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Standing waves are produced on a string that is held fixed at both ends. The tension in the string is kept constant. (a) For the second overtone standing wave the node-to-node distance is \(8.00 \mathrm{~cm} .\) What is the length of the string? (b) What is the node-to-node distance for the fourth harmonic standing wave?

Short Answer

Expert verified
The total length of the string is \(24.00 cm\) and the node-to-node distance for the fourth harmonic standing wave is \(6.00 cm\).

Step by step solution

01

Calculate the total length of the string

Since the second overtone is the equivalent to the third harmonic, the string is three half-wavelengths long. Hence, the length of the string can be found by multiplying the given node-to-node distance by three: \[ L = 3(8.00 cm) = 24.00 cm \]
02

Calculate the node-to-node distance for the fourth harmonic

The fourth harmonic is equivalent to four half-wavelengths or two full wavelengths. Therefore, the node-to-node distance can be found by dividing the total length of the string by the harmonic number: \[ d = L/4 = 24.00 cm/ 4 = 6.00 cm \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Series

Understanding the harmonic series is essential to grasp the behavior of waves in musical instruments and many physical systems. The harmonic series in waves describes the resonant frequencies at which a system vibrates. These are also known as the natural frequencies or harmonics. For a string fixed at both ends – such as a guitar string – these harmonics are integer multiples of the fundamental frequency. The first harmonic, which is the lowest frequency, is called the fundamental. Each subsequent harmonic frequency will be twice, three times, four times, etc., the fundamental frequency.

  • The second harmonic is also known as the first overtone.
  • The third harmonic corresponds to the second overtone, and so on.

When we talk about, for instance, the 'second overtone', we are referring to the third harmonic in the series, which relates to three half-wavelengths of the string being present. For students, remembering this relationship between overtones and harmonics can significantly simplify understanding standing waves and related exercises.

Wavelength Calculation

Wavelength calculation is fundamental in understanding waves, be they on a string, in a column of air, or even light. The wavelength \( \lambda \) is the distance over which the wave's shape repeats. It is inversely proportional to the frequency: the higher the frequency, the shorter the wavelength. For standing waves on a string, many students struggle with visualizing how the calculated distance translates to the actual wave.

In the exercise, the relationship between the second overtone (third harmonic) and the wave's length is crucial. If we know the distance between nodes (points of no displacement on the standing wave), we can calculate the string’s wavelength and then find the entire length of the string.

The pattern is as follows:

  • For the first harmonic (fundamental frequency), the wavelength is twice the string length.
  • For the second harmonic, the wavelength is equal to the string length.
  • For the third harmonic, the wavelength is two-thirds the string length, and so on.

Armed with this knowledge, students can confidently calculate wavelengths and solve related problems.

Vibrations in Strings

Vibrations in strings are a model for various physical phenomena and are widely taught in physics for their principles of wave behavior and harmonics. When a string is plucked or struck, it vibrates, and these vibrations produce standing waves. The stationary points, where there is no vertical motion, are called nodes, and the points of maximum displacement are called antinodes.

For a string fixed at both ends:

  • The length of the string must accommodate whole numbers of half-wavelengths to support standing waves.
  • Vibrational patterns form based on how many half-wavelengths fit within the string, which define the harmonics. For example, the fundamental mode has just one antinode, and each overtone adds more.

The tension and linear density of the string affect the speed of the wave and thus its frequency. In practice, this concept is applied when tuning stringed instruments or in engineering when analyzing the vibrational modes of structures.

By understanding harmonics and the role of string tension, students can better conceptualize how strings vibrate and predict the wave patterns that emerge.

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Most popular questions from this chapter

Energy Output. By measurement you determine that sound waves are spreading out equally in all directions from a point source and that the intensity is \(0.026 \mathrm{~W} / \mathrm{m}^{2}\) at a distance of \(4.3 \mathrm{~m}\) from the source. (a) What is the intensity at a distance of \(3.1 \mathrm{~m}\) from the source? (b) How much sound energy does the source emit in one hour if its power output remains constant?

A string or rope will break apart if it is placed under too much tensile stress [see Eq. (11.8)]. Thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. One type of steel has density \(7800 \mathrm{~kg} / \mathrm{m}^{3}\) and will break if the tensile stress exceeds \(7.0 \times 10^{8} \mathrm{~N} / \mathrm{m}^{2}\). You want to make a guitar string from \(4.0 \mathrm{~g}\) of this type of steel. In use, the guitar string must be able to withstand a tension of \(900 \mathrm{~N}\) without breaking. Your job is to determine (a) the maximum length and minimum radius the string can have; (b) the highest possible fundamental frequency of standing waves on this string, if the entire length of the string is free to vibrate.

A \(1.50-\mathrm{m}\) -long rope is stretched between two supports with a tension that makes the speed of transverse waves \(62.0 \mathrm{~m} / \mathrm{s}\). What are the wavelength and frequency of (a) the fundamental; (b) the second overtone; (c) the fourth harmonic?

A transverse sine wave with an amplitude of \(2.50 \mathrm{~mm}\) and a wavelength of \(1.80 \mathrm{~m}\) travels from left to right along a long, horizontal, stretched string with a speed of \(36.0 \mathrm{~m} / \mathrm{s}\). Take the origin at the left end of the undisturbed string. At time \(t=0\) the left end of the string has its maximum upward displacement. (a) What are the frequency, angular frequency, and wave number of the wave? (b) What is the function \(y(x, t)\) that describes the wave? (c) What is \(y(t)\) for a particle at the left end of the string? (d) What is \(y(t)\) for a particle \(1.35 \mathrm{~m}\) to the right of the origin? (e) What is the maximum magnitude of transverse velocity of any particle of the string? (f) Find the transverse displacement and the transverse velocity of a particle \(1.35 \mathrm{~m}\) to the right of the origin at time \(t=0.0625 \mathrm{~s}\)

A musician tunes the C-string of her instrument to a fundamental frequency of \(65.4 \mathrm{~Hz}\). The vibrating portion of the string is \(0.600 \mathrm{~m}\) long and has a mass of \(14.4 \mathrm{~g}\). (a) With what tension must the musician stretch it? (b) What percent increase in tension is needed to increase the frequency from \(65.4 \mathrm{~Hz}\) to \(73.4 \mathrm{~Hz}\), corresponding to a rise in pitch from \(\mathrm{C}\) to \(\mathrm{D}\) ?

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