/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 The voltage drop \(V_{a b}\) acr... [FREE SOLUTION] | 91Ó°ÊÓ

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The voltage drop \(V_{a b}\) across each of resistors \(A\) and \(B\) was measured as a function of the current \(I\) in the resistor. The results are shown in the table: $$ \begin{array}{l|llll} \text { Resistor } A & & & & \\ I(\mathrm{~A}) & 0.50 & 1.00 & 2.00 & 4.00 \\ V_{a b}(\mathrm{~V}) & 2.55 & 3.11 & 3.77 & 4.58 \\ & & & & \\ \begin{array}{l} \text { Resistor } B \\ I(\mathrm{~A}) \end{array} & 0.50 & 1.00 & 2.00 & 4.00 \\ V_{a b}(\mathrm{~V}) & 1.94 & 3.88 & 7.76 & 15.52 \end{array} $$ (a) For each resistor, graph \(V_{a b}\) as a function of \(I\) and graph the resistance \(R=V_{a b} / I\) as a function of \(I\). (b) Does resistor \(A\) obey Ohm's law? Explain. (c) Does resistor \(B\) obey Ohm's law? Explain. (d) What is the power dissipated in \(A\) if it is connected to a \(4.00 \mathrm{~V}\) battery that has negligible internal resistance? (e) What is the power dissipated in \(B\) if it is connected to the battery?

Short Answer

Expert verified
A visual examination of the graphs for both resistors will show whether each obeys Ohm's law. Calculations for the power dissipated in each, using Ohm's law, will provide the answers to parts (d) and (e).

Step by step solution

01

Create a graph of \(V_{ab}\) as a function of \(I\)

Plot the current \(I\) on the x-axis and the voltage drop \(V_{ab}\) on the y-axis for both resistor A and resistor B.
02

Create a graph of \(R\) as a function of \(I\)

Calculate the resistance \(R = V_{ab}/I\) for each current value given in the table, then plot this resistance against the current \(I\).
03

Determine if resistor A obeys Ohm's Law

Ohm's law states that the voltage across a resistor is directly proportional to the current through it, which means the graph of \(V_{ab}\) against \(I\) should be a straight line. Analyze the graph created in step 1 to determine whether resistor A obeys Ohm's law.
04

Determine if resistor B obeys Ohm's Law

Similarly, analyze the graph for resistor B to determine whether it obeys Ohm's law.
05

Calculate the power dissipated in A

The power \(P\) dissipated in a resistor is given by \(P=V_{ab}I\). In this case, as we are given a voltage of 4V and can use the value of current at 4V from the table, we can calculate the power dissipated in resistor A.
06

Calculate the power dissipated in B

Repeat the calculation from step 5 for resistor B to find its power dissipation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Voltage Drop
Voltage drop refers to the reduction in voltage as electrical current flows through a component, like a resistor, in a circuit. It is an essential aspect when analyzing circuits because it can affect the functionality of the entire system. Using Ohm’s Law, the voltage drop can be calculated using the formula \( V_{ab} = I imes R \), where \( V_{ab} \) is the voltage drop, \( I \) is the current flowing through the circuit, and \( R \) is the resistance of the resistor.

When current flows through a resistor, energy is converted into heat, leading to a drop in voltage. Understanding this helps in designing circuits that operate efficiently under specific voltages. In practical scenarios, we measure the voltage across each component to ensure each device in a circuit receives the correct voltage to function properly.

In our exercise, the voltage drop across resistors \( A \) and \( B \) changes with different levels of current \( I \). Plotting \( V_{ab} \) against \( I \) gives a visual representation of these changes, helping to determine whether the resistors adhere to Ohm’s Law.
Resistance Calculation
Resistance is a measure of how much a resistor opposes the flow of electrical current. It can be calculated using Ohm's Law, by rearranging the basic formula to \( R = \frac{V_{ab}}{I} \). This formula tells us that resistance is the ratio of voltage drop across a resistor to the current flowing through it.

Understanding resistance helps in calculating and analyzing how devices in a circuit will perform. Knowing the resistance values also assists in selecting appropriate resistors for different components, ensuring that the circuit operates within safe limits.

In our exercise, calculating resistance for different current values helps determine if resistors \( A \) and \( B \) are behaving as expected. If the resistance remains constant as the current changes, the resistor is said to obey Ohm's Law. Through graphs plotted in the exercise, this behavior can be visually analyzed.
Power Dissipation
Power dissipation in a resistor refers to the process of electrical energy being converted into heat as current passes through the resistor. It is calculated using the formula \( P = V_{ab} \times I \).

Understanding power dissipation is vital for designing circuits that avoid overheating and maintain energy efficiency. Excessive power dissipation can lead to damage or failure of components, so precisely calculating the power a resistor can safely handle is crucial in circuit design.

In the given exercise, the power dissipated in resistors \( A \) and \( B \) is calculated by using a 4V power source. By using the current values given for this voltage, the power can be determined for each resistor. This provides insights into how much energy is being lost as heat in the system, a critical factor in evaluating a circuit's overall performance.

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Most popular questions from this chapter

A copper wire has a square cross \(2.3 \mathrm{~mm}\) on a side. The wire is \(4.0 \mathrm{~m}\) long and carries a current of \(3.6 \mathrm{~A}\). The density of free electrons is \(8.5 \times 10^{28} / \mathrm{m}^{3} .\) Find the magnitudes of (a) the current density in the wire and (b) the electric field in the wire. (c) How much time is required for an electron to travel the length of the wire?

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A 5.00 A current runs through a 12 gauge copper wire (diameter \(2.05 \mathrm{~mm}\) ) and through a light bulb. Copper has \(8.5 \times 10^{28}\) free electrons per cubic meter. (a) How many electrons pass through the light bulb each second? (b) What is the current density in the wire? (c) At what speed does a typical electron pass by any given point in the wire? (d) If you were to use wire of twice the diameter, which of the above answers would change? Would they increase or decrease?

The region between two concentric conducting spheres with radii \(a\) and \(b\) is filled with a conducting material with resistivity \(\rho\). (a) Show that the resistance between the spheres is given by $$ R=\frac{\rho}{4 \pi}\left(\frac{1}{a}-\frac{1}{b}\right) $$ (b) Derive an expression for the current density as a function of radius, in terms of the potential difference \(V_{a b}\) between the spheres. (c) Show that the result in part (a) reduces to Eq. (25.10) when the separation \(L=b-a\) between the spheres is small.

A long, thin solenoid has 400 turns per meter and radius \(1.10 \mathrm{~cm} \). The current in the solenoid is increasing at a uniform rate \(d i / d t\). The induced electric field at a point near the center of the solenoid and \(3.50 \mathrm{~cm}\) from its axis is \(8.00 \times 10^{-6} \mathrm{~V} / \mathrm{m} .\) Calculate \(d i / d t\)

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