/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 A dielectric of permittivity \(3... [FREE SOLUTION] | 91Ó°ÊÓ

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A dielectric of permittivity \(3.5 \times 10^{-11} \mathrm{~F} / \mathrm{m}\) completely fills the volume between two capacitor plates. For \(t>0\) the electric flux through the dielectric is \(\left(8.0 \times 10^{3} \mathrm{~V} \cdot \mathrm{m} / \mathrm{s}^{3}\right) t^{3} .\) The dielectric is ideal and nonmagnetic; the conduction current in the dielectric is zero. At what time does the displacement current in the dielectric equal \(21 \mu \mathrm{A} ?\)

Short Answer

Expert verified
The displacement current in the dielectric equals 21 µA at t = 0.7 s.

Step by step solution

01

Understand the displacement current

Displacement current is a concept in electromagnetism where a varying electric field gives rise to a form of current despite the absence of free charges. It is represented by the equation \(I_d = \epsilon \frac{d\Phi_E}{dt}\), where \(I_d\) is the displacement current, \(\epsilon\) is the permittivity of the material, and \(\frac{d\Phi_E}{dt}\) is the rate of change of the electric flux.
02

Relate given values to the equation

From the problem, we know the value of displacement current \(I_d = 21 \mu A\), permittivity of the dielectric \(\epsilon = 3.5 \times 10^{-11} F/m\), and the electric flux as a function of time \(\Phi_E = (8.0 \times 10^{3} V \cdot m/s^{3}) t^{3}\). All these values can be substituted into the equation of the displacement current.
03

Substitute the values and solve for time

On substituting these values into the equation \(I_d = \epsilon \frac{d\Phi_E}{dt}\), we have \(21 \times 10^{-6} A = 3.5 \times 10^{-11} F/m \times \frac{d}{dt}(8.0 \times 10^{3} V \cdot m/s^{3} t^{3})\). Solving this equation, the derivative of the flux with respect to time is \(\frac{d\Phi_E}{dt} = 24,000 t^{2}\). Substituting back into the equation, we will have \(21 \times 10^{-6} A = 3.5 \times 10^{-11} F/m \times 24,000 t^{2}\). Solving for \(t\), we get \(t = 0.7s\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permittivity
Permittivity is a fundamental property of materials that quantifies their ability to permit electric field lines to pass through them. More formally, it is a measure of the electric susceptibility of a dielectric material. The permittivity of a material is represented by the symbol \( \epsilon \) and is expressed in the units of farads per meter (F/m). In the context of capacitors, the permittivity of the dielectric material between the plates determines the capacitance of the capacitor, the amount of electric charge it can store for a given electric potential.
In the given exercise, the dielectric has a permittivity of \( 3.5 \times 10^{-11} \rm{{F/m}} \) which indicates its capacity to store electric energy. The higher the permittivity, the more electric flux the material can support, leading to a higher capacitance. Students often struggle to visualize permittivity but can think of it as a measure of how 'dense' the electric field can be within a material.
Electric Flux
Electric flux is a key term in electromagnetism that represents the number of electric field lines passing through a given area. Think of it as a measure of the 'flow' of the electric field through a surface. It's often denoted by \( \Phi_E \) and influences many aspects of electromagnetic phenomena, such as the generation of electric fields around charged objects.
In our exercise, the electric flux varies with time according to the function \( \Phi_E = (8.0 \times 10^{3} \rm{V} \cdot \rm{m/s^{3}}) t^{3} \), with \( t \) being the time. The cubic relationship with time indicates that the electric flux – and thus the strength of the electric field – increases rapidly as time progresses. Visualizing electric flux can be challenging for students; one can imagine it as the number of field lines 'flowing' through a virtual surface, which changes over time in this particular scenario.
Electromagnetism
Electromagnetism is one of the four fundamental forces that govern the universe and it encompasses the interaction between electrically charged particles. Within this field of study, we explore concepts such as electric fields, magnetic fields, and their interdependence. Displacement current, introduced by James Clerk Maxwell, is a cornerstone concept in electromagnetism that allows us to understand how changing electric fields can create magnetic fields, even without the physical movement of charge that constitutes a traditional electric current.

Understanding Displacement Current

The exercise presents a practical application of displacement current, which occurs within the dielectric of a capacitor. Even in the absence of free charge movement, the displacement current is a manifestation of a time-varying electric field within the dielectric, critical for electromagnetic wave propagation. Clear comprehension of this concept helps bridge one's understanding between electricity and magnetism in electromagnetic waves and is essential for grasping advanced topics in physics and engineering.
Capacitor Dielectric
The capacitor dielectric is the insulating material placed between the plates of a capacitor. Its primary role is to increase the capacitor's ability to store electrical energy. This is accomplished by reducing the electric field within the capacitor, which allows the capacitor to hold more charge at a given voltage, thereby increasing its capacitance. The effectiveness of a dielectric material is determined by its permittivity, as discussed earlier.

