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An unknown liquid has density \(\rho\) and coefficient of volume expansion \(\beta\). A quantity of heat \(Q\) is added to a volume \(V\) of the liquid, and the volume of the liquid increases by an amount \(\Delta V\). There is no phase change. In terms of these quantities, what is the specific heat capacity \(c\) of the liquid?

Short Answer

Expert verified
The specific heat capacity of the liquid is \(c = \frac{Q \beta}{\rho \Delta V}\)

Step by step solution

01

Express the mass in terms of volume and density

The mass \(m\) of a substance is given by the product of its volume \(V\) and density \(\rho\), that is \(m = \rho V\).
02

Determine the change in temperature

The coefficient of volume expansion \(\beta\) is defined as \(\beta = \frac{\Delta V}{V \Delta T}\), where \(\Delta T\) is the change in temperature. Solving for \(\Delta T\) yields \(\Delta T = \frac{\Delta V}{V \beta}\).
03

Calculate the specific heat capacity

The formula for the specific heat capacity is \(c = \frac{Q}{m \Delta T}\). It represents the heat supplied per unit mass per unit temperature change. Substituting the expressions from steps 1 and 2 into this equation gives \(c = \frac{Q}{(\rho V) \left(\frac{\Delta V}{V\beta}\right)} = \frac{Q \beta}{\rho \Delta V}\). Applaud yourself, because you have made it to the final step!

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density of Liquid
Density plays a vital role when studying liquids in physics and chemistry. It is defined as the mass of a substance per unit volume. For a liquid, the density \( \rho \) can be thought of as how compactly the molecules of that substance are packed together. A higher density means that the molecules are more closely packed.
Understanding density is crucial when trying to determine other properties, such as the specific heat capacity in our exercise. When heat \( Q \) is added to a liquid, the mass of the liquid \( m \) is required to find its specific heat. Using the relationship \( m = \rho V \), where \( V \) is the volume of the liquid, we can connect the concept of density directly to the calculation of specific heat capacity, showing its importance in thermal dynamics.
Coefficient of Volume Expansion
The coefficient of volume expansion \( \beta \) is a measure of how much the volume of a material changes with temperature. In the context of our exercise, it quantifies the change in volume \( \Delta V \) of the liquid for a given change in temperature \( \Delta T \).
In mathematical terms, \( \beta \) is defined as \( \beta = \frac{\Delta V}{V \Delta T} \) for a fixed amount of liquid with volume \( V \). It's a crucial parameter for predicting the behavior of liquids under temperature variations, with higher coefficients indicating more sensitivity to temperature changes. When calculating specific heat capacity, knowledge of the coefficient of volume expansion allows us to determine the temperature change corresponding to the volume change, furthering our understanding of thermal expansion.
Thermal Expansion
Thermal expansion is a concept that describes how the size of an object changes with a change in temperature. Specifically, for liquids and gases, we typically talk about volume expansion rather than linear expansion which is more common in solids.
When a liquid heats up, its molecules move faster and tend to occupy more space, hence the liquid expands, and its volume increases. This expansion is characterized by the coefficient of volume expansion \( \beta \) as discussed previously. \( \Delta V \) signifies this increase in volume, and it's intrinsically linked to the change in temperature. As seen in the exercise, understanding how much the liquid will expand helps to determine vital properties such as specific heat capacity, by relating the volume change to the amount of heat added.
Heat Transfer in Thermodynamics
Heat transfer is the process by which heat energy is exchanged between physical systems. Thermodynamics, the branch of physics that deals with the relationships between heat and other forms of energy, describes this process through several fundamental principles.
In our specific case, we are adding a quantity of heat \( Q \) to a liquid, which results in an increase in temperature and a corresponding volume expansion. It’s this energy transfer without a phase change that we analyze to determine the specific heat capacity \( c \) of the liquid. This property \( c \) indicates how much heat energy is required to raise the temperature of a unit mass of a substance by one degree. It is a key parameter in the study of thermodynamics, essential for the design of heating and cooling systems, and understanding and predicting the thermal behavior of materials.

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Most popular questions from this chapter

On-Demand Water Heaters. Conventional hot-water heaters consist of a tank of water maintained at a fixed temperature. The hot water is to be used when needed. The drawbacks are that energy is wasted because the tank loses heat when it is not in use and that you can run out of hot water if you use too much. Some utility companies are encouraging the use of on-demand water heaters (also known as flash heaters), which consist of heating units to heat the water as you use it. No water tank is involved, so no heat is wasted. A typical household shower flow rate is \(2.5 \mathrm{gal} / \mathrm{min}(9.46 \mathrm{~L} / \mathrm{min})\) with the tap water being heated from \(50^{\circ} \mathrm{F}\left(10^{\circ} \mathrm{C}\right)\) to \(120^{\circ} \mathrm{F}\left(49^{\circ} \mathrm{C}\right)\) by the on-demand heater. What rate of heat input (either electrical or from gas) is required to operate such a unit, assuming that all the heat goes into the water?

A carpenter builds a solid wood door with dimensions \(2.00 \mathrm{~m} \times 0.95 \mathrm{~m} \times 5.0 \mathrm{~cm} .\) Its thermal conductivity is \(k=0.120 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The air films on the inner and outer surfaces of the door have the same combined thermal resistance as an additional \(1.8 \mathrm{~cm}\) thickness of solid wood. The inside air temperature is \(20.0^{\circ} \mathrm{C},\) and the outside air temperature is \(-8.0^{\circ} \mathrm{C}\). (a) What is the rate of heat flow through the door? (b) By what factor is the heat flow increased if a window \(0.500 \mathrm{~m}\) on a side is inserted in the door? The glass is \(0.450 \mathrm{~cm}\) thick, and the glass has a thermal conductivity of \(0.80 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The air films on the two sides of the glass have a total thermal resistance that is the same as an additional \(12.0 \mathrm{~cm}\) of glass.

One end of an insulated metal rod is maintained at \(100.0^{\circ} \mathrm{C}\), and the other end is maintained at \(0.00^{\circ} \mathrm{C}\) by an ice-water mixture. The rod is \(60.0 \mathrm{~cm}\) long and has a cross-sectional area of \(1.25 \mathrm{~cm}^{2}\). The heat conducted by the rod melts \(8.50 \mathrm{~g}\) of ice in \(10.0 \mathrm{~min} .\) Find the thermal conductivity \(k\) of the metal.

Animals in cold climates often depend on \(t w o\) layers of insulation: a layer of body fat (of thermal conductivity \(0.20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) ) surrounded by a layer of air trapped inside fur or down. We can model a black bear (Ursus americanus) as a sphere \(1.5 \mathrm{~m}\) in diameter having a layer of fat \(4.0 \mathrm{~cm}\) thick. (Actually, the thickness varies with the season, but we are interested in hibernation, when the fat layer is thickest.) In studies of bear hibernation, it was found that the outer surface layer of the fur is at \(2.7^{\circ} \mathrm{C}\) during hibernation, while the inner surface of the fat layer is at \(31.0^{\circ} \mathrm{C}\). (a) What is the temperature at the fat-inner fur boundary so that the bear loses heat at a rate of \(50.0 \mathrm{~W} ?\) (b) How thick should the air layer (contained within the fur) be?

In a container of negligible mass, \(0.0400 \mathrm{~kg}\) of steam at \(100^{\circ} \mathrm{C}\) and atmospheric pressure is added to \(0.200 \mathrm{~kg}\) of water at \(50.0^{\circ} \mathrm{C}\) (a) If no heat is lost to the surroundings, what is the final temperature of the system? (b) At the final temperature, how many kilograms are there of steam and how many of liquid water?

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