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A sinusoidally varying driving force is applied to a damped harmonic oscillator of force constant \(k\) and mass \(m .\) If the damping constant has a value \(b_{1},\) the amplitude is \(A_{1}\) when the driving angular frequency equals \(\sqrt{k / m}\). In terms of \(A_{1}\), what is the amplitude for the same driving frequency and the same driving force amplitude \(F_{\max },\) if the damping constant is (a) \(3 b_{1}\) and (b) \(b_{1} / 2 ?\)

Short Answer

Expert verified
The amplitude \(A\) changes inversely with damping constant \(b\). So, for \(b = 3b_{1}\), the amplitude \(A_2 = A_{1} / 3\). For \(b = b_{1} / 2\), the amplitude \(A_3 = 2 A_{1}\).

Step by step solution

01

Understand the Background

Damped harmonic oscillators are systems that experience a restoring force proportional to displacement but also some form of resistance. This damping typically reduces the amplitude of the oscillator's motion over time. When a driving force is applied to such system, it causes oscillation at a certain amplitude which depends on the driving frequency, amplitude of the driving force, but critically here also the damping constant.
02

Derive the formula of amplitude with damping constant

The amplitude \(A\) of a damped harmonic oscillator driven by an external sinusoidal force can be expressed as \(A = F_{max} / \sqrt{(k - mω^2)^2 + (bω)^2 }\), where \(F_{max}\) is the amplitude of the driving force, \(k\) is the force constant, \(m\) is the mass, \(ω\) is the driving angular frequency, and \(b\) is the damping constant. Given the conditions of the problem, the driving angular frequency is equal to \(\sqrt{k / m}\), by plugging this into the equation, we get a simpler form: \(A = F_{max} / b\), since \(ω = \sqrt{k/m}\) leads to a zero in for \(k - mω^2\) in the equation.
03

Calculate the amplitude for \(3b_{1}\) and \(b_{1} / 2\)

With the equation from step 2, we can now substitute \(b\) with \(3b_{1}\) and \(b_{1}/2\) to get the new amplitudes. For \(3b_{1}\), the amplitude \(A_{2}\) is: \(A_{2} = F_{max} / 3b_{1} = A_{1} / 3\). Similarly for \(b_{1} / 2\), the amplitude \(A_{3}\) is: \(A_{3} = F_{max} / (b_{1}/2) = 2 A_{1}\).
04

Analyzing the results

It's clear that an increase in damping constant decreases the amplitude while a decrease in damping constant increases the amplitude, provided the driving frequency and force amplitude remain constant. This conforms to our intuitive understanding of damping.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Driving Force
Imagine pushing a child on a swing; each push you provide is akin to the driving force in a damped harmonic oscillator—it's what keeps the system moving. In physics, a driving force is generally a periodic external force that leads to the sustained oscillation of a system. When applied to a damped harmonic oscillator, this force can counteract the energy loss due to damping, thus maintaining the oscillation.

In our textbook problem, the driving force is sinusoidally varying, meaning it changes in a sine wave pattern, which is common in physical systems. The amplitude of this force, denoted by \( F_{\text{max}} \), is crucial as it directly affects the oscillation amplitude. If the driving force were to increase, the system would oscillate with greater amplitude—similar to how pushing the swing harder makes it go higher.
Damping Constant
The damping constant, represented by \( b \), measures the extent to which a force can slow down the motion in a damped harmonic oscillator. It's the numerical value behind what we often think of as 'resistance' or 'friction'. A high damping constant means the oscillation will fade out more quickly, while a low damping constant indicates a more persistent oscillation.

When observing different damping constants—such as \( 3b_1 \) and \( b_1 / 2 \) in the exercise—we see how changing \( b \) alters the oscillator's behavior. With \( 3b_1 \), the system experiences stronger resistance, leading to a smaller amplitude, as the formula \( A = F_{\text{max}} / 3b_{1} \) shows. Conversely, halving the damping constant allows for a larger amplitude \( A = F_{\text{max}} / (b_{1}/2) \). It’s akin to pushing the swing in a medium with varying air resistance—the thicker the air, the harder it is to maintain the swing’s motion.
Oscillation Amplitude
The term oscillation amplitude, symbolized by \( A \), is essentially the 'height' of the swing’s motion in our earlier analogy, representing the maximum extent of displacement from the equilibrium position in an oscillatory system. For a damped harmonic oscillator with a consistent driving force, the amplitude is determined not just by the driving force itself, but also by the interplay between the force constant, mass, driving frequency, and damping constant.

In the scenario presented in the textbook, modifications to the damping constant have a direct and predictable effect on the amplitude. If the damping is strong (\( 3b_1 \)), the amplitude shrinks, as demonstrated by \( A_{2} = A_{1} / 3 \). If the damping is weak (\( b_1 / 2 \)), the amplitude doubles, seen in \( A_{3} = 2 A_{1} \). This inverse relationship between damping constant and amplitude is a key concept to grasp when analyzing damped systems.
Angular Frequency
The angular frequency, denoted by \( \omega \), is akin to the speed at which you continuously push the swing to maintain its motion. In the realm of oscillations, it describes how rapidly the system oscillates in radians per unit time. It’s important to note that the angular frequency of the driving force need not match the natural frequency of the damped oscillator for the motion to ensue, but when it does, as in the case of resonance, the amplitude can reach its peak value.

In our textual exercise, the driving angular frequency is set to \( \sqrt{k/m} \), the system's natural frequency. At this precise frequency, the formula simplifies, leading to the aforementioned relationship between damping constant and amplitude. This holds true as long as the system operates under a constant driving force and frequency, emphasizing the fundamental role of angular frequency in understanding damped oscillations.

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Most popular questions from this chapter

A thin metal disk with mass \(2.00 \times 10^{-3} \mathrm{~kg}\) and radius \(2.20 \mathrm{~cm}\) is attached at its center to a long fiber (Fig. \(\mathbf{E 1 4 . 4 0}\) ). The disk, when twisted and released, oscillates with a period of \(1.00 \mathrm{~s}\). Find the torsion constant of the fiber.

SHM of a Floating Object. An object with height \(h\)mass \(M\), and a uniform cross-sectional area \(A\) floats upright in a liquid with density \(\rho\). (a) Calculate the vertical distance from the surface of the liquid to the bottom of the floating object at equilibrium. (b) A downward force with magnitude \(F\) is applied to the top of the object. At the new equilibrium position, how much farther below the surface of the liquid is the bottom of the object than it was in part (a)? (Assume that some of the object remains above the surface of the liquid.) (c) Your result in part (b) shows that if the force is suddenly removed, the object will oscillate up and down in SHM. Calculate the period of this motion in terms of the density \(\rho\) of the liquid, the mass \(M,\) and the cross-sectional area \(A\) of the object. You can ignore the damping due to fluid friction (see Section 14.7).

The tip of a tuning fork goes through 440 complete vibrations in \(0.500 \mathrm{~s}\). Find the angular frequency and the period of the motion.

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A \(2.00 \mathrm{~kg},\) frictionless block is attached to an ideal spring with force constant \(300 \mathrm{~N} / \mathrm{m}\). At \(t=0\) the spring is neither stretched nor compressed and the block is moving in the negative direction at \(12.0 \mathrm{~m} / \mathrm{s} .\) Find (a) the amplitude and (b) the phase angle. (c) Write an equation for the position as a function of time.

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