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\(\mathrm{CP}\) BIO Struck by Lightning. Lightning strikes can involve currents as high as 25,000 A that last for about \(40 \mu \mathrm{s}\). If a person is struck by a bolt of lightning with these properties, the current will pass through his body. We shall assume that his mass is \(75 \mathrm{~kg}\), that he is wet (after all, he is in a rainstorm) and therefore has a resistance of \(1.0 \mathrm{k} \Omega\), and that his body is all water (which is reasonable for a rough, but plausible, approximation). (a) By how many degrees Celsius would this lightning bolt increase the temperature of \(75 \mathrm{~kg}\) of water? (b) Given that the internal body temperature is about \(37^{\circ} \mathrm{C}\), would the person's temperature actually increase that much? Why not? What would happen first?

Short Answer

Expert verified
The lightning strike would theoretically increase the temperature of the body by a very large amount, but in reality, this is not feasible. The heat will dissipate quickly throughout the body and the environment, and the person's cells would likely fail before reaching such high temperatures.

Step by step solution

01

Calculate the amount of heat generated

First, use Joule's law to calculate the heat generated by the lightning strike. Substitute the given current \(I = 25,000 A\), resistance \(R = 1.0 k \Omega = 1000 \Omega\) and time duration \(t = 40 \mu s = 40 \times 10^{-6} s\) into the equation \(Q=I^{2}Rt\)
02

Convert the heat into temperature change

The specific heat capacity of water is \(4.18 \times 10^{3} J/kg°C\). Use this value to convert the heat generated into a temperature change. Substitute the given mass \(m = 75 kg\), the heat generated Q, and the specific heat capacity \(c = 4.18 \times 10^{3} J/kg°C\) into the equation \(Q = mc \Delta T\). Solve for \(\Delta T\) which represents the change in temperature of the water
03

Analyze the feasible temperature rise

Even though the temperature increase calculated is very high, it does not mean that the person's temperature would increase by that much. Firstly, heat transfer within the body happens very quickly, reducing the time for the entire body to heat up. Secondly, some of the current could travel externally, or be deflected away by clothing, further reducing the actual heating. Finally, if a person's temperature rises too high too quickly, damage or death of body cells will occur before reaching the calculated temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joule's law
Joule's law describes how electricity can turn into heat during its passage through a conductor, which in this case is the human body. When electrical current flows, it experiences resistance. This leads to heat being generated. The law is mathematically represented by the formula \( Q = I^{2}Rt \). Here:
  • \( Q \) is the heat energy produced, measured in Joules.
  • \( I \) is the current flowing through the conductor, measured in Amperes.
  • \( R \) is the resistance in the path of the current, measured in Ohms.
  • \( t \) is the time duration for which the current flows, measured in seconds.
In the example of a lightning strike, the body acts as a conductor with a specific resistance. As a result, when the lightning strikes, a large amount of heat is generated in a very short time due to the high current of 25,000 A passing through the body with given resistance. This concept is crucial to understanding the thermal effects of electrical current on conductors, in this case, a human body.
specific heat capacity
Specific heat capacity is a property of a substance that describes how much heat energy is required to change its temperature. It's usually denoted by \( c \), with units of Joules per kilogram per degree Celsius (\( J/kg°C \)).For water, the specific heat capacity is quite high at \( 4.18 \times 10^{3} \ J/kg°C \). This means water absorbs a lot of heat before its temperature increases significantly. Hence, it's used as a reference in many thermal calculations.In the context of the lightning strike problem, knowing the specific heat capacity of water is essential as it helps us calculate how much the temperature of the water-like body mass will rise when a specific amount of heat is transferred to it. The formula for this calculation is \( \Delta T = \frac{Q}{mc} \), where:
  • \( \Delta T \) is the change in temperature.
  • \( Q \) is the heat energy subjected to the mass, in Joules.
  • \( m \) represents the mass of the water, in kilograms.
Without knowing the specific heat capacity, we would not be able to predict the temperature change resulting from the energy transferred by the lightning strike.
heat transfer
Heat transfer is the process where heat energy moves from one substance, object, or region to another. It can occur through conduction, convection, or radiation. In the case of a lightning strike, heat transfer primarily occurs through conduction and the body's distribution of heat. When the heat is generated by a lightning strike, it does not stay confined to the point of contact. Instead, it spreads throughout the body. This is crucial for minimizing localized damage by "diluting" the heat, potentially saving the body from more severe burns. Moreover, rapid heat transfer in a body ensures that, while there might be an immediate increase in temperature at the point of strike, this heat is quickly spread out, reducing the intensity at any single point. However, even if the person were to survive the initial strike, the rapid heat can lead to severe internal damage and burns, reflecting why the temperature might not rise as expected.
resistance in wet conditions
Resistance is a measure of how much a material opposes the flow of electrical current. For humans, resistance varies based on conditions. In dry conditions, the body's resistance is relatively high. However, in wet conditions, such as in rain, the resistance decreases significantly.When wet, the outer layer of the skin becomes highly conductive, leading to potentially dangerous scenarios during events, like lightning strikes. In the provided exercise, the resistance is set at \( 1.0 \ k\Omega \), a typical assumption for a wet body.Lower resistance means that a greater portion of the current can flow through the body, as per Ohm's Law and Joule’s law, leading to more heat being produced internally. This significantly heightens the risk during a lightning strike, as more heat can mean more severe thermal injuries. Understanding resistance is key to assessing the possible outcomes and damage from such extreme electrical exposure.

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