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An unknown liquid has density \(\rho\) and coefficient of volume expansion \(\beta\). A quantity of heat \(Q\) is added to a volume \(V\) of the liquid, and the volume of the liquid increases by an amount \(\Delta V\). There is no phase change. In terms of these quantities, what is the specific heat capacity \(c\) of the liquid?

Short Answer

Expert verified
The specific heat capacity of the liquid is \(c = \frac{Q \beta}{\rho \Delta V}\)

Step by step solution

01

Express the mass in terms of volume and density

The mass \(m\) of a substance is given by the product of its volume \(V\) and density \(\rho\), that is \(m = \rho V\).
02

Determine the change in temperature

The coefficient of volume expansion \(\beta\) is defined as \(\beta = \frac{\Delta V}{V \Delta T}\), where \(\Delta T\) is the change in temperature. Solving for \(\Delta T\) yields \(\Delta T = \frac{\Delta V}{V \beta}\).
03

Calculate the specific heat capacity

The formula for the specific heat capacity is \(c = \frac{Q}{m \Delta T}\). It represents the heat supplied per unit mass per unit temperature change. Substituting the expressions from steps 1 and 2 into this equation gives \(c = \frac{Q}{(\rho V) \left(\frac{\Delta V}{V\beta}\right)} = \frac{Q \beta}{\rho \Delta V}\). Applaud yourself, because you have made it to the final step!

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density of Liquid
Density plays a vital role when studying liquids in physics and chemistry. It is defined as the mass of a substance per unit volume. For a liquid, the density \( \rho \) can be thought of as how compactly the molecules of that substance are packed together. A higher density means that the molecules are more closely packed.
Understanding density is crucial when trying to determine other properties, such as the specific heat capacity in our exercise. When heat \( Q \) is added to a liquid, the mass of the liquid \( m \) is required to find its specific heat. Using the relationship \( m = \rho V \), where \( V \) is the volume of the liquid, we can connect the concept of density directly to the calculation of specific heat capacity, showing its importance in thermal dynamics.
Coefficient of Volume Expansion
The coefficient of volume expansion \( \beta \) is a measure of how much the volume of a material changes with temperature. In the context of our exercise, it quantifies the change in volume \( \Delta V \) of the liquid for a given change in temperature \( \Delta T \).
In mathematical terms, \( \beta \) is defined as \( \beta = \frac{\Delta V}{V \Delta T} \) for a fixed amount of liquid with volume \( V \). It's a crucial parameter for predicting the behavior of liquids under temperature variations, with higher coefficients indicating more sensitivity to temperature changes. When calculating specific heat capacity, knowledge of the coefficient of volume expansion allows us to determine the temperature change corresponding to the volume change, furthering our understanding of thermal expansion.
Thermal Expansion
Thermal expansion is a concept that describes how the size of an object changes with a change in temperature. Specifically, for liquids and gases, we typically talk about volume expansion rather than linear expansion which is more common in solids.
When a liquid heats up, its molecules move faster and tend to occupy more space, hence the liquid expands, and its volume increases. This expansion is characterized by the coefficient of volume expansion \( \beta \) as discussed previously. \( \Delta V \) signifies this increase in volume, and it's intrinsically linked to the change in temperature. As seen in the exercise, understanding how much the liquid will expand helps to determine vital properties such as specific heat capacity, by relating the volume change to the amount of heat added.
Heat Transfer in Thermodynamics
Heat transfer is the process by which heat energy is exchanged between physical systems. Thermodynamics, the branch of physics that deals with the relationships between heat and other forms of energy, describes this process through several fundamental principles.
In our specific case, we are adding a quantity of heat \( Q \) to a liquid, which results in an increase in temperature and a corresponding volume expansion. It’s this energy transfer without a phase change that we analyze to determine the specific heat capacity \( c \) of the liquid. This property \( c \) indicates how much heat energy is required to raise the temperature of a unit mass of a substance by one degree. It is a key parameter in the study of thermodynamics, essential for the design of heating and cooling systems, and understanding and predicting the thermal behavior of materials.

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Most popular questions from this chapter

Size of a Light-Bulb Filament. The operating temperature of a tungsten filament in an incandescent light bulb is \(2450 \mathrm{~K},\) and its emissivity is \(0.350 .\) Find the surface area of the filament of a \(150 \mathrm{~W}\) bulb if all the electrical energy consumed by the bulb is radiated by the filament as electromagnetic waves. (Only a fraction of the radiation appears as visible light.)

A \(\mathrm 500.0 \mathrm{~g}\) chunk of an unknown metal, which has been in boiling water for several minutes, is quickly dropped into an insulating Styrofoam beaker containing \(1.00 \mathrm{~kg}\) of water at room temperature \(\left(20.0^{\circ} \mathrm{C}\right) .\) After waiting and gently stirring for 5.00 minutes, you observe that the water's temperature has reached a constant value of \(22.0^{\circ} \mathrm{C}\). (a) Assuming that the Styrofoam absorbs a negligibly small amount of heat and that no heat was lost to the surroundings, what is the specific heat of the metal? (b) Which is more useful for storing thermal energy: this metal or an equal weight of water? Explain. (c) If the heat absorbed by the Styrofoam actually is not negligible, how would the specific heat you calculated in part (a) be in error? Would it be too large, too small, or still correct? Explain.

The emissivity of tungsten is 0.350 . A tungsten sphere with radius \(1.50 \mathrm{~cm}\) is suspended within a large evacuated enclosure whose walls are at \(290.0 \mathrm{~K}\). What power input is required to maintain the sphere at \(3000.0 \mathrm{~K}\) if heat conduction along the supports is ignored?

In a container of negligible mass, \(0.200 \mathrm{~kg}\) of ice at an initial temperature of \(-40.0^{\circ} \mathrm{C}\) is mixed with a mass \(m\) of water that has an initial temperature of \(80.0^{\circ} \mathrm{C}\). No heat is lost to the surroundings. If the final temperature of the system is \(28.0^{\circ} \mathrm{C},\) what is the mass \(m\) of the water that was initially at \(80.0^{\circ} \mathrm{C}\) ?

Convert the following Celsius temperatures to Fahrenheit: (a) \(-62.8^{\circ} \mathrm{C}\), the lowest temperature ever recorded in North America (February \(3,1947,\) Snag, Yukon); (b) \(56.7^{\circ} \mathrm{C},\) the highest temperature ever recorded in the United States (July \(10,1913,\) Death Valley, California); (c) \(31.1^{\circ} \mathrm{C},\) the world's highest average annual temperature (Lugh Ferrandi, Somalia).

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