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An infinitely long line of charge has linear charge density \(5.00 \times 10^{-12} \mathrm{C} / \mathrm{m} .\) A proton (mass \(1.67 \times 10^{-27} \mathrm{~kg},\) charge \(+1.60 \times 10^{-19} \mathrm{C}\) ) is \(18.0 \mathrm{~cm}\) from the line and moving directly toward the line at \(3.50 \times 10^{3} \mathrm{~m} / \mathrm{s}\). (a) Calculate the proton's initial kinetic energy. (b) How close does the proton get to the line of charge?

Short Answer

Expert verified
The solution includes finding the initial kinetic energy of the proton and then setting it equal to the energy due to the scalar electric potential of the line charge to find at which distance the proton will stop moving towards the line. The exact values will depend on the calculations in each step.

Step by step solution

01

Calculate Initial kinetic energy

The initial kinetic energy \(E_{K_{initial}}\) of a proton can be calculated with the formula: \(E_{K_{initial}}=\frac{1}{2} m v^2\), where \(m=1.67 \times 10^{-27} kg\) is the proton mass and \(v=3.50 \times 10^{3} m/s\) is the velocity.
02

Calculate Energy due to line charge

The energy produced by the scalar electric potential of the line charge at a distance r from the line is given by \(E_{V}=k |\lambda| ln(r)\), where \(k=9.0 \times 10^9 Nm^2/C^2\) is Coulomb's constant, |\(\lambda\)|\(=5.00 \times 10^{-12} C/m\) is the linear charge density, r is the distance from the line charge, and ln denotes the natural logarithm.
03

Equate and Solve

Now equate \(E_{V}\) to \(E_{K_{initial}}\) and solve for r to find how close the proton gets to the line. So, \(k |\lambda| ln(r) = \frac{1}{2} m v^2\). Then, resolve for r.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Charge Density
Linear charge density is a measure of the amount of electric charge per unit length along a line. It is represented by the symbol \( \lambda \), and in SI units, it is expressed in coulombs per meter (C/m). This concept is particularly important when dealing with infinitely long lines of charge, a common element in theoretical physics problems to simplify the calculation of electric fields and potentials.

Imagine a uniformly charged thread or wire, extending in both directions farther than we can measure. The linear charge density tells us how 'concentrated' the charge is at any point along that line. An infinitely long line of charge with a constant linear charge density creates an electric field and potential that can affect nearby charges or particles, such as protons, as stated in the exercise. Understanding the linear charge density allows us to calculate these electric field strengths and potentials.
Kinetic Energy of a Proton
The kinetic energy of a proton, or any particle, represents the energy it possesses due to its motion. It can be calculated using the formula \( E_{K} = \frac{1}{2} m v^2 \), where \( m \) is the mass of the proton and \( v \) is its velocity. In our exercise, a proton is moving with a specific velocity towards a line of charge, and this movement entails kinetic energy.

For a proton, which is a subatomic particle found within atomic nuclei, kinetic energy is particularly noteworthy in the study of nuclear and particle physics. Its kinetic energy plays a critical role in understanding phenomena like particle collisions and can be significant in the context of electric potentials and fields, as the proton interacts with charged objects, such as the infinitely long line of charge in the given problem.
Coulomb's Law
Coulomb's law is a fundamental principle that describes the electrostatic interaction between electrically charged particles. It states that the force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. The law's formula is expressed as \( F = k \frac{|q_1 q_2|}{r^2} \), where \( F \) is the electrostatic force, \( q_1 \) and \( q_2 \) are the quantities of the charges, \( r \) is the distance between the center of the two charges, and \( k \) is Coulomb's constant \( (k = 9.0 \times 10^9 \, Nm^2/C^2) \).

Coulomb's law is pivotal for understanding the forces that charged particles exert on each other. It not only explains the interactions at a distance but also serves as the basis for deriving electric field intensity and potential due to any distribution of static charges.
Electric Potential of a Line Charge
The electric potential of a line charge is the potential energy per unit charge at a point in space due to the presence of the line charge. For an infinitely long line charge with a constant linear charge density, the electric potential \( V \) at a distance \( r \) from the line is given by the formula \( V = \frac{k \lambda}{2\pi} \ln(\frac{r}{r_0}) \), where \( k \) is Coulomb's constant, \( \lambda \) is the linear charge density, and \( r_0 \) is a reference distance from the line charge.

