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Two identical air-filled parallel-plate capacitors \(C_{1}\) and \(C_{2}\), each with capacitance \(C,\) are connected in series to a battery that has voltage \(V\). While the two capacitors remain connected to the battery, a dielectric with dielectric constant \(K>1\) is inserted between the plates of one of the capacitors, completely filling the space between them. Let \(U_{0}\) be the total energy stored in the two capacitors without the dielectric and \(U\) be the total energy stored after the dielectric is inserted. In terms of \(K,\) what is the ratio \(U / U_{0} ?\) Does the total stored energy increase, decrease, or stay the same after the dielectric is inserted?

Short Answer

Expert verified
The ratio of the energy stored (after the insertion of the dielectric to that before) is \(2K / (K+1)\). Since \(K > 1\), \(U / U_{0}\) is less than 2, meaning the total energy stored decreases with the insertion of the dielectric.

Step by step solution

01

Understand the Capacitors in Series

When capacitors are connected in series, their total capacitance \(C_{total}\) can be found out using the formula: \[1 / C_{total} = 1 / C_{1} + 1 / C_{2}\]. In this case, since both capacitors are identical, \[ 1 / C_{total} = 1 / C + 1 / C = 2 / C\]. So, \(C_{total} = C / 2\].
02

Finding Energy without Dielectric

The energy stored in a capacitor can be calculated with the formula: \(U = (1/2)*C*V^{2}\). In this case, substituting \(C_{total}\) and \(V\) into the formula gives: \(U_{0} = (1/2)*(C / 2)* V^{2}\).
03

Finding New Capacitance with Dielectric

When a dielectric is inserted, the new capacitance for \(C_{1}\) becomes \(K*C\) (This is because capacitance of a capacitor increases K times when a dielectric is inserted). But \(C_{2}\) remains untouched. Now, our total capacitance, \(C'_{total}\) would be found from: \[ 1 / C'_{total} = 1 / (K*C) + 1 / C = (K+1) / (K*C)\]. Simplifying this equation, we get \(C'_{total} = K*C / (K+1)\).
04

Finding Energy with Dielectric

Again we can substitute \(C'_{total}\) into the original energy stored formula: \(U = (1/2)*C'_{total}* V^{2}\). Substituting gives us: \(U = (1/2)*[K*C / (K+1)]* V^{2}\).
05

Finding the ratio of energies

We find the ratio of energies \(U / U_{0}\) by dividing \(U\) by \(U_{0}\). Using the values from step 2 and step 4, the \(V^{2}\) and \(1/2\) terms cancel out and we are left with: \(U / U_{0} = (K*C / (K+1)) / (C / 2)\). Simplifying this yields: \(U / U_{0} = 2K / (K+1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dielectric Constant
The dielectric constant is an essential concept in understanding how materials affect electrical forces. When we place a dielectric material between the plates of a capacitor, it enhances the capacitor's ability to store electric charge. This is because dielectrics reduce the effective electric field between the capacitor plates.
The dielectric constant, often denoted by the symbol "K," measures a material's insulating ability compared to a vacuum. For example:
  • If the dielectric constant of a material is 5, the capacitance will increase by a factor of 5 when this material fills the space between the plates of a capacitor.
  • An increased dielectric constant leads to greater energy storage within the capacitor.
Understanding this concept helps in designing capacitors for various electronic devices, where maximizing energy storage is often crucial.
Energy Stored in Capacitors
The energy stored in a capacitor is an important aspect of their function. Capacitors store energy in the form of an electric field between their plates. The formula to calculate the energy, \(U\), stored in a capacitor is: \[ U = \frac{1}{2} C V^2 \] where \(C\) is the capacitance and \(V\) is the voltage across the capacitor.
This equation tells us a few key facts about energy storage in capacitors:
  • The energy stored is directly proportional to the capacitance. Therefore, anything that increases the capacitance, like inserting a dielectric, will increase the stored energy.
  • The energy is also proportional to the square of the voltage, showing that even small increases in voltage can significantly increase energy storage.
The presence of a dielectric modifies this energy storage by effectively increasing the capacitance while keeping the voltage the same, thus affecting the total energy stored.
Capacitance Calculations
Capacitance calculations are critical when determining how capacitors behave, especially when configurations such as series or parallel combinations are considered. For capacitors in series, the total capacitance, \(C_{total}\), is calculated using the formula: \[ \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} \ldots \]
In our example of two identical capacitors in series, this simplifies to \(C_{total} = \frac{C}{2}\). When a dielectric is inserted into one capacitor, it changes the capacitance of that individual component but impacts the whole series setup. The new calculation becomes: \[ \frac{1}{C'_{total}} = \frac{1}{KC} + \frac{1}{C} \] leading to a new effective capacitance \( C'_{total} = \frac{KC}{K+1} \).
Understanding these calculations is essential for designing circuits, as it allows engineers to predict how combinations of components will affect the circuit's overall performance.

