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Two point charges are placed on the \(x\) -axis as follows: Charge \(q_{1}=+4.00 \mathrm{nC}\) is located at \(x=0.200 \mathrm{~m},\) and charge \(q_{2}=+5.00 \mathrm{nC}\) is at \(x=-0.300 \mathrm{~m} .\) What are the magnitude and direction of the total force exerted by these two charges on a negative point charge \(q_{3}=-6.00 \mathrm{nC}\) that is placed at the origin?

Short Answer

Expert verified
The magnitude of the total force exerted by these two charges on the negative point charge \(q_3\) is given by \(F_{net} = |F_2 - F_1|\). The direction is towards the side of the charge that exerts the larger force.

Step by step solution

01

Identify knowns and unknowns

Let's identify what we know and what we need to find out. We know the position and charge for all three charges. The unknowns are the magnitude and direction of the total force exerted by \(q_1\) and \(q_2\) on \(q_3\).
02

Determine forces individually

Let's use Coulomb's law to determine the forces exerted by \(q_1\) and \(q_2\) on \(q_3\) individually. Coulomb's law formula is \(F = K \cdot \frac{|q_1 \cdot q_2|}{r^2}\). Another thing to consider is the force direction. \(q_1\) and \(q_3\) are both positive charges, so they repel each other, and the force is to the right. \(q_2\) and \(q_3\) are both negative charges, so they also repel each other, and the force is to the left.
03

Calculate individual forces

Now plug in the known values into the Coulomb's law. Here, \(K\) is Coulomb's constant (\(K = 9.00 \times 10^9 \, N \cdot m^2/C^2\)), \(q_i\) is the charge, and \(r\) is the distance between the charges. So we calculate, \(F_1 = K \cdot \frac{|q_1 \cdot q_3|}{r_1^2}\) and \(F_2 = K \cdot \frac{|q_2 \cdot q_3|}{r_2^2}\).
04

Calculate total force

Now, to find the total force, since \(F_1\) and \(F_2\) have opposite directions, we subtract them to get \(F_{net} = |F_2 - F_1|\). Also, the direction of the net force will be towards the charge inducing larger force.
05

Find direction of total force

Observe the magnitude of resultant force and decide the direction of force. If \(|F_2| > |F_1|\), the force is towards the left. Otherwise, it is towards the right.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Charge
Electric charge is one of the fundamental properties of matter, intimately related to electromagnetic interactions. It's classified into two types - positive and negative. Like charges repel each other, while unlike charges attract. The unit of electric charge is the coulomb (C). Subatomic particles carry charges, with electrons having a negative charge and protons a positive charge. The conservation of charge principle states that the total charge in an isolated system remains constant no matter what changes take place within the system.

Charges exert forces on each other, which bring about the vast array of observable phenomena in electricity and magnetism. In our exercise example, we see point charges, which can be thought of as idealized charges concentrated at a single point in space. This concept simplifies the problem by reducing the complex distribution of charges to manageable calculations using Coulomb's law.
Electric Force
Electric force is the push or pull that charged objects exert on each other. The magnitude of this force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them, as stated by Coulomb's law. Mathematically, it's expressed as \(F = K \cdot \frac{|q_1 \cdot q_2|}{r^2}\), where \(F\) is the force, \(K\) is Coulomb's constant (\(9.00 \times 10^9 \, N \cdot m^2/C^2\)), \(|q_1 \cdot q_2|\) is the absolute product of the charges, and \(r\) is the distance between the charges.

In the context of our exercise, we're using Coulomb's law to calculate the forces between each pair of charges to understand the net force acting on a charge. By considering both magnitude and direction, we ensure accurate and complete solutions to problems involving electrostatic forces.
Electrostatics
Electrostatics is the branch of physics that studies electric charges at rest. As opposed to electrodynamics, which involves moving charges and varying fields, electrostatics focuses on static charges and constant electric fields. Central to electrostatics is the concept that force is exerted without physical contact; this action-at-a-distance is due to electric fields generated by static charges.

An electric field exerts forces on charges within its influence, giving us a useful way to visualize and calculate how charged objects behave when placed in such fields. The problem we're looking at involves electrostatic forces as all charges are stationary. By understanding electrostatic principles, one can predict how the negative point charge in our exercise will move in response to the forces exerted by the other two stationary charges.

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Most popular questions from this chapter

A small sphere with mass \(m\) carries a positive charge \(q\) and is attached to one end of a silk fiber of length \(L .\) The other end of the fiber is attached to a large vertical insulating sheet that has a positive surface charge density \(\sigma\). Show that when the sphere is in equilibrium, the fiber makes an angle equal to arctan \(\left(q \sigma / 2 m g \epsilon_{0}\right)\) with the vertical sheet.

A charge of \(-3.00 \mathrm{nC}\) is placed at the origin of an \(x y-\)coordinate system, and a charge of \(2.00 \mathrm{nC}\) is placed on the \(y\) -axis at \(y=4.00 \mathrm{~cm} .\) (a) If a third charge, of \(5.00 \mathrm{nC}\), is now placed at the point \(x=3.00 \mathrm{~cm}, y=4.00 \mathrm{~cm},\) find the \(x-\) and \(y-\) components of the total force exerted on this charge by the other two charges. (b) Find the magnitude and direction of this force.

What is the best explanation for the observation that the electric charge on the stem became positive as the charged bee approached (before it landed)? (a) Because air is a good conductor, the positive charge on the bee's surface flowed through the air from bee to plant. (b) Because the earth is a reservoir of large amounts of charge, positive ions were drawn up the stem from the ground toward the charged bee. (c) The plant became electrically polarized as the charged bee approached. (d) Bees that had visited the plant earlier deposited a positive charge on the stem.

An electric dipole with dipole moment \(\vec{p}\) is in a uniform external electric field \(E\). (a) Find the orientations of the dipole for which the torque on the dipole is zero. (b) Which of the orientations in part (a) is stable, and which is unstable? (Hint: Consider a small rotation away from the equilibrium position and see what happens.) (c) Show that for the stable orientation in part (b), the dipole's own electric field tends to oppose the external field.

A point charge is placed at each corner of a square with side length a. All charges have magnitude \(q\). Two of the charges are positive and two are negative (Fig. E21.38). What is the direction of the net electric field at the center of the square due to the four charges, and what is its magnitude in terms of \(q\) and \(a\) ?

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