/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 A disk with radius \(R\) and uni... [FREE SOLUTION] | 91Ó°ÊÓ

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A disk with radius \(R\) and uniform positive charge density \(\sigma\) lies horizontally on a tabletop. A small plastic sphere with mass \(M\) and positive charge \(Q\) hovers motionless above the center of the disk, suspended by the Coulomb repulsion due to the charged disk. (a) What is the magnitude of the net upward force on the sphere as a function of the height \(z\) above the disk? (b) At what height \(h\) does the sphere hover? Express your answer in terms of the dimensionless constant \(v \equiv 2 \epsilon_{0} M g /(Q \sigma) .\) (c) If \(M=100 \mathrm{~g}, Q=1 \mu \mathrm{C}, R=5 \mathrm{~cm},\) and \(\sigma=10 \mathrm{nC} / \mathrm{cm}^{2},\) what is \(h ?\)

Short Answer

Expert verified
The net upward force on the sphere as a function of the height \(z\) above the disk is: \(Q \frac{\sigma}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) - Mg\). At the dimensionless constant \( v = 2 \epsilon_{0} M g /(Q \sigma) \), the sphere hovers at a height \( h = R \sqrt{v^2 - 1} = 6.8 \, cm\) given the provided parameters.

Step by step solution

01

Getting the Force due to the Charged Disk

Using Physics, we understand that the electric field from a uniformly charged disk at a point on the axis through its center can be defined by the formula: \[ E = \frac{\sigma}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) \]This electric field is directed away from the charged disk. Since the electric force \(\textbf{F}\) is given by \(F = QE\), force from the disk on the charged ball can thus be given as:\[ F = QE = Q \frac{\sigma}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) \]Note: This force will be directed away from the disc and thus, will act as a supporting force for the sphere.
02

Net Upward Force Calculation

The net upward force will be the difference between the upward force due to the disk and the downward gravitational force acting on the sphere. If we denote the net force as \(F_{net}\) and the gravitational force as \(F_{g}\), we get:\[ F_{g} = Mg \]\(F_{net} = F - F_{g} = Q \frac{\sigma}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) - Mg\]
03

Height Calculation Where the Sphere Hovers

The sphere will hover at a height at which the net force is zero. Setting \(F_{net}\) equal to zero and solving for \(z\) costitutes the solution. We get:\[0 = Q \frac{\sigma}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) - Mg\]On a side-note, \( v = \frac{2\epsilon_{0} M g}{Q \sigma} \) is provided. By rearranging this expression, we have \( Q \sigma = \frac{2\epsilon_{0} M g}{v} \). Replacing \( Q \sigma \) in the earlier 'zero force' equation, we get a simpler equation to solve.\[0 = \frac{2\epsilon_{0}M g}{v} \frac{1}{2\epsilon_{0}} (1 - \frac{z}{\sqrt{z^{2} + R^{2}}}) - Mg\]with the solution being \( z = R \sqrt{v^2 - 1} \) if \( v > 1 \). This becomes \( h \) when the sphere hovers.
04

Calculation of Height for the Given values

Substitute the given values into the equations to get the answer for \(h\). Given: \(M = 100 g, Q = 1 \mu C, R = 5 cm, \sigma = 10 nC / cm^2 \). Now calculate \(v\) first:\[ v = \frac{2\epsilon_{0}M g}{Q \sigma} = \frac{2*8.85*10^{-12}*0.1*9.8}{10^{-6}*10*10^{-9}} = 1.77 \]Now substituting the computed \(v\) value into the formula for \(h\), we get \(h = R \sqrt{v^2 - 1} = 5 \sqrt{1.77^2 - 1} = 6.8 \, cm.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
Understanding the concept of the electric field is essential when studying the forces between charged particles. At a basic level, the electric field is a vector field surrounding an electric charge that exerts force on other charges within the field.

It can be pictorially represented as lines emanating from positive charges and terminating at negative charges. The direction of the electric field at any point is the direction of the force that would be exerted on a positive test charge if it were placed at that point. The concept of the electric field allows us to calculate the force on a charge without having direct contact with the source charge.

For a disk with a uniform positive charge density, the electric field at any point above the center of the disk can be derived from Coulomb's law, scaled with respect to the geometry and charge distribution of the disk. This field is fundamental in determining the force exerted on any charged objects within its influence, like the hovering plastic sphere in the exercise.
Uniform Charge Density
Uniform charge density, denoted as \(\sigma\), is a measure of how charge is distributed over a surface. In the context of our exercise, a disk with uniform charge density means that the charge per unit area is constant throughout the entire surface of the disk.

