/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 \(\mathrm{A}\) block with mass \... [FREE SOLUTION] | 91Ó°ÊÓ

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\(\mathrm{A}\) block with mass \(m\) is undergoing SHM on a horizontal, frictionless surface while attached to a light, horizontal spring that has force constant \(k\). You use motion sensor equipment to measure the maximum speed of the block during its oscillations. You repeat the measurement for the same spring and blocks of different masses while keeping the amplitude \(A\) at a constant value of \(12.0 \mathrm{~cm}\). You plot your data as \(v_{\max }^{2}\) versus \(1 / m\) and find that the data lie close to a straight line that has slope \(8.62 \mathrm{~N} \cdot \mathrm{m} .\) What is the force constant \(k\) of the spring?

Short Answer

Expert verified
The force constant \(k\) of the spring is approximately \(600 \mathrm{N/m}\)

Step by step solution

01

Write down known values

The amplitude \(A\) of the oscillation is given as \(12.0 \mathrm{cm}\) or \(0.12 \mathrm{m}\), and the slope of the graph \(m\) is given as \(8.62 \mathrm{N} \cdot \mathrm{m}\). The slope of the graph corresponds to the value of \(kA^{2}\).
02

Calculate the spring constant

Knowing that \(kA^{2}\) is equal to the slope \(m = 8.62 \mathrm{N} \cdot \mathrm{m}\), we solve for \(k\), the spring constant. The formula for the spring constant \(k\) is obtained by rearranging \(kA^{2} = m\) to get \(k = \frac{m}{A^{2}}\). Substituting the known values gives, \(k = \frac{8.62 \mathrm{N} \cdot \mathrm{m}}{(0.12 \mathrm{~m})^2}\)
03

Simplify and solve

Doing the calculation we get \(k = 599.3 \mathrm{N/m}\). So, the spring constant \(k\) is approximately \(600 \mathrm{N/m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
In simple harmonic motion (SHM), the spring constant, often denoted as \( k \), is a crucial parameter. It defines how stiff a spring is and determines the force required to stretch or compress it by a given distance. For springs, Hooke's Law states that this force \( F \) is proportional to the displacement \( x \) from its equilibrium position, mathematically given by \( F = -kx \). The negative sign indicates that the force is opposite to the displacement direction, acting to restore equilibrium.
In our exercise, we use the relationship between the maximum speed of an oscillating block and the mass to identify the spring constant. This is achieved by plotting the square of the maximum speed against the reciprocal of mass, where the slope of this line directly allows us to calculate \( k \) using the formula \( k = \frac{m}{A^2} \). This setup highlights how small deviations and relationships in SHM can be used to extract meaningful physical properties of the system.
Understanding the spring constant is fundamental, especially in physics and engineering, as it affects dynamics and energy storage in spring-mass systems.
Maximum Speed of Oscillation
The maximum speed of oscillation in simple harmonic motion is the peak speed an object attains during its motion. In our given setup, the object is a block oscillating on a frictionless surface attached to a spring. The maximum speed \( v_{max} \) of the block can be derived using the relationship \( v_{max} = A\omega \), where \( A \) is the amplitude, and \( \omega \) is the angular frequency. Angular frequency itself is calculated using the formula \( \omega = \sqrt{\frac{k}{m}} \).
The exercise effectively exemplifies how changes in mass, while keeping the spring constant and amplitude steady, influence \( v_{max} \). Observing \( v_{max}^2 \) versus \( 1/m \) draws a linear relationship, offering insights into the spring's force constant directly. Such exercises help in deepening the understanding of energy transfer, where the kinetic energy is maximum when all potential energy in the spring converts during equilibrium.
Motion Sensor Equipment
Motion sensor equipment plays an integral role in measuring various aspects of motion, including position, velocity, and acceleration. In our scenario, a motion sensor tracks the block's oscillation to measure its maximum speed accurately. These sensors typically employ technologies like infrared, ultrasound, or laser to determine object movement in real-time.
By capturing detailed data, the sensors help plot graphs like \( v_{max}^2 \) against \( 1/m \), which are instrumental in understanding the dynamics of the oscillations. This application underlines the importance of accurate data collection in physics experiments, enabling precise quantification of parameters like the spring constant, and providing an empirical foundation to theoretical models.
  • Enhances data collection accuracy
  • Facilitates visualization of motion dynamics
  • Supports empirical validation of theoretical concepts
Motion sensors bridge practical experimentation with theoretical insights, offering powerful insights into both the analyzed physical systems and the nature of simple harmonic motion itself.
Mass and Amplitude Relationship
The interaction between mass and amplitude in simple harmonic motion is an intriguing aspect of SHM systems. While amplitude \( A \) is typically a measure of the maximum extent of displacement from equilibrium, it remains constant in our experiment. Hence, the focus shifts to how variations in mass \( m \) affect the system.
In SHM, although the amplitude depends on initial conditions, the mass primarily influences the system's frequency and period. The period \( T \) of oscillation, \( T = 2\pi \sqrt{\frac{m}{k}} \), indicates that more massive objects will generally oscillate slower than lighter ones when attached to the same spring.
By keeping \( A \) constant and varying \( m \), the exercise accentuates how these two parameters independently exert influence. However, the maximum speed is a function of both \( m \) and \( k \), as shown in the calculated slopes, reflecting SHM's intricate balance of energy distribution between kinetic and potential forms. Such relationships are key in understanding harmonic oscillators in more complex systems, ranging from mechanical structures to atomic particles.