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Most popular questions from this chapter

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is \(10.0 \mathrm{pC}\). The inner cylinder has radius \(0.50 \mathrm{~mm},\) the outer one has radius \(5.00 \mathrm{~mm},\) and the length of each cylinder is \(18.0 \mathrm{~cm} .\) (a) What is the capacitance? (b) What applied potential difference is necessary to produce these charges on the cylinders?

BIO Potential in Human Cells. Some cell walls in the human body have a layer of negative charge on the inside surface and a layer of positive charge of equal magnitude on the outside surface. Suppose that the charge density on either surface is \(\pm 0.50 \times 10^{-3} \mathrm{C} / \mathrm{m}^{2},\) the cell wall is \(5.0 \mathrm{nm}\) thick, and the cell-wall material is air. (a) Find the magnitude of \(\vec{E}\) in the wall between the two layers of charge. (b) Find the potential difference between the inside and the outside of the cell. Which is at the higher potential? (c) A typical cell in the human body has a volume of \(10^{-16} \mathrm{~m}^{3}\). Estimate the total electric- field energy stored in the wall of a cell of this size. (Hint: Assume that the cell is spherical, and calculate the volume of the cell wall.) (d) In reality, the cell wall is made up, not of air, but of tissue with a dielectric constant of 5.4 . Repeat parts (a) and (b) in this case.

A \(5.00 \mu \mathrm{F}\) parallel-plate capacitor is connected to a \(12.0 \mathrm{~V}\) battery. After the capacitor is fully charged, the battery is disconnected without loss of any of the charge on the plates. (a) A voltmeter is connected across the two plates without discharging them. What does it read? (b) What would the voltmeter read if (i) the plate separation were doubled; (ii) the radius of each plate were doubled but their separation was unchanged?

A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius \(12.5 \mathrm{~cm},\) and the outer sphere has radius \(14.8 \mathrm{~cm} .\) A potential difference of \(120 \mathrm{~V}\) is applied to the capacitor. (a) What is the energy density at \(r=12.6 \mathrm{~cm}\), just outside the inner sphere? (b) What is the energy density at \(r=14.7 \mathrm{~cm},\) just inside the outer sphere? (c) For a parallel-plate capacitor the energy density is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?

BIO Cell Membranes. Cell membranes (the walled enclosure around a cell) are typically about \(7.5 \mathrm{nm}\) thick. They are partially permeable to allow charged material to pass in and out, as needed. Equal but opposite charge densities build up on the inside and outside faces of such a membrane, and these charges prevent additional charges from passing through the cell wall. We can model a cell membrane as a parallel-plate capacitor, with the membrane itself containing proteins embedded in an organic material to give the membrane a dielectric constant of about \(10 .\) (See Fig. \(\mathbf{P 2 4 . 4 8}\).) (a) What is the capacitance per square centimeter of such a cell wall? (b) In its normal resting state, a cell has a potential difference of \(85 \mathrm{mV}\) across its membrane. What is the electric field inside this membrane?

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