/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 A fuel gauge uses a capacitor to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A fuel gauge uses a capacitor to determine the height of the fuel in a tank. The effective dielectric con- stant \(K_{\text {eff }}\) changes from a value of 1 when the tank is empty to a value of \(K\), the dielectric constant of the fuel, when the tank is full. The appropriate electronic circuitry can determine the effective dielectric constant of the combined air and fuel between the capacitor plates. Each of the two rectangular plates has a width \(w\) and a length \(L\) (Fig. \(\mathbf{P 2 4 . 6 6}\) ). The height of the fuel between the plates is \(h\). You can ignore any fringing effects. (a) Derive an expression for \(K_{\text {eff }}\) as a function of \(h\). (b) What is the effective dielectric constant for a tank \(\frac{1}{4}\) full, \(\frac{1}{2}\) full, and \(\frac{3}{4}\) full if the fuel is gasoline \((K=1.95) ?\) (c) Repeat part (b) for methanol \((K=33.0)\). (d) For which fuel is this fuel gauge more practical?

Short Answer

Expert verified
The short answer will depend on the calculations made in Steps 2 and 3, and the comparison made in Step 4.

Step by step solution

01

Derive expression for \(K_{\text {eff }}\)

Let the distance between the plates be \(d\). The effective dielectric constant \(K_{\text {eff }}\) can be derived by considering the capacitor as two capacitors in series, one filled with air and the other with fuel. The dielectric constant of air is 1, and the height of the air part is \(d-h\). The dielectric constant of fuel is \(K\) and the height is \(h\). The total capacitance of the capacitor would be \(C_{total}=(\varepsilon_{0}wL/(d-h\))\(C_{2}=\varepsilon_{0}KwL/h\), where \(C_{1}\) and \(C_{2}\) are the capacitances of the air and fuel parts respectively. The total capacitance when two capacitors are in series is given by \(1/C_{total}=1/C_{1}+1/C_{2}\). Solve this equation for \(K_{\text {eff }}=\varepsilon_{0}K_{eff}wL/d\), where \(K_{eff}\) is the effective dielectric constant.
02

Calculate \(K_{\text {eff }}\) for different fuel heights

To find \(K_{\text {eff }}\) for a tank \(\frac{1}{4}\) full, \(\frac{1}{2}\) full, and \(\frac{3}{4}\) full for gasoline, substitute the corresponding \(h\) values and \(K = 1.95\) into the expression derived in Step 1 and calculate \(K_{\text {eff }}\) respectively.
03

Repeat calculations for methanol

Repeat the calculations in Step 2, but this time using \(K = 33.0\), the dielectric constant for methanol.
04

