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Three moles of an ideal gas undergo a reversible isothermal compression at \(20.0^{\circ} \mathrm{C}\). During this compression, \(1850 \mathrm{~J}\) of work is done on the gas. What is the change of cntropy of the gas?

Short Answer

Expert verified
The change in entropy of the gas is 6.314 J/K.

Step by step solution

01

Convert Temperature to Kelvin

First, convert the temperature from Celsius to Kelvin. The conversion formula is T(K) = T(°C) + 273.15. So, T(K) = 20.0°C + 273.15 = 293.15 K.
02

Calculate Work in Terms of Heat

In isothermal processes for ideal gases, the work done is equal to the heat transferred to or from the system. So, Q = 1850 J (Joules).
03

Calculate the Change in Entropy

The formula to find the change in entropy is ΔS = Q/T. By inserting Q = 1850 J and T = 293.15 K into the formula, ΔS = 1850 J / 293.15 K.
04

Final Simplification

By simplifying the calculation, we find that ΔS = 6.314 J/K.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isothermal Compression
In the context of thermodynamics, the term isothermal refers to processes that occur at a constant temperature. When we talk about isothermal compression, this involves the reduction of volume of a gas while maintaining the same temperature throughout the process. It's important to understand that in an ideal gas—a hypothetical gas that perfectly follows the gas laws—no energy is lost or gained in the form of heat during isothermal compression.

The exercise at hand deals with such an isothermal process. For students to fully grasp the concept, picture a piston compressing the gas in a cylinder slowly enough that the system can exchange heat with its surroundings to stay at a constant temperature. Entropy, which we'll discuss later, can be a bit tricky in isothermal processes but remembering that temperature remains unchanged is key to understanding the other steps involved.
Thermodynamics
Thermodynamics is a branch of physics that deals with the relationship between heat and other forms of energy. In the world of thermodynamics, we often speak of systems and surroundings; a system is the part of the universe that is being studied, while everything else constitutes the surroundings. The exercise we're examining illustrates one of the fundamental aspects of thermodynamics—the conservation of energy, which in this case is demonstrated through an isothermal process.

The First Law of Thermodynamics

Relating to the exercise, the first law, which is essentially the law of conservation of energy, tells us that the energy of the universe is constant. For an isothermal compression of an ideal gas, where temperature is constant, any work done on the system results in an equivalent amount of heat being released or absorbed, keeping the internal energy unchanged. This is crucial when calculating the change in entropy to determine directionality and magnitude of energy dispersion.
Entropy Calculation
Entropy is a measure of the disorder or randomness in a system. Calculating the change in entropy, symbolized as \( \Delta S \), is a fundamental part of thermodynamics that provides insight into the spontaneity of processes and the energy distribution within a system. We calculate entropy change by the formula \( \Delta S = \frac{Q}{T} \), where \( Q \) is the heat transfer at a constant temperature and \( T \) is the absolute temperature in Kelvin.

In our exercise, an ideal gas undergoes isothermal compression and 1850 J of work is done on the gas, implying that the same amount of heat is transferred due to the characteristics of an isothermal process. Applying the formula, with \( Q = 1850 \text{J} \) and \( T = 293.15 \text{K} \) (after converting from Celsius to Kelvin), we find the change in entropy to be positive. This increase in entropy may seem counterintuitive since compression might suggest less disorder; however, it actually reflects the dispersion of energy into the surroundings in the form of heat.

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Most popular questions from this chapter

A Carnot engine is operated between two heat rescrvoirs at temperatures of \(520 \mathrm{~K}\) and \(300 \mathrm{~K}\). (a) If the engine receives \(6.45 \mathrm{~kJ}\) of heat energy Irom the reservoir at \(520 \mathrm{~K}\) in each eycle, how many joules per cycle does it discard to the reservoir at \(300 \mathrm{~K}^{\prime} ?\) (b) How much mechanical work is performed by the engine during each cycle? (c) What is the thermal efficiency of the engine?

The Outo-cycle engine in a Mercedes-Benz SL.K230 has a compression ratio of 8.8 . (a) What is the ideal efficiency of the engine? Use \(\gamma=1.40 .\) (b) The engine in a Dodge Viper GT2 has a slightly higher compression ratio of 9.6 . How much increase in the ideal efficicncy results from this increase in the compression ratio?

An aircraft cngine takes in \(9000 \mathrm{~J}\) of heat and discards \(6400 \mathrm{~J}\) each cycle. (a) What is the mechanical work output of the engine during one cycle? (b) What is the thermal efficiency of the engine?

In your summer job with a venture capital firm, you are given funding requests from four inventors of heat cngines. The inventors claim the following data for their operating prototypes: for a Carnot device that operates between \(95 \mathrm{~F}\) and \(80^{\circ} \mathrm{F}\). (c) You have an air conditioner with an EER of 10.9 . Your home on average requires a total cooling output of \(\left|Q_{\mathrm{C}}\right|=1.9 \times 10^{10} \mathrm{~J}\) per year. If electricity costs you 15.3 cents per \(\mathrm{kW} \cdot \mathrm{h}\), how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's EER accurately represcits the operation of your air conditioner. A seasonal energy efficiency ratio (SEFR) is often used. The SFFR is calculated over a range of outside temperatures to get a more accurate seasonal average.) (d) You are considering replacing your air conditioner with a more efficient one with an EER of 14.6 . Based on the EER, how much would that save you on electricity costs in an average year?

You decide to take a nice hot bath but discover that your thoughtless roommate has used up most of the hot water. You fill the tub with \(195 \mathrm{~kg}\) of \(30.0^{\circ} \mathrm{C}\) water and attempt to warm it further by pouring in \(5.00 \mathrm{~kg}\) of boiling water from the stove. (a) Is this a reversible or an irreversible process? Use physical reasoning to cxplain. (b) Calculate the final temperature of the bath water. (c) Calculate the net change in entropy of the system (bath water + boiling water), assuming no heat exchange with the air or the tub itself.

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