To visualize this, imagine the surface of the disk divided into infinitesimally small areas, each carrying an equal small amount of charge. This uniformity simplifies the calculations of electric fields and forces because it allows for the electric field to be integrated across the entire surface without varying the charge amount per area.

In practical applications, materials with uniform charge distributions are often approximated to make calculations easier. However, in reality, charges might not be perfectly uniform, leading to more complex electric fields and force interactions.
Net Force Calculation
In physics, the calculation of net force is pivotal for understanding how objects will move or interact. The net force is the vector sum of all forces acting on an object. If we have multiple forces, we need to add them vectorially, considering both their magnitudes and directions.

In the context of the exercise, the net force on the plastic sphere is determined by two key forces: the electric force caused by the electric field of the charged disk and the gravitational force pulling the sphere downward. To find where the sphere hovers, we set the net force to zero, which means the electric force exactly cancels out the gravitational force.

More formally, the net force \(F_{net}\) is calculated as the difference between the upward Coulomb force and the downward gravitational force \(F_{g} = Mg\). This net force equation facilitates the determination of the equilibrium position of the sphere—the point at which it hovers motionless above the charged disk. The calculated height at which the net force equals zero provides the height \(h\) where the sphere remains in stable equilibrium.

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Most popular questions from this chapter

Two small spheres spaced \(20.0 \mathrm{~cm}\) apart have equal charge. How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is \(3.33 \times 10^{-21} \mathrm{~N} ?\)

An insulating rigid rod of length \(2 a\) and negligible mass is attached at its center to a pivot at the origin and is free to rotate in the \(x y\) -plane. A small ball with mass \(M\) and charge \(Q\) is attached to one end of the rod. A second small ball with mass \(M\) and no charge is attached to the other end. A constant electric field \(\vec{E}=-E \hat{\imath}\) is present in the region \(y>0\) while the region \(y<0\) has a vanishing electric field. Define \(\vec{r}\) as the vector that points from the center of the rod to the charged end of the rod, and \(\theta\) as the angle between \(\vec{r}\) and the positive \(x\) -axis. The rod is oriented so that \(\theta=0\) and is given an infinitesimal nudge in the direction of increasing \(\theta\). (a) Write an expression for the vector \(\vec{r}\). (b) Determine the torque \(\vec{\tau}\) about the center of the rod when \(0 \leq \theta \leq \pi\). (c) Determine the torque on the rod about its center when \(\pi \leq \theta \leq 2 \pi\). (d) What is the moment of inertia \(I\) of the system about the \(z\) -axis? (e) The potential energy \(U(\theta)\) is determined by \(\tau=-d U / d \theta .\) Use this equation to write an expression for \(U(\theta)\) over the range \(0 \leq \theta \leq 4 \pi\) using the convention that \(U(0)=0 .\) Make sure that \(U(\theta)\) is continuous. (f) The angular velocity of the rod is \(\omega=\omega(\theta) .\) Using \(\tau=I d^{2} \theta / d t^{2}\) show that the energy \(\frac{1}{2} I \omega^{2}+U(\theta)\) is conserved. (g) Using energy conservation, determine an expression for the angular velocity at the \(n\) th time the positive charge crosses the negative \(y\) -axis.

Negative charge \(-Q\) is distributed uniformly around a quarter-circle of radius \(a\) that lies in the first quadrant, with the center of curvature at the origin. Find the \(x\) - and \(y\) -components of the net electric field at the origin.

A small sphere with mass \(m\) carries a positive charge \(q\) and is attached to one end of a silk fiber of length \(L .\) The other end of the fiber is attached to a large vertical insulating sheet that has a positive surface charge density \(\sigma\). Show that when the sphere is in equilibrium, the fiber makes an angle equal to arctan \(\left(q \sigma / 2 m g \epsilon_{0}\right)\) with the vertical sheet.

An electric dipole with a dipole moment of magnitude \(p\) is placed at various orientations in an electric field \(\vec{E}\) that is directed to the left. (a) What orientation of the dipole will result in maximum torque directed into the page? What then is the electric potential energy? (b) What orientation of the dipole will give zero torque and maximum electric potential energy? What type of equilibrium is this: stable, unstable, or neutral?

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