In our exercise, to find how close a moving proton can get to an infinitely long line charge, we use the relationship between the proton's initial kinetic energy and the electric potential of the line charge. By equating the initial kinetic energy of the proton to the scalar electric potential energy due to the line charge, we can solve for \( r \), the closest distance the proton will reach before being stopped by the electrostatic force.

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Most popular questions from this chapter

An annulus with an inner radius of \(a\) and an outer radius of \(b\) has charge density \(\sigma\) and lies in the \(x y\) -plane with its center at the origin, as shown in Fig. \(\mathbf{P} 2 \mathbf{3 . 8 0}\). (a) Using the convention that the potential vanishes at infinity, determine the potential at all points on the \(z\) -axis. (b) Determine the electric field at all points on the \(z\) -axis by differentiating the potential. (c) Show that in the limit \(a \rightarrow 0, b \rightarrow \infty\) the electric field reproduces the result obtained in Example 22.7 for an infinite plane sheet of charge. (d) If \(a=5.00 \mathrm{~cm}, b=10.0 \mathrm{~cm}\) and the total charge on the annulus is \(1.00 \mu \mathrm{C}\), what is the potential at the origin? (e) If a particle with mass \(1.00 \mathrm{~g}\) (much less than the mass of the annulus) and charge \(1.00 \mu \mathrm{C}\) is placed at the origin and given the slightest nudge, it will be projected along the \(z\) -axis. In this case, what will be its ultimate speed?

At a certain distance from a point charge, the potential and electric-field magnitude due to that charge are \(4.98 \mathrm{~V}\) and \(16.2 \mathrm{~V} / \mathrm{m}\) respectively. (Take \(V=0\) at infinity.) (a) What is the distance to the point charge? (b) What is the magnitude of the charge? (c) Is the electric field directed toward or away from the noint charge?

A thin spherical shell with radius \(R_{1}=3.00 \mathrm{~cm}\) is concentric with a larger thin spherical shell with radius \(R_{2}=5.00 \mathrm{~cm}\). Both shells are made of insulating material. The smaller shell has charge \(q_{1}=+6.00 \mathrm{nC}\) distributed uniformly over its surface, and the larger shell has charge \(q_{2}=-9.00 \mathrm{nC}\) distributed uniformly over its surface. Take the electric potential to be zero at an infinite distance from both shells. (a) What is the electric potential due to the two shells at the fol- (ii) \(r=4.00 \mathrm{~cm}\) lowing distance from their common center: (i) \(r=0\) (iii) \(r=6.00 \mathrm{~cm} ?\) (b) What is the magnitude of the potential difference between the surfaces of the two shells? Which shell is at higher potential: the inner shell or the outer shell?

A solid conducting sphere of radius \(5.00 \mathrm{~cm}\) carries a net charge. To find the value of the charge, you measure the potential difference \(V_{A B}=V_{A}-V_{B}\) between point \(A,\) which is \(8.00 \mathrm{~cm}\) from the center of the sphere, and point \(B\), which is a distance \(r\) from the center of the sphere. You repeat these measurements for several values of \(r>8.00 \mathrm{~cm} .\) When you plot your data as \(V_{A B}\) versus \(1 / r,\) the values lie close to a straight line with slope \(-18.0 \mathrm{~V} \cdot \mathrm{m}\). What does your data give for the net charge on the sphere? Is the net charge positive or negative?

Points \(A\) and \(B\) lie within a region of space where there is a uniform electric field that has no \(x\) - or \(z\) -component; only the \(y\) -component \(E_{y}\) is nonzero. Point \(A\) is at \(y=8.00 \mathrm{~cm}\) and point \(B\) is at \(y=15.0 \mathrm{~cm} .\) The potential difference between \(B\) and \(A\) is \(V_{B}-V_{A}=+12.0 \mathrm{~V},\) so point \(B\) is at higher potential than point \(A\). (a) Is \(E_{y}\) positive or negative? (b) What is the magnitude of the electric field? (c) Point \(C\) has coordinates \(x=5.00 \mathrm{~cm}, y=5.00 \mathrm{~cm} .\) What is the potential difference between points \(B\) and \(C ?\)

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