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The electric field at the surface of a charged, solid, copper sphere with radius \(0.200 \mathrm{~m}\) is \(3800 \mathrm{~N} / \mathrm{C}\), directed toward the center of the sphere. What is the potential at the center of the sphere, if we take the potential to be zero infinitely far from the sphere?

Short Answer

Expert verified
The potential at the center of the sphere is -76.2 V.

Step by step solution

01

Identify given quantities

We have a solid, charged, copper sphere with a radius of \(0.200 \ m\) and an electric field at its surface of \(3800 \ N/C\), which is directed towards the sphere's center. The electric potential infinitively far from the sphere is taken to be zero.
02

Use Coulomb's Law to compute the charge

Coulomb's law for the electric field \(E\) of a charged sphere is given as \(E = k_e \frac{Q}{r^2}\) where \(k_e\) is the electrostatic constant, \(Q\) is the charge on the sphere, and \(r\) is the radius of the sphere. The electric field is directed towards the sphere, which indicates a negative charge. Solving for \(Q\), we find \(Q = E \cdot r^2 / k_e = 3800 \cdot (0.2)^2 / (8.99 \times 10^9) = -1.689 \times 10^{-9} \ C\).
03

Calculate the potential at the center

The electric potential \(V\) at a point located at distance \(r\) from a point charge \(Q\) is given by \(V = k_e \frac{Q}{r}\). Since we want to find the potential at the center of the sphere, \(r\) is equal to the radius of the sphere. Replacing \(r\) with the radius of the sphere and \(Q\) with the charge obtained earlier, we get \(V = k_e \frac{Q}{r} = 8.99 \times 10^9 \cdot (\frac{-1.689 \times 10^{-9}}{0.2}) = -76.2 \ V\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a fundamental principle that helps us understand how electric charges interact with each other. It describes the force between two stationary, point charges. According to Coulomb's Law, the electric force (F) between two charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. This can be mathematically expressed as:\[F = k_e \frac{|Q_1Q_2|}{r^2}\]where:
  • \(F\) is the force between the charges,
  • \(Q_1\) and \(Q_2\) are the magnitudes of the charges,
  • \(r\) is the distance between the charges,
  • \(k_e\) is the electrostatic constant, approximately equal to \(8.99 \times 10^9 \, \text{N}·\text{m}^2/\text{C}^2\) .

In the context of a charged sphere, Coulomb's Law can be slightly modified since the sphere effectively behaves as a point charge at its center when calculating forces and fields at distances greater than or equal to its radius. This principle helps derive other properties, like the electric field, associated with the charged sphere.
Charged Sphere
A charged sphere, particularly when considered a solid metal sphere like copper, distributes charge uniformly across its surface. Inside a conductor, such as metal, the electric field is zero, and all excess charge resides on the surface.
The electric field (E) at the surface of a charged sphere can be determined using a form of Coulomb's Law. It follows:\[E = k_e \frac{Q}{r^2}\]Here:
  • \(E\) is the electric field on the surface,
  • \(Q\) is the total charge on the sphere,
  • \(r\) is the radius of the sphere.

In this exercise, the electric field was given as \(3800 \, \text{N/C}\), directed inward, indicating a negatively charged sphere. The surface's electric field tells us about how the sphere's charge interacts with the space around it. Since our example assumes potential to be zero at infinity, the calculated electric potential at any point can give insight into the energy required to move a charge to that point through the sphere’s electric field.
Electric Field
The electric field is a vector field around a charged object where each point in the space has a vector associated with it that points in the direction that a positive test charge would move if placed at that point. The magnitude of the electric field tells us the force that a charge of \(1 \, \text{C}\) would experience at each point.
The formula for the electric field \(E\) around a point charge \(Q\) is given as:\[E = k_e \frac{Q}{r^2}\]
  • \(E\) represents the electric field,
  • \(k_e\) is the electrostatic constant,
  • \(Q\) is the point charge,
  • \(r\) is the distance from the charge.

For a charged sphere, such an electric field will be strong and directed towards or away from the sphere depending on the charge’s sign. In this problem, since the field is toward the center, it suggests a negative surface charge. Understanding the electric field is essential for computing the behavior of charges around the sphere, and ultimately, determining the potential at different points within and around the sphere.

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Most popular questions from this chapter

A small sphere with mass \(5.00 \times 10^{-7} \mathrm{~kg}\) and charge \(+7.00 \mu \mathrm{C}\) is released from rest a distance of \(0.400 \mathrm{~m}\) above a large horizontal insulating sheet of charge that has uniform surface charge density \(\sigma=+8.00 \mathrm{pC} / \mathrm{m}^{2} .\) Using energy methods, calculate the speed of the sphere when it is \(0.100 \mathrm{~m}\) above the sheet.

Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by \(45.0 \mathrm{~mm}\), and the potential difference between them is \(360 \mathrm{~V}\). (a) What is the magnitude of the electric field (assumed to be uniform) in the region between the plates? (b) What is the magnitude of the force this field exerts on a particle with charge \(+2.40 \mathrm{nC} ?\) (c) Use the results of part (b) to compute the work done by the field on the particle as it moves from the higher-potential plate to the lower. (d) Compare the result of part (c) to the change of potential energy of the same charge, computed from the electric potential.

For a particular experiment, helium ions are to be given a kinetic energy of \(3.0 \mathrm{MeV}\). What should the voltage at the center of the accelerator be, assuming that the ions start essentially at rest? (a) \(-3.0 \mathrm{MV}\) (b) \(+3.0 \mathrm{MV} ;(\mathrm{c})+1.5 \mathrm{MV} ;(\mathrm{d})+1.0 \mathrm{MV}\)

(a) How much excess charge must be placed on a copper sphere \(25.0 \mathrm{~cm}\) in diameter so that the potential of its center is \(3.75 \mathrm{kV} ?\) Take the point where \(V=0\) to be infinitely far from the sphere, (b) What is the potential of the sphere's surface?

Point charges \(q_{1}=+2.00 \mu \mathrm{C}\) and \(q_{2}=-2.00 \mu \mathrm{C}\) are placed at adjacent corners of a square for which the length of each side is \(3.00 \mathrm{~cm}\). Point \(a\) is at the center of the square, and point \(b\) is at the empty corner closest to \(q_{2}\). Take the electric potential to be zero at a distance far from both charges. (a) What is the electric potential at point \(a\) due to \(q_{1}\) and \(q_{2} ?\) (b) What is the electric potential at point \(b ?\) (c) A point charge \(q_{3}=-5.00 \mu \mathrm{C}\) moves from point \(a\) to point \(b .\) How much work is done on \(q_{3}\) by the electric forces exerted by \(q_{1}\) and \(q_{2} ?\) Is this work positive or negative?

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