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(a) Normal body temperature. The average normal body temperature measured in the mouth is \(310 \mathrm{~K}\). What would Celsius and Fahrenheit thermometers read for this temperature? (b) Elevated body temperature. During very vigorous exercise, the body's temperature can go as high as \(40^{\circ} \mathrm{C}\). What would Kelvin and Fahrenheit thermometers read for this temperature? (c) Temperature difference in the body. The surface temperature of the body is normally about \(7 \mathrm{C}^{\circ}\) lower than the internal temperature. Express this temperature difference in kelvins and in Fahrenheit degrees. (d) Blood storage. Blood stored at \(4.0^{\circ} \mathrm{C}\) lasts safely for about 3 weeks, whereas blood stored at \(-160^{\circ} \mathrm{C}\) lasts for 5 years. Express both temperatures on the Fahrenheit and Kelvin scales. (e) Heat stroke. If the body's temperature is above \(105^{\circ} \mathrm{F}\) for a prolonged period, heat stroke can result. Express this temperature on the Celsius and Kelvin scales.

Short Answer

Expert verified
For a normal body, Celsius would read \(36.85 ^{\circ}C\) and Fahrenheit \(98.33 ^{\circ}F\). For vigorous exercise, Kelvin would read \(313.15 K\) and Fahrenheit \(104 ^{\circ}F\). The difference in internal and external body temperature is \(7 K\) or \(12.6 ^{\circ}F\). The blood storage temperature for 3 weeks is \(39.2 ^{\circ}F\) or \(277.15 K\), and for 5 years is \(-256 ^{\circ}F\) or \(113.15 K\). The temperature for potential heat stroke is \(40.56^{\circ}C\) or \(313.71 K\).

Step by step solution

01

Convert Body Temperature to Celsius and Fahrenheit

Given the average body temperature is \(310 \mathrm{~K}\), in Celsius, \( C = K - 273.15 = 310 - 273.15 = 36.85 ^{\circ}C \). In Fahrenheit, use the converted Celsius value: \( F = 9/5(C) + 32 = 9/5(36.85) + 32 = 98.33 ^{\circ}F \).
02

Temperature During Vigorous Exercise

Elevated body temperature is \(40^{\circ} C\). In Kelvin, \( K = C + 273.15 = 40 + 273.15 = 313.15 K \). In Fahrenheit, \( F = 9/5(C) + 32 = 9/5(40) + 32 = 104 ^{\circ}F \).
03

Temperature Differences

Given the temperature difference is \(7^{\circ} \mathrm{C}\). This difference in Celsius is same as Kelvin, so, difference = \(7 K\). In Fahrenheit, use the difference in Celsius without adding the 32 constant: diff = \(9/5(7) = 12.6 ^{\circ}F\).
04

Blood Storage Temperatures

Temperature of blood when safely stored for 3 weeks and 5 years are \(4^{\circ} C\) and \(-160^{\circ} C\). In Fahrenheit, \( F1 = 9/5(4) + 32 = 39.2 ^{\circ}F \) and \( F2 = 9/5(-160) + 32 = -256 ^{\circ}F \). In Kelvin, \( K1 = 4 + 273.15 = 277.15 K \) and \( K2 = -160 + 273.15 = 113.15 K \).
05

Temperature Leading to Heat Stroke

Body temperature above which heat stroke can result is \(105^{\circ} F\). In Celsius, \( C = 5/9(F - 32) = 5/9(105 - 32) = 40.56^{\circ}C \). In Kelvin, \( K = C + 273.15 = 40.56 + 273.15 = 313.71 K \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kelvin to Celsius Conversion
Understanding the relationship between Kelvin and Celsius is crucial in physics and everyday life. Kelvin is the base unit of temperature in the International System of Units (SI), and it's an absolute scale starting at absolute zero, the theoretical point where all kinetic motion in atoms ceases.

To convert from Kelvin to Celsius, you subtract 273.15 from the Kelvin value. The formula is quite simple: \( C = K - 273.15 \). So when you have a body temperature of \(310 K\), applying this formula gives you \( C = 310K - 273.15 = 36.85^{\textdegree}C \). This means that the average normal body temperature in Celsius is about \(36.85^{\textdegree}C\), which is close to the commonly cited \(37^{\textdegree}C\).

When dealing with temperature changes or differences, the degree of change is the same in Kelvin as in Celsius. This is because both scales increase at the same rate: a one-degree increase in Celsius corresponds to a one-degree increase in Kelvin.
Celsius to Fahrenheit Conversion
When converting temperatures from Celsius to Fahrenheit, which is common in countries like the United States, the formula to use is \( F = \frac{9}{5}C + 32 \). Knowing this formula allows you to grasp the temperature readings in a format you might be more familiar with.

