/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Standing waves on a wire are des... [FREE SOLUTION] | 91Ó°ÊÓ

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Standing waves on a wire are described by Eq. (15.28), with \(A_{\mathrm{SW}}=2.50 \mathrm{~mm}, \omega=942 \mathrm{rad} / \mathrm{s},\) and \(k=0.750 \pi \mathrm{rad} / \mathrm{m} .\) The left end of the wire is at \(x=0 .\) At what distances from the left end are (a) the nodes of the standing wave and (b) the antinodes of the standing wave?

Short Answer

Expert verified
The positions of the nodes are \(x_n = \frac{n}{0.750}\) m and the positions of the antinodes are \(x_a = \frac{(2n+1)}{1.50}\) m, where \(n\) is an integer.

Step by step solution

01

Understanding the property of a node

A node is a point of zero amplitude. In a standing wave, the nodes occur where \(kx = n\pi\), where \(n\) is an integer.
02

Calculation of node positions

Rearrange the equation \(kx = n\pi\) to find \(x\). Given that \(k = 0.750\pi \) rad/m, the equation becomes \(x_n = \frac{n}{0.750}\) m, for \(n = 0, 1, 2, 3, ... \).
03

Understanding the property of an antinode

An antinode is a point of maximum amplitude. In a standing wave, the antinodes occur where \(kx = (n+1/2)\pi\), where \(n\) is an integer.
04

Calculation of antinode positions

Rearrange the equation \(kx = (n+1/2)\pi\) to find \(x\). Given that \(k = 0.750\pi \) rad/m, the equation becomes \(x_a = \frac{(2n+1)}{1.50}\) m, for \(n = 0, 1, 2, 3, ... \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Node and Antinode
Standing waves are unique phenomena where certain points called nodes and antinodes depict the extremities of motion. A node is a point along the medium where the wave has zero amplitude at all times. In simpler terms, it's a stationary point that doesn't move as the wave passes through. On the other side, an antinode is a point where the wave exhibits maximum amplitude, meaning it oscillates with the greatest possible distance from the rest point. In standing waves, these points are alternately spaced; where you find a node, an antinode will always be half a wavelength away. The difference between nodes and antinodes is a critical foundation for understanding wave behavior in various physical systems, from musical instruments to the quantum realms.

Wave Amplitude
The amplitude of a wave is indicative of its energy and is defined as the maximum distance from the equilibrium position that points on the wave reach during oscillation. For standing waves, like the ones described in our problem, the amplitude is represented by the symbol \( A_{\mathrm{SW}} \: 2.50 \mathrm{~ mm} \) indicating the peak value of the wave's displacement from its rest position. When considering standing waves on a wire, the amplitude is the distance between the center line of the wire and the highest point that it reaches. Amplitude plays a central role in the properties of a wave, affecting not just its power but also the energy transferred through the medium.

Angular Wave Number
The angular wave number, represented by the symbol \(k\), is a measure of the number of wave cycles that fit within a unit length. Technically, it relates to the spatial frequency of a wave and is proportional to 2\(\pi\) divided by the wavelength. For our standing waves on a wire, \(k = 0.750 \pi \mathrm{rad} / \mathrm{m} \), offering insight into the wave's structure and how tightly packed each oscillation is. A higher value of \(k\) means more waves per meter, implying a shorter wavelength. Angular wave number is pivotal in solving standing wave problems as it connects the general wave properties with specific positions of nodes and antinodes.

Wavelength of Standing Waves
The wavelength is the distance over which the wave's shape repeats. It determines the length between consecutive points in phase, such as node to node or antinode to antinode. For standing waves, the wavelength can be determined using the relationship between the angular wave number and the integral multiples of \(\pi\). As standing waves are formed by the interference of two waves with the same wavelength moving in opposite directions, understanding the wavelength is key to constructing and analyzing these wave patterns. It's an essential component in the calculation of both nodes and antinodes positions. In musical instruments, for instance, the wavelength governs the pitch of the note played, showing the widespread importance of this concept.

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Most popular questions from this chapter

Adjacent antinodes of a standing wave on a string are \(15.0 \mathrm{~cm}\) apart. A particle at an antinode oscillates in simple harmonic motion with amplitude \(0.850 \mathrm{~cm}\) and period \(0.0750 \mathrm{~s}\). The string lies along the \(+x\) -axis and is fixed at \(x=0 .\) (a) How far apart are the adjacent nodes? (b) What are the wavelength, amplitude, and speed of the two traveling waves that form this pattern? (c) Find the maximum and minimum transverse speeds of a point at an antinode. (d) What is the shortest distance along the string between a node and an antinode?

A piano wire with mass \(3.00 \mathrm{~g}\) and length \(80.0 \mathrm{~cm}\) is stretched with a tension of \(25.0 \mathrm{~N}\). A wave with frequency \(120.0 \mathrm{~Hz}\) and amplitude \(1.6 \mathrm{~mm}\) travels along the wire. (a) Calculate the average power carried by the wave. (b) What happens to the average power if the wave amplitude is halved?

With what tension must a rope with length \(2.50 \mathrm{~m}\) and mass \(0.120 \mathrm{~kg}\) be stretched for transverse waves of frequency \(40.0 \mathrm{~Hz}\) to have a wavelength of \(0.750 \mathrm{~m} ?\)

A \(1.005 \mathrm{~m}\) chain consists of small spherical beads, each with a mass of \(1.00 \mathrm{~g}\) and a diameter of \(5.00 \mathrm{~mm},\) threaded on an elastic strand with negligible mass such that adjacent beads are separated by a center-to-center distance of \(10.0 \mathrm{~mm}\). There are beads at each end of the chain. The strand has a spring constant of \(28.8 \mathrm{~N} / \mathrm{m}\). The chain is stretched horizontally on a frictionless tabletop to a length of \(1.50 \mathrm{~m}\), and the beads at both ends are fixed in place. (a) What is the linear mass density of the chain? (b) What is the tension in the chain? (c) With what speed would a pulse travel down the chain? (d) The chain is set vibrating and exhibits a standing-wave pattern with four antinodes. What is the frequency of this motion? (e) If the beads are numbered sequentially from 1 to \(101,\) what are the numbers of the five beads that remain motionless? (f) The 13th bead has a maximum speed of \(7.54 \mathrm{~m} / \mathrm{s}\). What is the amplitude of that bead's motion? (g) If \(x_{0}=0\) corresponds to the center of the 1 st bead and \(x_{101}=1.50 \mathrm{~m}\) corresponds to the center of the 101 st bead, what is the position \(x_{n}\) of the \(n\) th bead? (h) What is the maximum speed of the 30 th bead?

\(\mathrm{A}\) jet plane at takeoff can produce sound of intensity \(10.0 \mathrm{~W} / \mathrm{m}^{2}\) at \(30.0 \mathrm{~m}\) away. But you prefer the tranquil sound of normal conversation, which is \(1.0 \mu \mathrm{W} / \mathrm{m}^{2}\). Assume that the plane behaves like a point source of sound. (a) What is the closest distance you should live from the airport runway to preserve your peace of mind? (b) What intensity from the jet does your friend experience if she lives twice as far from the runway as you do? (c) What power of sound does the jet produce at takeoff?

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