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Points \(A\) and \(B\) lie within a region of space where there is a uniform electric field that has no \(x\) - or \(z\) -component; only the \(y\) -component \(E_{y}\) is nonzero. Point \(A\) is at \(y=8.00 \mathrm{~cm}\) and point \(B\) is at \(y=15.0 \mathrm{~cm} .\) The potential difference between \(B\) and \(A\) is \(V_{B}-V_{A}=+12.0 \mathrm{~V},\) so point \(B\) is at higher potential than point \(A\). (a) Is \(E_{y}\) positive or negative? (b) What is the magnitude of the electric field? (c) Point \(C\) has coordinates \(x=5.00 \mathrm{~cm}, y=5.00 \mathrm{~cm} .\) What is the potential difference between points \(B\) and \(C ?\)

Short Answer

Expert verified
a) The \(y\) -component of the electric field \(E_{y}\) is positive.\nb) The magnitude of the electric field is \(171 \, V/m.\)\nc) The potential difference between points \(B\) and \(C\) is \(-17.1 \, V.\)

Step by step solution

01

Find the Direction of the Electric Field

A positive potential difference means moving in the direction of the electric field. Since \(B\) is at a higher potential than \(A\), and \(B\) is greater than \(A\) in the \(y\) -direction, this means that the electric field \(E_{y}\) is positive.
02

Find the Magnitude of the Electric Field

The magnitude of the electric field \(E_{y}\) can be found using the equation \( \Delta V = -E\Delta y \), where \( \Delta V = V_B - V_A \) and \( \Delta y = y_B - y_A \). Solving this equation gives \( E_y= -\Delta V/\Delta y = -(V_B - V_A)/(y_B - y_A) = -(+12.0 V)/(15.0 cm - 8.00 cm) = -1.71 V/cm = -171 V/m.\) However, since we found that \(E_{y}\) is positive, the magnitude of the electric field is \(171 \, V/m.\)
03

Calculate the Potential Difference between Points \(B\) and \(C\)

Finally, the potential difference \( \Delta V_{BC} = V_B -V_C \) can be found using the equation \(\Delta V = -E \Delta y\), where \(\Delta y = y_B - y_C\). Substituting the known values gives \(\Delta V_{BC} = -(E_{y})(y_B - y_C) = -171 V/m (15.0 cm - 5.00 cm) = -1.71 V/cm (10.0 cm) = -17.1 V.\) Therefore, the potential difference between points \(B\) and \(C\) is \(-17.1 \, V.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Difference
The potential difference, often referred to as voltage, is a fundamental concept in the field of electricity. It tells us about the energy difference per unit charge between two points in an electric field. Think of it as the electrical 'pressure' that motivates electrons to move from one point to another.

A positive potential difference, as mentioned in the given problem, indicates that one point (point B in this case) is at a higher potential energy than another point (point A). This acts as a motivating 'force' for electrons to move towards the lower potential point when a conductive path is provided. In a battery, for example, the potential difference between the terminals drives the current through a circuit.

One way to visualize potential difference is by thinking about a hill. If point B is at the top of the hill and point A is at the bottom, the ball (representing a charge) will naturally roll down from higher to lower elevation, which is similar to how electrons move from higher to lower electrical potential.
Uniform Electric Field
A uniform electric field is characterized by electric field vectors that have the same magnitude and direction at every point within the field. This makes the field predictable and easy to calculate, much like the effect of gravity near the Earth's surface is considered uniform for practical purposes.

In the context of the exercise, the electric field only has a component along the y-axis, meaning it is uniform in the vertical direction with respect to the problem's coordinate system. A uniform electric field is typically created between two parallel plates with a voltage across them, such as in a parallel-plate capacitor. If you were to place test charges in a uniform electric field, each charge would experience the same force regardless of its position in the field.

Mathematically, the uniformity of the field provides us with the convenience of being able to exclude the shape of the path taken by a charge between two points when calculating work done, making potential difference calculations more straightforward.
Magnitude of Electric Field
The magnitude of an electric field represents the force experienced by a positive test charge placed within the field, per unit of charge. It's measured in volts per meter (V/m) or, equivalently, in newtons per coulomb (N/C).

The magnitude of the electric field within a region tells us how strong or intense the field is. Higher magnitudes mean a greater force on charges in the field. In the given exercise, determining the magnitude of the electric field was crucial to understand how much force a charge would experience when moving from one point to another.

To calculate this magnitude, as shown in the solution steps, we used the potential difference between points and the distance between them. This provides a simple yet powerful way to determine the field's strength. In practical terms, knowing the electric field's magnitude allows engineers to design electrical equipment that can withstand the forces within the field, like the insulation on a power line.

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Most popular questions from this chapter

An infinitely long line of charge has linear charge density \(5.00 \times 10^{-12} \mathrm{C} / \mathrm{m} .\) A proton (mass \(1.67 \times 10^{-27} \mathrm{~kg},\) charge \(+1.60 \times 10^{-19} \mathrm{C}\) ) is \(18.0 \mathrm{~cm}\) from the line and moving directly toward the line at \(3.50 \times 10^{3} \mathrm{~m} / \mathrm{s}\). (a) Calculate the proton's initial kinetic energy. (b) How close does the proton get to the line of charge?

Two large, parallel conducting plates carrying opposite charges of equal magnitude are separated by \(2.20 \mathrm{~cm}\). (a) If the surface charge density for each plate has magnitude \(47.0 \mathrm{nC} / \mathrm{m}^{2}\), what is the magnitude of \(\dot{E}\) in the region between the plates? (b) What is the potential difference between the two plates? (c) If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitude of the electric field and to the potential difference?

At a certain distance from a point charge, the potential and electric-field magnitude due to that charge are \(4.98 \mathrm{~V}\) and \(16.2 \mathrm{~V} / \mathrm{m}\) respectively. (Take \(V=0\) at infinity.) (a) What is the distance to the point charge? (b) What is the magnitude of the charge? (c) Is the electric field directed toward or away from the noint charge?

A proton and an alpha particle are released from rest when they are \(0.225 \mathrm{nm}\) apart. The alpha particle (a helium nucleus) has essentially four times the mass and two times the charge of a proton. Find the maximum speed and maximum acceleration of each of these particles. When do these maxima occur: just following the release of the particles or after a very long time?

A point charge \(q_{1}\) is held stationary at the origin. A second charge \(q_{2}\) is placed at point \(a\), and the electric potential energy of the pair of charges is \(+5.4 \times 10^{-8} \mathrm{~J}\). When the second charge is moved to point \(b,\) the clectric force on the charge does \(-1.9 \times 10^{-8} \mathrm{~J}\) of work. What is the electric potential energy of the pair of charges when the second charge is at point \(b ?\)

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