For instance, the vigorous body temperature of \(40^{\textdegree}C\) would be converted to Fahrenheit by multiplying the Celsius temperature by \(\frac{9}{5}\) and then adding 32: \( F = \frac{9}{5}(40) + 32 = 104^{\textdegree}F \).

Similarly, for a body temperature that can lead to heat stroke at \(105^{\textdegree}F\), you can convert it back to Celsius using the inverse formula \( C = \frac{5}{9}(F - 32) \). Applied to this situation: \( C = \frac{5}{9}(105 - 32) = 40.56^{\textdegree}C \). Temperature conversions like these are practical not only in scientific settings but also in cooking, travel, and many other aspects of life.
Body Temperature Regulation
Body temperature regulation is a vital aspect of human physiology. It's the process by which our bodies maintain a stable internal temperature despite changes in the external environment. This temperature is generally around \(36.5^{\textdegree}C\) to \(37.5^{\textdegree}C\), or \(310 K\) on the Kelvin scale. The human body has several mechanisms in place to regulate temperature, including perspiration, shivering, expanding or constricting blood vessels, and metabolic adjustments.

During exercise, the body temperature can rise significantly, typically to about \(40^{\textdegree}C\) or \(313.15 K\), because of the increased metabolic rate. If body temperature rises above \(105^{\textdegree}F\) (\(40.56^{\textdegree}C\) or \(313.71 K\)), it could lead to heat stroke, a severe medical emergency requiring immediate attention.

The understanding of body temperature regulation is not only important for staying healthy but also for understanding the conditions under which the human body performs optimally.
Temperature Scales in Physics
In physics, understanding different temperature scales is essential. The primary scales are Celsius, Fahrenheit, and Kelvin. Each scale has its own uses, applications, and conversion formulas.

The Celsius scale is based on the properties of water, with \(0^{\textdegree}C\) being the freezing point of water and \(100^{\textdegree}C\) as its boiling point at standard atmospheric pressure. Fahrenheit, on the other hand, has its points of reference determined by a combination of various factors, and the freezing point of water is \(32^{\textdegree}F\), with the boiling point at \(212^{\textdegree}F\).

Kelvin is the scale used most in scientific measurements because it is an absolute temperature scale with its zero point at absolute zero, where theoretically no more thermal energy can be removed from a system.

In physics, temperatures are often measured in Kelvin for consistency and because it simplifies many physical laws, removing negative numbers from equations involving thermodynamics and kinetics.

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Most popular questions from this chapter

If the air temperature is the same as the temperature of your skin (about \(30^{\circ} \mathrm{C}\) ), your body cannot get rid of heat by transferring it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During bicycling, a typical \(70 \mathrm{~kg}\) person's body produces energy at a rate of about \(500 \mathrm{~W}\) due to metabolism, \(80 \%\) of which is converted to heat. (a) How many kilograms of water must the person's body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is \(2.42 \times 10^{6} \mathrm{~J} / \mathrm{kg} .\) (b) The evaporated water must, of course, be replenished, or the person will dehydrate. How many \(750 \mathrm{~mL}\) bottles of water must the bicyclist drink per hour to replenish the lost water? (Recall that the mass of a liter of water is \(1.0 \mathrm{~kg} .\) )

The emissivity of tungsten is 0.350 . A tungsten sphere with radius \(1.50 \mathrm{~cm}\) is suspended within a large evacuated enclosure whose walls are at \(290.0 \mathrm{~K}\). What power input is required to maintain the sphere at \(3000.0 \mathrm{~K}\) if heat conduction along the supports is ignored?

The rate at which radiant energy from the sun reaches the earth's upper atmosphere is about \(1.50 \mathrm{~kW} / \mathrm{m}^{2} .\) The distance from the earth to the sun is \(1.50 \times 10^{11} \mathrm{~m},\) and the radius of the sun is \(6.96 \times 10^{8} \mathrm{~m} .\) (a) What is the rate of radiation of energy per unit area from the sun's surface? (b) If the sun radiates as an ideal blackbody, what is the temperature of its surface?

Size of a Light-Bulb Filament. The operating temperature of a tungsten filament in an incandescent light bulb is \(2450 \mathrm{~K},\) and its emissivity is \(0.350 .\) Find the surface area of the filament of a \(150 \mathrm{~W}\) bulb if all the electrical energy consumed by the bulb is radiated by the filament as electromagnetic waves. (Only a fraction of the radiation appears as visible light.)

A machinist bores a hole of diameter \(1.35 \mathrm{~cm}\) in a steel plate that is at \(25.0^{\circ} \mathrm{C}\). What is the cross-sectional area of the hole (a) at \(25.0^{\circ} \mathrm{C}\) and \((\mathrm{b})\) when the temperature of the plate is increased to \(175^{\circ} \mathrm{C} ?\) Assume that the coefficient of linear expansion remains constant over this temperature range.

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