/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 You live on a busy street, but a... [FREE SOLUTION] | 91Ó°ÊÓ

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You live on a busy street, but as a music lover, you want to reduce the traffic noise. (a) If you install special sound-reflecting windows that reduce the sound intensity level (in \(\mathrm{dB}\) ) by \(30 \mathrm{~dB}\), by what fraction have you lowered the sound intensity (in \(\left.\mathrm{W} / \mathrm{m}^{2}\right) ?\) (b) If, instead, you reduce the intensity by half, what change (in \(\mathrm{dB}\) ) do you make in the sound intensity level?

Short Answer

Expert verified
a) The sound intensity is reduced by a factor of 1000. b) Halving the intensity corresponds to a decrease of about 3 dB.

Step by step solution

01

Formula for decibel

Firstly, we will need to use the formula for decibels, which is \(dB = 10 \cdot log_{10}\left(\frac{I}{I_0}\right)\) where \(I\) is the sound intensity, \(I_0\) is the reference sound intensity (usually the quietest sound that the human ear can hear, \(1 \times 10^{-12} W/m^2\) ), and \(log_{10}\) is a logarithm in base 10.
02

Calculate fraction decrease in intensity for a 30 dB decrease

We need to calculate by what fraction we've decreased the intensity when we decrease the sound level by 30 dB. We rearrange the formula to get \(I/I_0 = 10^{dB/10}\). If we decrease sound level by 30 dB, then \(dB = -30\), and we find that \(I/I_0 = 10^{-30/10} = 10^{-3}\). So the intensity is reduced to one thousandth of its original value, or it's reduced by a factor of 1000.
03

Calculate the change in dB for halving the intensity

In the second part of the problem, we need to find out how much the sound level changes (in dB) if we reduce the intensity to half. We set \(I/I_0 = 1/2\) in the formula for decibels, and solve for \(dB = 10 \cdot log_{10}(1/2) \approx -3 dB\). So decreasing the intensity by half corresponds to a decrease in sound level of about 3 dB.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Formula
When we delve into the study of sound, understanding the decibel formula is crucial for quantifying sound levels in a meaningful way. The formula is expressed as: \[\begin{equation} dB = 10 \times \text{log}_{10}\bigg(\frac{I}{I_0}\bigg) \text{where:} \end{equation}\]
  • \text{\textbf{dB}} - is the sound level in decibels,
  • \text{\textbf{I}} - represents the sound intensity of the noise you are measuring, and
  • \text{\textbf{I}}_0 - is the reference sound intensity, typically set at the threshold of hearing (1 \times 10^{-12} W/m^2).
In this context, sound intensity, denoted by \text{\textbf{I}}, refers to the amount of sound energy passing through a unit area in a unit time and is measured in watts per square meter (W/m^2). The reference intensity, \text{\textbf{I}}_0, is significant because it provides a common baseline for consistent measurements across different scenarios.

The formula highlights a logarithmic relationship between the actual sound intensity and its perceived level in decibels. This is why a 30 dB reduction in sound translates into a significant decrease in intensity, reducing it to one thousandth of its original value, as indicated by the formula: \[\begin{equation} I/I_0 = 10^{-30/10} = 10^{-3}\text{.}\end{equation}\]
Logarithmic Scale
The concept of a logarithmic scale is fundamental to understanding how we perceive changes in sound levels. Our hearing does not respond linearly to changes in sound intensity; hence, the logarithmic decibel scale is utilized. A logarithmic scale means that each equal step in decibel value represents a tenfold increase or decrease in sound intensity. Hence, what might seem like a small numeric change in dB can represent a significant change in actual sound intensity.

For example, if one sound is 10 dB higher than another, it's not just 'a little' louder; it's 10 times more intense. This is critical when considering the sound level reduction in an environment. Reducing sound intensity by just a few decibels, as seen in the exercise where a halving of the intensity reduces the sound level by approximately 3 dB, can have a noticeable impact on what we hear. The logarithmic nature of the decibel scale allows us to capture the full range of human hearing, from the quietest sounds to the threshold of pain, in a manageable numerical range.
Sound Intensity Physics
Fundamentally, sound is a mechanical wave that propagates through a medium, such as air, transferring energy as it travels. Sound intensity physics focuses on the power carried by these sound waves per unit area. In an equation, sound intensity (\text{\textbf{I}}) is given by the rate at which energy (\text{\textbf{E}}) flows through a specified area (\text{\textbf{A}}). That is: \[\begin{equation} I = \frac{\text{Energy}}{\text{Area} \times \text{Time}} = \frac{E}{A \times t}\end{equation}\]This is why sound intensity is measured in units of watts per square meter (W/m^2).Subtle changes in intensity can make a big difference in how we experience sound. The physical principles behind how sound intensity affects the human ear underscore the importance of materials and technologies that can reduce any unwanted noise. For instance, in the exercise, the use of sound-reflecting windows demonstrates the application of these principles in a real-world context, giving a quantifiable difference in one’s auditory environment.

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Most popular questions from this chapter

A loud factory machine produces sound having a displacement amplitude of \(1.00 \mu \mathrm{m}\), but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to \(10.0 \mathrm{~Pa}\). Under the conditions of this factory, the bulk modulus of air is \(1.42 \times 10^{5} \mathrm{~Pa}\). What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit? Is this frequency audible to the workers?

A \(2.00 \mathrm{MHz}\) sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 72 beats per second are detected. The speed of sound in body tissue is \(1500 \mathrm{~m} / \mathrm{s}\). Calculate the speed of the fetal heart wall at the instant this measurement is made.

A turntable \(1.50 \mathrm{~m}\) in diameter rotates at \(75 \mathrm{rpm} .\) Two speakers, each giving off sound of wavelength \(31.3 \mathrm{~cm},\) are attached to the rim of the table at opposite ends of a diameter. A listener stands in front of the turntable. (a) What is the greatest beat frequency the listener will receive from this system? (b) Will the listener be able to distinguish individual beats?

A railroad train is traveling at \(25.0 \mathrm{~m} / \mathrm{s}\) in still air. The frequency of the note emitted by the locomotive whistle is \(400 \mathrm{~Hz}\). What is the wavelength of the sound waves (a) in front of the locomotive and (b) behind the locomotive? What is the frequency of the sound heard by a stationary listener (c) in front of the locomotive and (d) behind the locomotive?

A long tube contains air at a pressure of 1.00 atm and a temperature of \(77.0^{\circ} \mathrm{C}\). The tube is open at one end and closed at the other by a movable piston. A tuning fork that vibrates with a frequency of \(500 \mathrm{~Hz}\) is placed near the open end. Resonance is produced when the piston is at distances \(18.0 \mathrm{~cm}, 55.5 \mathrm{~cm},\) and \(93.0 \mathrm{~cm}\) from the open end. (a) From these values, what is the speed of sound in air at \(77.0^{\circ} \mathrm{C}\) ? (b) From the result of part (a), what is the value of \(\gamma ?\) (c) These results show that a displacement antinode is slightly outside the open end of the tube. How far outside is it?

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