/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 An infinitely long line of charg... [FREE SOLUTION] | 91Ó°ÊÓ

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An infinitely long line of charge has linear charge density \(5.00 \times 10^{-12} \mathrm{C} / \mathrm{m} .\) A proton (mass \(1.67 \times 10^{-27} \mathrm{~kg},\) charge \(+1.60 \times 10^{-19} \mathrm{C}\) ) is \(18.0 \mathrm{~cm}\) from the line and moving directly toward the line at \(3.50 \times 10^{3} \mathrm{~m} / \mathrm{s}\). (a) Calculate the proton's initial kinetic energy. (b) How close does the proton get to the line of charge?

Short Answer

Expert verified
The solution includes finding the initial kinetic energy of the proton and then setting it equal to the energy due to the scalar electric potential of the line charge to find at which distance the proton will stop moving towards the line. The exact values will depend on the calculations in each step.

Step by step solution

01

Calculate Initial kinetic energy

The initial kinetic energy \(E_{K_{initial}}\) of a proton can be calculated with the formula: \(E_{K_{initial}}=\frac{1}{2} m v^2\), where \(m=1.67 \times 10^{-27} kg\) is the proton mass and \(v=3.50 \times 10^{3} m/s\) is the velocity.
02

Calculate Energy due to line charge

The energy produced by the scalar electric potential of the line charge at a distance r from the line is given by \(E_{V}=k |\lambda| ln(r)\), where \(k=9.0 \times 10^9 Nm^2/C^2\) is Coulomb's constant, |\(\lambda\)|\(=5.00 \times 10^{-12} C/m\) is the linear charge density, r is the distance from the line charge, and ln denotes the natural logarithm.
03

Equate and Solve

Now equate \(E_{V}\) to \(E_{K_{initial}}\) and solve for r to find how close the proton gets to the line. So, \(k |\lambda| ln(r) = \frac{1}{2} m v^2\). Then, resolve for r.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Charge Density
Linear charge density is a measure of the amount of electric charge per unit length along a line. It is represented by the symbol \( \lambda \), and in SI units, it is expressed in coulombs per meter (C/m). This concept is particularly important when dealing with infinitely long lines of charge, a common element in theoretical physics problems to simplify the calculation of electric fields and potentials.

Imagine a uniformly charged thread or wire, extending in both directions farther than we can measure. The linear charge density tells us how 'concentrated' the charge is at any point along that line. An infinitely long line of charge with a constant linear charge density creates an electric field and potential that can affect nearby charges or particles, such as protons, as stated in the exercise. Understanding the linear charge density allows us to calculate these electric field strengths and potentials.
Kinetic Energy of a Proton
The kinetic energy of a proton, or any particle, represents the energy it possesses due to its motion. It can be calculated using the formula \( E_{K} = \frac{1}{2} m v^2 \), where \( m \) is the mass of the proton and \( v \) is its velocity. In our exercise, a proton is moving with a specific velocity towards a line of charge, and this movement entails kinetic energy.

For a proton, which is a subatomic particle found within atomic nuclei, kinetic energy is particularly noteworthy in the study of nuclear and particle physics. Its kinetic energy plays a critical role in understanding phenomena like particle collisions and can be significant in the context of electric potentials and fields, as the proton interacts with charged objects, such as the infinitely long line of charge in the given problem.
Coulomb's Law
Coulomb's law is a fundamental principle that describes the electrostatic interaction between electrically charged particles. It states that the force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. The law's formula is expressed as \( F = k \frac{|q_1 q_2|}{r^2} \), where \( F \) is the electrostatic force, \( q_1 \) and \( q_2 \) are the quantities of the charges, \( r \) is the distance between the center of the two charges, and \( k \) is Coulomb's constant \( (k = 9.0 \times 10^9 \, Nm^2/C^2) \).

Coulomb's law is pivotal for understanding the forces that charged particles exert on each other. It not only explains the interactions at a distance but also serves as the basis for deriving electric field intensity and potential due to any distribution of static charges.
Electric Potential of a Line Charge
The electric potential of a line charge is the potential energy per unit charge at a point in space due to the presence of the line charge. For an infinitely long line charge with a constant linear charge density, the electric potential \( V \) at a distance \( r \) from the line is given by the formula \( V = \frac{k \lambda}{2\pi} \ln(\frac{r}{r_0}) \), where \( k \) is Coulomb's constant, \( \lambda \) is the linear charge density, and \( r_0 \) is a reference distance from the line charge.

In our exercise, to find how close a moving proton can get to an infinitely long line charge, we use the relationship between the proton's initial kinetic energy and the electric potential of the line charge. By equating the initial kinetic energy of the proton to the scalar electric potential energy due to the line charge, we can solve for \( r \), the closest distance the proton will reach before being stopped by the electrostatic force.

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Most popular questions from this chapter

A particle with charge \(+4.20 \mathrm{nC}\) is in a uniform electric field \(\vec{E}\) directed to the left. The charge is released from rest and moves to the left; after it has moved \(6.00 \mathrm{~cm},\) its kinetic energy is \(+2.20 \times 10^{-6} \mathrm{~J}\). What are (a) the work done by the electric force, (b) the potential of the starting point with respect to the end point, and (c) the magnitude of \(\overrightarrow{\boldsymbol{E}}\) ?

A very long insulating cylinder of charge of radius \(2.50 \mathrm{~cm}\) carries a uniform linear density of \(15.0 \mathrm{nC} / \mathrm{m}\). If you put one probe of a voltmeter at the surface, how far from the surface must the other probe be placed so that the voltmeter reads \(175 \mathrm{~V} ?\)

A very long uniform line of charge with charge per unit length \(\lambda=+5.00 \mu \mathrm{C} / \mathrm{m}\) lies along the \(x\) -axis, with its midpoint at the origin. A very large uniform sheet of charge is parallel to the \(x y\) -plane; the center of the sheet is at \(z=+0.600 \mathrm{~m}\). The sheet has charge per unit area \(\sigma=+8.00 \mu \mathrm{C} / \mathrm{m}^{2}\), and the center of the sheet is at \(x=0\). \(y=0 .\) Point \(A\) is on the \(z\) -axis at \(z=+0.300 \mathrm{~m}\), and point \(B\) is on the \(z\) -axis at \(z=-0.200 \mathrm{~m}\). What is the potential difference \(V_{A B}=V_{A}-V_{B}\) between points \(A\) and \(B ?\) Which point, \(A\) or \(B,\) is at higher potential?

At a certain distance from a point charge, the potential and electric-field magnitude due to that charge are \(4.98 \mathrm{~V}\) and \(16.2 \mathrm{~V} / \mathrm{m}\) respectively. (Take \(V=0\) at infinity.) (a) What is the distance to the point charge? (b) What is the magnitude of the charge? (c) Is the electric field directed toward or away from the noint charge?

Charge \(Q=5.00 \mu \mathrm{C}\) is distributed uniformly over the volume of an insulating sphere that has radius \(R=12.0 \mathrm{~cm} .\) A small sphere with charge \(q=+3.00 \mu \mathrm{C}\) and mass \(6.00 \times 10^{-5} \mathrm{~kg}\) is projected toward the center of the large sphere from an initial large distance. The large sphere is held at a fixed position and the small sphere can be treated as a point charge. What minimum speed must the small sphere have in order to come within \(8.00 \mathrm{~cm}\) of the surface of the large sphere?

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