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Two particles having charges \(q_{1}=0.500 \mathrm{nC} \quad\) and\(q_{2}=8.00 \mathrm{nC}\) are separated by a distance of \(1.20 \mathrm{~m}\). At what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?

Short Answer

Expert verified
The location where the total electric field is zero is 2.37m to the right of the 8.00 nC charge.

Step by step solution

01

Identify the Scenerio

Firstly, identify there can be two scenarios - either the null point of the electric field is located between the charges or outside of them. You should analyze these cases separately.
02

Case 1 - Null Point Between Charges

Assuming the null point is between the charges, call this distance from the 0.500nC charge x. Then the distance from the 8.00nC charge is \((1.20-x)\) m. Set the absolute values of the two electric field contributions equal to each other and solve for x. \(|k \frac{q_{1}}{x^{2}}| = |k \frac{q_{2}}{(1.20-x)^{2}}|\). After simplifying this equation we get \(x^{2}(0.500) = (1.20 - x)^{2}(8.00)\).
03

Solve for x

Solving this quadratic equation yields \(x = 1.07 m\). However, check if this value is believable. The distance from 0.500nC charge is larger than the separation 1.20m, therefore discard it.
04

Case 2 - Null Point Outside of The Charges

Assume the null point is located some distance x to the right of the 8.00nC charge. Then the absolute values of the electric field contributions from each charge are \(k \frac{q_{2}}{x^{2}}\), and \(k \frac{q_{1}}{(1.20 + x)^{2}}\) respectively. Setting these equal gives \(x^{2}(8.00) = (1.20 + x)^{2}(0.500)\).
05

Solve for x

Solving the quadratic equation gives \(x = 2.37 m\). This is plausible and means that at 2.37m right of the 8.00nC charge, the electric fields due to both charges cancel each other out.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Charge
Electric charge is a fundamental property of particles that determines how they interact with other charged particles and electromagnetic fields. There are two types of charges: positive and negative. Like charges repel each other, while opposite charges attract. The unit of charge is the coulomb (C), but in many cases, charges are so small that we use subunits like the nanocoulomb (nC), as seen in the exercise. Charges are quantized, meaning they exist in discrete packets (e.g., the charge of an electron is approximately -1.602 x 10-19 C).

In the exercise, two particles with different charges are considered. To understand the behavior of these charges, it's essential to know that electric fields arise from charges and exert forces on other charges within the field. The goal of the problem is to discover the point where the electric fields from each charge cancel out, leaving a net electric field of zero.
Coulomb's Law
Coulomb's Law is crucial for any calculations related to electric charges. It describes the electric force between two charges as directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The equation is given by:
\[ F = k \frac{{|q_1 q_2|}}{{r^2}} \]
where \(F\) is the force, \(k\) is Coulomb's constant (approximately 8.988 x 109 Nm2/C2), \(q_1\) and \(q_2\) are the charges, and \(r\) is the distance between the charges. This law applies to point charges—idealized charges located at a single point in space. In the exercise, Coulomb's Law helps us understand the electric field contributions from each charge and how they might cancel out to yield a point with zero electric field.
Quadratic Equations
Quadratic equations, which take the form \(ax^2 + bx + c = 0\), are polynomial equations of the second degree. They have a variety of applications across different fields of science and engineering. In our scenario, the quadratic equation emerges from setting the magnitudes of the electric field contributions from each charge equal to one another, following Coulomb's Law and the inverse-square relationship.

The solutions to a quadratic equation are found using the quadratic formula: \[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}\]
However, not all solutions may be physically meaningful within the context of a problem. In our exercise, the quadratic equation derived from equating the electric field contributions leads to two potential solutions. It is essential to analyze these solutions in the context of the problem to determine which is physically plausible.
Electric Field Contributions
The electric field (\(E\)) at a point in space is a vector quantity that represents the force per unit charge a test charge would experience at that point. It's defined as:\[E = k \frac{{q}}{{r^2}}\]
where \(E\) is the electric field, \(k\) is Coulomb's constant, \(q\) is the charge creating the field, and \(r\) is the distance from the charge to the point in question. For multiple charges, the net electric field is the vector sum of the individual fields due to each charge.

In the textbook exercise, we explore the superposition principle by looking for a zero point, where the electric field contributions from two charges cancel out. As the charges have different magnitudes, the zero point can be found at a location where the distance to each charge differs in such a way that their field magnitudes are equal and opposite. This shows that electric field intensity depends on both the magnitude of the charge and the distance from the charge.

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Most popular questions from this chapter

A nerve signal is transmitted through a neuron when an excess of \(\mathrm{Na}^{+}\) ions suddenly enters the axon, a long cylindrical part of the neuron. Axons are approximately \(10.0 \mu \mathrm{m}\) in diameter, and measurements show that about \(5.6 \times 10^{11} \mathrm{Na}^{+}\) ions per meter (each of charge \(+e\) ) enter during this process. Although the axon is a long cylinder, the charge does not all enter everywhere at the same time. A plausible model would be a series of point charges moving along the axon. Consider a \(0.10 \mathrm{~mm}\) length of the axon and model it as a point charge. (a) If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a \(0.10 \mathrm{~mm}\) length of the axon? (b) What electric field (magnitude and direction) does the sudden influx of charge produce at the surface of the body if the axon is \(5.00 \mathrm{~cm}\) below the skin? (c) Certain shark can respond to electric fields as weak as \(1.0 \mu \mathrm{N} / \mathrm{C}\). How far from this segment of axon could a shark be and still detect its electric field?

A small sphere with positive charge \(q\) and mass \(m\) is released from rest in a uniform electric field \(\vec{E}\) that is directed vertically upward. The magnitude of the field is large enough for the sphere to travel upward when it is released. How long does it take the sphere to travel upward a distance \(d\) after being released from rest? Give your answer in terms of \(q, m, d, E,\) and the acceleration due to gravity, \(g\).

Three parallel sheets of charge, large enough to be treated as infinite sheets, are perpendicular to the \(x\) -axis. Sheet \(A\) has surface charge density \(\sigma_{A}=+8.00 \mathrm{nC} / \mathrm{m}^{2}\). Sheet \(B\) is \(4.00 \mathrm{~cm}\) to the right of sheet \(A\) and has surface charge density \(\sigma_{B}=-4.00 \mathrm{nC} / \mathrm{m}^{2} .\) Sheet \(C\) is \(4.00 \mathrm{~cm}\) to the right of sheet \(B,\) so is \(8.00 \mathrm{~cm}\) to the right of sheet \(A,\) and has surface charge density \(\sigma_{C}=+6.00 \mathrm{nC} / \mathrm{m}^{2}\). What are the magnitude and direction of the resultant electric field at a point that is midway between sheets \(B\) and \(C,\) or \(2.00 \mathrm{~cm}\) from each of these two sheets?

An electric dipole with a dipole moment of magnitude \(p\) is placed at various orientations in an electric field \(\vec{E}\) that is directed to the left. (a) What orientation of the dipole will result in maximum torque directed into the page? What then is the electric potential energy? (b) What orientation of the dipole will give zero torque and maximum electric potential energy? What type of equilibrium is this: stable, unstable, or neutral?

A negative charge of \(-0.550 \mu \mathrm{C}\) exerts an upward \(0.600 \mathrm{~N}\) force on an unknown charge that is located \(0.300 \mathrm{~m}\) directly below the first charge. What are (a) the value of the unknown charge (magnitude and sign); (b) the magnitude and direction of the force that the unknown charge exerts on the \(-0.550 \mu \mathrm{C}\) charge?

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