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Standing waves are produced on a string that is held fixed at both ends. The tension in the string is kept constant. (a) For the second overtone standing wave the node-to-node distance is \(8.00 \mathrm{~cm} .\) What is the length of the string? (b) What is the node-to-node distance for the fourth harmonic standing wave?

Short Answer

Expert verified
The total length of the string is \(24.00 cm\) and the node-to-node distance for the fourth harmonic standing wave is \(6.00 cm\).

Step by step solution

01

Calculate the total length of the string

Since the second overtone is the equivalent to the third harmonic, the string is three half-wavelengths long. Hence, the length of the string can be found by multiplying the given node-to-node distance by three: \[ L = 3(8.00 cm) = 24.00 cm \]
02

Calculate the node-to-node distance for the fourth harmonic

The fourth harmonic is equivalent to four half-wavelengths or two full wavelengths. Therefore, the node-to-node distance can be found by dividing the total length of the string by the harmonic number: \[ d = L/4 = 24.00 cm/ 4 = 6.00 cm \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Series

Understanding the harmonic series is essential to grasp the behavior of waves in musical instruments and many physical systems. The harmonic series in waves describes the resonant frequencies at which a system vibrates. These are also known as the natural frequencies or harmonics. For a string fixed at both ends – such as a guitar string – these harmonics are integer multiples of the fundamental frequency. The first harmonic, which is the lowest frequency, is called the fundamental. Each subsequent harmonic frequency will be twice, three times, four times, etc., the fundamental frequency.

  • The second harmonic is also known as the first overtone.
  • The third harmonic corresponds to the second overtone, and so on.

When we talk about, for instance, the 'second overtone', we are referring to the third harmonic in the series, which relates to three half-wavelengths of the string being present. For students, remembering this relationship between overtones and harmonics can significantly simplify understanding standing waves and related exercises.

Wavelength Calculation

Wavelength calculation is fundamental in understanding waves, be they on a string, in a column of air, or even light. The wavelength \( \lambda \) is the distance over which the wave's shape repeats. It is inversely proportional to the frequency: the higher the frequency, the shorter the wavelength. For standing waves on a string, many students struggle with visualizing how the calculated distance translates to the actual wave.

In the exercise, the relationship between the second overtone (third harmonic) and the wave's length is crucial. If we know the distance between nodes (points of no displacement on the standing wave), we can calculate the string’s wavelength and then find the entire length of the string.

The pattern is as follows:

  • For the first harmonic (fundamental frequency), the wavelength is twice the string length.
  • For the second harmonic, the wavelength is equal to the string length.
  • For the third harmonic, the wavelength is two-thirds the string length, and so on.

Armed with this knowledge, students can confidently calculate wavelengths and solve related problems.

Vibrations in Strings

Vibrations in strings are a model for various physical phenomena and are widely taught in physics for their principles of wave behavior and harmonics. When a string is plucked or struck, it vibrates, and these vibrations produce standing waves. The stationary points, where there is no vertical motion, are called nodes, and the points of maximum displacement are called antinodes.

For a string fixed at both ends:

  • The length of the string must accommodate whole numbers of half-wavelengths to support standing waves.
  • Vibrational patterns form based on how many half-wavelengths fit within the string, which define the harmonics. For example, the fundamental mode has just one antinode, and each overtone adds more.

The tension and linear density of the string affect the speed of the wave and thus its frequency. In practice, this concept is applied when tuning stringed instruments or in engineering when analyzing the vibrational modes of structures.

By understanding harmonics and the role of string tension, students can better conceptualize how strings vibrate and predict the wave patterns that emerge.

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Most popular questions from this chapter

You are exploring a newly discovered planet. The radius of the planet is \(7.20 \times 10^{7} \mathrm{~m}\). You suspend a lead weight from the lower end of a light string that is \(4.00 \mathrm{~m}\) long and has mass \(0.0280 \mathrm{~kg}\). You measure that it takes \(0.0685 \mathrm{~s}\) for a transverse pulse to travel from the lower end to the upper end of the string. On the earth, for the same string and lead weight, it takes \(0.0390 \mathrm{~s}\) for a transverse pulse to travel the length of the string. The weight of the string is small enough that you ignore its effect on the tension in the string. Assuming that the mass of the planet is distributed with spherical symmetry, what is its mass?

A thin, \(75.0 \mathrm{~cm}\) wire has a mass of \(16.5 \mathrm{~g}\). One end is tied to a nail, and the other end is attached to a screw that can be adjusted to vary the tension in the wire. (a) To what tension (in newtons) must you adjust the screw so that a transverse wave of wavelength \(3.33 \mathrm{~cm}\) makes 625 vibrations per second? (b) How fast would this wave travel?

The speed of sound in air at \(20^{\circ} \mathrm{C}\) is \(344 \mathrm{~m} / \mathrm{s}\). (a) What is the wavelength of a sound wave with a frequency of \(784 \mathrm{~Hz}\), corresponding to the note \(\mathrm{G}_{5}\) on a piano, and how many milliseconds does each vibration take? (b) What is the wavelength of a sound wave one octave higher (twice the frequency) than the note in part (a)?

You are designing a two-string instrument with metal strings \(35.0 \mathrm{~cm}\) long, as shown in Fig. \(\mathrm{P} 15.52 .\) Both strings are under the same tension. String \(S_{1}\) has a mass of \(8.00 \mathrm{~g}\) and produces the note middle \(\mathrm{C}\) (frequency \(262 \mathrm{~Hz}\) ) in its fundamental mode. (a) What should be the tension in the string? (b) What should be the mass of string \(S_{2}\) so that it will produce A-sharp (frequency \(466 \mathrm{~Hz}\) ) as its fundamental? (c) To extend the range of your instrument, you include a fret located just under the strings but not normally touching them. How far from the upper end should you put this fret so that when you press \(S_{1}\) tightly against it, this string will produce \(\mathrm{C}\) -sharp (frequency \(277 \mathrm{~Hz}\) ) in its fundamental? That is, what is \(x\) in the figure? (d) If you press \(S_{2}\) against the fret, what frequency of sound will it produce in its fundamental?

One end of a horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates the rope transversely at \(120 \mathrm{~Hz}\). The other end passes over a pulley and supports a \(1.50 \mathrm{~kg}\) mass. The linear mass density of the rope is \(0.0480 \mathrm{~kg} / \mathrm{m} .\) (a) What is the speed of a transverse wave on the rope? (b) What is the wavelength? (c) How would your answers to parts (a) and (b) change if the mass were increased to \(3.00 \mathrm{~kg} ?\)

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