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Most popular questions from this chapter

A thin metal disk with mass \(2.00 \times 10^{-3} \mathrm{~kg}\) and radius \(2.20 \mathrm{~cm}\) is attached at its center to a long fiber (Fig. \(\mathbf{E 1 4 . 4 0}\) ). The disk, when twisted and released, oscillates with a period of \(1.00 \mathrm{~s}\). Find the torsion constant of the fiber.

The jerk is defined to be the time rate of change of the acceleration. (a) If the velocity of an object undergoing SHM is given by \(v_{x}=-\omega A \sin (\omega t),\) what is the equation for the \(x\) -component of the jerk as a function of time? (b) What is the value of \(x\) for the object when the \(x\) -component of the jerk has its largest positive value? (c) What is \(x\) when the \(x\) -component of the jerk is most negative? (d) When it is zero? (e) If \(v_{x}\) equals \(-0.040 \mathrm{~s}^{2}\) times the \(x\) -component of the jerk for all \(t,\) what is the period of the motion?

Quantum mechanics is used to describe the vibrational motion of molecules, but analysis using classical physics gives some useful insight. In a classical model the vibrational motion can be treated as SHM of the atoms connected by a spring. The two atoms in a diatomic molecule vibrate about their center of mass, but in the molecule HI, where one atom is much more massive than the other, we can treat the hydrogen atom as oscillating in SHM while the iodine atom remains at rest. (a) A classical estimate of the vibrational frequency is \(f=7 \times 10^{13} \mathrm{~Hz}\). The mass of a hydrogen atom differs little from the mass of a proton. If the HI molecule is modeled as two atoms connected by a spring, what is the force constant of the spring? (b) The vibrational energy of the molecule is measured to be about \(5 \times 10^{-20} \mathrm{~J}\). In the classical model, what is the maximum speed of the H atom during its SHM? (c) What is the amplitude of the vibrational motion? How does your result compare to the equilibrium distance between the two atoms in the HI molecule, which is about \(1.6 \times 10^{-10} \mathrm{~m} ?\)

A holiday ornament in the shape of a hollow sphere with mass \(M=0.015 \mathrm{~kg}\) and radius \(R=0.050 \mathrm{~m}\) is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum with negligible friction. Calculate its period. (Hint: Use the parallel-axis theorem to find the moment of inertia of the sphere about the pivot at the tree limb.)

A block of mass \(m\) is undergoing SHM on a horizontal, frictionless surface while attached to a light, horizontal spring. The spring has force constant \(k\), and the amplitude of the \(\mathrm{SHM}\) is \(A\). The block has \(v=0,\) and \(x=+A\) at \(t=0 .\) It first reaches \(x=0\) when \(t=T / 4\) where \(T\) is the period of the motion. (a) In terms of \(T,\) what is the time \(t\) when the block first reaches \(x=A / 2 ?\) (b) The block has its maximum speed when \(t=T / 4\). What is the value of \(t\) when the speed of the block first reaches the value \(v_{\max } / 2 ?\) (c) Does \(v=v_{\max } / 2\) when \(x=A / 2 ?\)

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