetic field has magnitude \(B=0.588 \mathrm{~T}\) and is horizontal. What are the magnitude and direction of the magnetic force on a \(1.00 \mathrm{~cm}\) section of the wire that is in this uniform magnetic field, if the magnetic field direction is (a) east; (b) south; (c) \(30.0^{\circ}\) south of west?

An alpha particle (a He nucleus, containing two protons and two neutrons and having a mass of \(6.64 \times 10^{-27} \mathrm{~kg}\) ) traveling horizontally at \(35.6 \mathrm{~km} / \mathrm{s}\) enters a uniform, vertical, \(1.80 \mathrm{~T}\) magnetic field. (a) What is the diameter of the path followed by this alpha particle? (b) What effect does the magnetic field have on the speed of the particle? (c) What are the magnitude and direction of the acceleration of the alpha particle while it is in the magnetic field? (d) Explain why the speed of the particle does not change even though an unbalanced external force acts on it.

An electron traveling from the sun as part of the solar wind strikes the earth's magnetosphere at latitude \(80.0^{\circ} \mathrm{N}\) in a region where the magnetic field has a strength of \(15.0 \mu \mathrm{T}\) and is directed toward the earth's center. The electron has a speed of \(400 \mathrm{~km} / \mathrm{s}\) and is directed toward the earth's axis parallel to the equator. Magnetic forces send the electron on a helical trajectory. (a) What is the radius of this helix? (b) With what speed does the electron approach the surface of the earth? (c) If you are looking downward toward the earth from space, is the electron's motion clockwise or counterclockwise? (d) What is the frequency of the motion? (e) This electron strikes the ionosphere, where it is further accelerated by an electric field with strength \(20.0 \mathrm{mV} / \mathrm{m}\) directed northward parallel to the earth's surface. What is the electron's new speed after it has been deflected \(100 \mathrm{~km}\) southward by this field? (f) By what factor has its kinetic energy been increased by the electric field?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.