/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 One suggested treatment for a pe... [FREE SOLUTION] | 91Ó°ÊÓ

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One suggested treatment for a person who has suffered a stroke is immersion in an ice-water bath at \(0^{\circ} \mathrm{C}\) to lower the body temperature, which prevents damage to the brain. In one set of tests, patients were cooled until their internal temperature reached \(32.0^{\circ} \mathrm{C}\). To treat a \(70.0 \mathrm{~kg}\) patient, what is the minimum amount of ice (at \(0^{\circ} \mathrm{C}\) ) you need in the bath so that its temperature remains at \(0^{\circ} \mathrm{C} ?\) The specific heat of the human body is \(3480 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{C}^{\circ},\) and recall that normal body temperature is \(37.0^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The minimum amount of ice required so that its temperature remains at \(0^{\circ} C\) is approximately 3.66 kg.

Step by step solution

01

Determine the heat lost by the patient

First we have to calculate the amount of heat the patient's body will lose when the body temperature drops from \(37.0^{\circ} C\) to \(32.0^{\circ} C\). We use the formula \( q = mc \Delta T \), where \( m = 70.0 kg \) is the mass of the patient, \( c = 3480 J/kgâ‹…^{\circ} C \) is the specific heat of the human body, and \( \Delta T = 37.0^{\circ} C - 32.0^{\circ} C = 5.0^{\circ} C \) is the change in body temperature. So, \( q = 70.0 kg \times 3480 J/kgâ‹…^{\circ} C \times 5.0^{\circ} C = 1.22 \times 10^6 J \)
02

Determine the amount of ice required

Now we need to calculate how much ice is needed to absorb this heat. When ice melts, it absorbs heat from the surroundings, and each gram of ice absorbs 334 J to change state from solid to liquid, still at \(0^{\circ} C\). The mass \( m \) of ice required will be the heat divided by the heat absorbed per gram of ice i.e., \( m = q/L_f \), where \( L_f = 334 J/g \) (latent heat of fusion of ice). So, m = \(1.22 \times 10^6 J / 334 J/g = 3660 g or 3.66 kg\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
Specific heat capacity is a property that tells us how much heat energy is required to raise the temperature of a unit mass of a substance by one degree Celsius. It basically measures a material's ability to hold heat. In the provided exercise, we talk about the specific heat capacity of the human body, which is given as \(3480 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{C}^{\circ}\). Understand this: the higher the specific heat capacity, the more heat is needed to increase the temperature, making the substance a good candidate for thermal treatments like preventing brain damage post-stroke by cooling.

When the patient's body temperature decreases, heat is transferred out of the body and absorbed by the surroundings. This concept is crucial for medical procedures that require precise temperature control, such as the one described where lowering the body temperature is key to the patient's recovery.
Latent Heat of Fusion
Latent heat of fusion is the amount of heat energy required to change the state of a substance from solid to liquid at its melting point, without changing its temperature. It is a crucial concept when dealing with phase changes, like melting ice in our exercise. For ice, the latent heat of fusion is \(334 J/g\), meaning each gram of ice needs to absorb 334 joules to melt.

The exercise mentions using ice to absorb the heat from the patient, taking advantage of the ice's latent heat of fusion. Since the temperature during the phase change remains constant, the ice can absorb a significant amount of heat energy without increasing in temperature, which is exactly what's needed to maintain a steady water temperature in the ice-water bath.
Heat Transfer
Heat transfer involves the movement of thermal energy from one object or material to another. In the realms of medicine and thermal physics, understanding how heat transfer works is fundamental for safely changing a patient's body temperature. There are three mechanisms of heat transfer: conduction, convection, and radiation. In our exercise, the key aspect of heat transfer is through the melting of ice, which is a combination of conduction (direct contact transfer) and the phase change absorption. This heat transfer keeps the water in the bath at a steady \(0^\circ \mathrm{C}\).

Remember, efficient heat transfer mechanisms are vital in medical applications to prevent overheating or undercooling, which can be detrimental to patient health.
Temperature Change in Thermal Systems
In any thermal system, the temperature change is the difference observed in the system's temperature when heat is added or removed. The principle of energy conservation plays a vital role here. As the patient's body temperature decreases, heat is conserved by transferring to the surrounding ice-water bath, maintaining thermal equilibrium.

The exercise illustrates this when the patient's body temperature drops from \(37.0^\circ \mathrm{C}\) to \(32.0^\circ \mathrm{C}\). Monitoring and controlling temperature changes are crucial in medical treatments to prevent tissue damage and, in the case of stroke patients, to limit brain damage by reducing metabolic rates.

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Most popular questions from this chapter

A copper sphere with density \(8900 \mathrm{~kg} / \mathrm{m}^{3},\) radius \(5.00 \mathrm{~cm}\) and emissivity \(e=1.00\) sits on an insulated stand. The initial temperature of the sphere is \(300 \mathrm{~K}\). The surroundings are very cold, so the rate of absorption of heat by the sphere can be neglected. (a) How long does it take the sphere to cool by \(1.00 \mathrm{~K}\) due to its radiation of heat energy? Neglect the change in heat current as the temperature decreases. (b) To assess the accuracy of the approximation used in part (a), what is the fractional change in the heat current \(H\) when the temperature changes from \(300 \mathrm{~K}\) to \(299 \mathrm{~K} ?\)

A machinist bores a hole of diameter \(1.35 \mathrm{~cm}\) in a steel plate that is at \(25.0^{\circ} \mathrm{C}\). What is the cross-sectional area of the hole (a) at \(25.0^{\circ} \mathrm{C}\) and \((\mathrm{b})\) when the temperature of the plate is increased to \(175^{\circ} \mathrm{C} ?\) Assume that the coefficient of linear expansion remains constant over this temperature range.

A steel wire has density \(7800 \mathrm{~kg} / \mathrm{m}^{3}\) and mass \(2.50 \mathrm{~g}\). It is stretched between two rigid supports separated by \(0.400 \mathrm{~m}\). (a) When the temperature of the wire is \(20.0^{\circ} \mathrm{C}\), the frequency of the fundamental standing wave for the wire is \(440 \mathrm{~Hz}\). What is the tension in the wire? (b) What is the temperature of the wire if its fundamental standing wave has frequency \(460 \mathrm{~Hz}\) ? For steel the coefficient of linear expansion is \(1.2 \times 10^{-5} \mathrm{~K}^{-1}\) and Young's modulus is \(20 \times 10^{10} \mathrm{~Pa}\)

One end of an insulated metal rod is maintained at \(100.0^{\circ} \mathrm{C}\), and the other end is maintained at \(0.00^{\circ} \mathrm{C}\) by an ice-water mixture. The rod is \(60.0 \mathrm{~cm}\) long and has a cross-sectional area of \(1.25 \mathrm{~cm}^{2}\). The heat conducted by the rod melts \(8.50 \mathrm{~g}\) of ice in \(10.0 \mathrm{~min} .\) Find the thermal conductivity \(k\) of the metal.

A copper pot with a mass of \(0.500 \mathrm{~kg}\) contains \(0.170 \mathrm{~kg}\) of water, and both are at \(20.0^{\circ} \mathrm{C}\). A \(0.250 \mathrm{~kg}\) block of iron at \(85.0^{\circ} \mathrm{C}\) is dropped into the pot. Find the final temperature of the system, assuming no heat loss to the surroundings.

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