Determine the more practical fuel

The fuel gauge will be more practical for the type of fuel that leads to larger changes in the effective dielectric constant for changes in fuel height. Compare the results from Steps 2 and 3 to make this determination.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dielectric Constant
The dielectric constant is a measure of a material's ability to store charge and affects how capacitors behave when different substances are between the plates. In this problem, the dielectric constant varies based on the fuel level in a tank, impacting the capacitance measurement used by a fuel gauge.
When a tank is empty, the dielectric constant of air, which is 1, dominates. As fuel fills the tank, the dielectric constant increases to the value characteristic of the fuel used. For gasoline, the constant is 1.95 and for methanol, it's 33.0. The effective dielectric constant, denoted as \(K_{\text{eff}}\), changes between these values as the fuel level changes.
  • If the tank is full, \(K_{\text{eff}}\) equals the dielectric constant of the fuel.
  • When the tank is empty, \(K_{\text{eff}}\) is 1, as only air is between the capacitor plates.
  • For intermediate levels, \(K_{\text{eff}}\) can be calculated by considering the tank as comprising two series capacitors—one with air and the other with fuel.
Understanding how \(K_{\text{eff}}\) changes helps engineers design more accurate fuel gauges.
Fuel Gauge Mechanics
Fuel gauges often utilize capacitors, which change capacitance based on the material between their plates. This feature is employed in determining the fuel level in a tank. Here's how it works:
First, the capacitor plates are installed in the fuel tank. As the fuel level changes, the material between the plates changes from air to fuel, significantly affecting capacitance.
It's important to accurately establish the effective dielectric constant at different fuel levels. This helps electronic circuits measure fuel height based on the changing capacitance. By detecting changes in \(K_{\text{eff}}\), the fuel gauge can effectively calculate the fuel level, whether the tank is 1/4, 1/2, or 3/4 full.
  • For instance, when the fuel is gasoline, the gauge must measure changes from 1 to 1.95.
  • For methanol, this range is more substantial, from 1 to 33.0.
This technique allows for precise fuel level readings by considering the different dielectric constant values between air and fuel.
Capacitor Design
Capacitor design is critical in developing a reliable fuel gauge that can measure fuel levels accurately. The design considers multiple factors to optimize the capacitor's performance in a fuel gauge.
The main challenge is to handle capacitors" changes in capacitance as they operate with a combination of air and fuel. The approach involves treating the setup as two separate capacitors in series. Here's a simplified process:
  • Design plates considering the tank's dimensions, such as width \(w\) and length \(L\).
  • Calculate \(K_{\text{eff}}\) using the derivation of effective capacitance when combining air-filled and fuel-filled capacitors.
  • Ensure the design allows accurate measurements regardless of fuel level.
The goal is to create a system sensitive enough to distinguish small changes in \(K_{\text{eff}}\). Thus, a tank that is partially filled tweaks the capacitor composition, adjusting the fuel gauge's reading. Understanding the design principles allows for choosing the correct plate size and spacing, improving accuracy, and providing a reliable fuel measurement system.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(20.0 \mu \mathrm{F}\) capacitor is charged to a potential difference of \(800 \mathrm{~V}\). The terminals of the charged capacitor are then connected to those of an uncharged \(10.0 \mu \mathrm{F}\) capacitor. Compute (a) the original charge of the system, (b) the final potential difference across each capacitor, (c) the final energy of the system, and (d) the decrease in energy when the capacitors are connected.

A cylindrical capacitor consists of a solid inner conducting core with radius \(0.250 \mathrm{~cm}\), surrounded by an outer hollow conducting tube. The two conductors are separated by air, and the length of the cylinder is \(12.0 \mathrm{~cm}\). The capacitance is \(36.7 \mathrm{pF}\). (a) Calculate the inner radius of the hollow tube. (b) When the capacitor is charged to \(125 \mathrm{~V},\) what is the charge per unit length \(\lambda\) on the capacitor?

BIO Cell Membranes. Cell membranes (the walled enclosure around a cell) are typically about \(7.5 \mathrm{nm}\) thick. They are partially permeable to allow charged material to pass in and out, as needed. Equal but opposite charge densities build up on the inside and outside faces of such a membrane, and these charges prevent additional charges from passing through the cell wall. We can model a cell membrane as a parallel-plate capacitor, with the membrane itself containing proteins embedded in an organic material to give the membrane a dielectric constant of about \(10 .\) (See Fig. \(\mathbf{P 2 4 . 4 8}\).) (a) What is the capacitance per square centimeter of such a cell wall? (b) In its normal resting state, a cell has a potential difference of \(85 \mathrm{mV}\) across its membrane. What is the electric field inside this membrane?

A \(10.0 \mu \mathrm{F}\) parallel-plate capacitor with circular plates is connected to a \(12.0 \mathrm{~V}\) battery. (a) What is the charge on each plate? (b) How much charge would be on the plates if their separation were doubled while the capacitor remained connected to the battery? (c) How much charge would be on the plates if the capacitor were connected to the \(12.0 \mathrm{~V}\) battery after the radius of each plate was doubled without changing their separation?

\- A parallel-plate vacuum capacitor has \(8.38 \mathrm{~J}\) of energy stored in it. The separation between the plates is \(2.30 \mathrm{~mm}\). If the separation is decreased to \(1.15 \mathrm{~mm},\) what is the energy stored (a) if the capacitor is disconnected from the potential source so the charge on the plates remains constant, and (b) if the capacitor remains connected to the potential source so the potential difference between the plates remains constant?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.