Role in Electric Fields

A dielectric material in a capacitor polarizes when exposed to an electric field, decreasing the field's strength inside the material compared to a vacuum. This polarization effect increases the capacitor's charge storage capacity without requiring additional voltage. For students, understanding dielectrics can be facilitated by looking at how these materials influence the behavior of capacitors and the efficiency of energy storage. In real-world applications, dielectrics are crucial not only for capacitors but also for a wide range of electronic components, where they improve performance, stability, and energy efficiency.

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Most popular questions from this chapter

When a resistor with resistance \(R\) is connected to a \(1.50 \mathrm{~V}\) flashlight battery, the resistor consumes \(0.0625 \mathrm{~W}\) of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a \(12.6 \mathrm{~V}\) car battery? Assume that \(R\) remains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes \(5.00 \mathrm{~W}\). What is the voltage of this battery?

A motor vehicle generates electrical power using an alternator, which employs electromagnetic induction to convert mechanical energy to electrical energy. The alternator acts as a dc generator (Example 29.4 ). The alternator maintains and replenishes charge on the car's battery and operates headlights, radiator fans, windshield wipers, power windows, computer systems, sensors, sound systems, and other components. (a) A typical car battery provides 70 amp-hours of charge. How many coulombs is that? (b) If headlights each draw 20 A of current, a radiator fan draws \(10 \mathrm{~A},\) and windshield wipers each draw \(5 \mathrm{~A},\) estimate the peak current needed for a car to operate on a rainy night. (c) A car's alternator supplies an average emf of \(14 \mathrm{~V}\) as emf induced in a sequence of stator coils in the presence of a magnetic field created by rotor coil electromagnets turned by a pulley system. A stator coil may have 42 windings and a cross-sectional diameter of \(5.0 \mathrm{~cm},\) and it rotates at \(400 \mathrm{~Hz}\). Estimate the strength of the magnetic field generated by a rotor coil.

A material with resistivity \(\rho\) is formed into a cylinder of length \(L\) and outer radius \(r_{\text {outer }}\). A cylindrical core with radius \(r_{\text {inner }}\) is removed from the axis of this cylinder and filled with a conducting material, which is attached to a wire. The outer surface of the cylinder is coated with a conducting material and attached to another wire. (a) If the second wire has potential \(V\) greater than the first wire, in what direction does the local electric field point inside of the cylinder? (b) The magnitude of this electric field is \(c / r,\) where \(c\) is a constant and \(r\) is the distance from the axis of the cylinder. Use the relationship \(V=\int \overrightarrow{\boldsymbol{E}} \cdot d \overrightarrow{\boldsymbol{l}}\) to determine the constant \(c .(\mathrm{c})\) What is the resistance of this device? (d) A \(1.00-\mathrm{cm}\) -long hollow cylindrical resistor has an inner radius of \(1.50 \mathrm{~mm}\) and an outer radius of \(3.00 \mathrm{~mm} .\) The material is a blend of powdered carbon and ceramic whose resistivity \(\rho\) may be altered by changing the amount of carbon. If this device should have a resistance of \(6.80 \mathrm{k} \Omega,\) what value of \(\rho\) should be selected?

The free-electron density in a copper wire is \(8.5 \times 10^{28}\) electrons \(/ \mathrm{m}^{3} .\) The electric field in the wire is \(0.0600 \mathrm{~N} / \mathrm{C}\) and the temperature of the wire is \(20.0^{\circ} \mathrm{C}\). (a) What is the drift speed \(v_{\mathrm{d}}\) of the electrons in the wire? (b) What is the potential difference between two points in the wire that are separated by \(20.0 \mathrm{~cm} ?\)

A small, closely wound coil has \(N\) turns, area \(A\), and resistance \(R\). The coil is initially in a uniform magnetic field that has magnitude \(B\) and a direction perpendicular to the plane of the loop. The coil is then rapidly pulled out of the field so that the flux through the coil is reduced to zero in time \(\Delta t\). (a) What are the magnitude of the average \(\operatorname{emf} \mathcal{E}_{\text {av }}\) and average current \(I_{\mathrm{av}}\) induced in the coil? (b) The total charge \(Q\) that flows through the coil is given by \(Q=I_{\mathrm{av}} \Delta t .\) Derive an expression for \(Q\) in terms of \(N, A, B,\) and \(R .\) Note that \(Q\) does not depend on \(\Delta t .\) (c) What is \(Q\) if \(N=150\) turns, \(A=4.50 \mathrm{~cm}^{2}, R=30.0 \Omega,\) and \(B=0.200 \mathrm{~T} ?\)

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