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A \(1.80 \mathrm{~kg}\) monkey wrench is pivoted \(0.250 \mathrm{~m}\) from its center of mass and allowed to swing as a physical pendulum. The period for small-angle oscillations is \(0.940 \mathrm{~s}\). (a) What is the moment of inertia of the wrench about an axis through the pivot? (b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position?

Short Answer

Expert verified
The moment of inertia of the wrench is approximately 0.171 kg.m^2 and the angular speed of wrench as it passes through the equilibrium position is approximately 5.63 rad/s.

Step by step solution

01

Calculation of Moment of Inertia

The formula for the period \(T\) of a physical pendulum is given as \(T = 2\pi \sqrt{\frac{I}{mgd}}\), where \(m\) is the mass of the object (1.80 kg), \(g\) is the acceleration due to gravity (approximately \(9.81 \, m/s^2\)), \(d\) is the distance from the pivot point to the center of mass (0.250 m), and \(I\) is the moment of inertia. Since we need to find \(I\), we can rearrange the formula and substitute the known values: \[ I = \frac{T^2m^2gd}{4\pi^2} = \frac{(0.940^2(1.80^2)(9.81)\times0.250}{4\pi^2} \]
02

Calculation of Angular Speed

In order to find the angular speed at the equilibrium position, it is important to understand that as the wrench swings from the initial position to the equilibrium point its potential energy converts into kinetic energy. So, equate the initial potential energy (\(m*g*d*θ_i\)) to the final kinetic energy \(\frac{1}{2}Iw_f^2)\). Where \(θ_i\) is the initial angular displacement (0.400 rad) and \(w_f\) is the final angular speed we're trying to find. Rearranging for \(w_f\) and substituting the known values gives: \[w_f = \sqrt{\frac{2m \cdot g \cdot d \cdot θ_i}{I}}\]
03

Calculate the values

Now we need to substitute the values into the formulas obtained in Step 1 and Step 2 and compute the numerical values for the moment of inertia and the angular speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Moment of Inertia
The moment of inertia, often denoted as "I," is a critical concept in the study of rotational motion. It represents how an object’s mass is distributed relative to an axis of rotation. In simpler terms, it's like a measure of an object's resistance to changes in its rotational motion.
For a physical pendulum, which is what we have with the monkey wrench, the formula \[I = \frac{T^2 m^2 g d}{4\pi^2}\] allows us to calculate the moment of inertia, where:
  • \(I\) is the moment of inertia.
  • \(T\) is the oscillation period (0.940 seconds in this case).
  • \(m\) is mass (1.80 kg for the wrench).
  • \(g\) is the acceleration due to gravity, approximately \(9.81 \, \text{m/s}^2\).
  • \(d\) is the distance from the pivot point to the center of mass (0.250 m).
By substituting the given values into the formula, you can determine the moment of inertia, gaining insight into how the mass of the wrench affects its swing.
Period of Oscillation
The oscillation period of a physical pendulum is the time it takes to complete one full back-and-forth movement. It's an essential concept because it describes how quickly or slowly the pendulum swings. The formula used to calculate this period for a physical pendulum is: \[T = 2\pi \sqrt{\frac{I}{mgd}}\] Here:
  • \(T\) represents the period of the pendulum.
  • \(I\) is the moment of inertia.
  • \(m\) is the mass of the pendulum.
  • \(g\) is the gravitational acceleration.
  • \(d\) is the distance from the pivot to the center of mass.
In this equation, you can see that the period is directly related to the moment of inertia. A greater moment of inertia means a longer period. Knowing the oscillation period helps us understand the dynamics of the pendulum, such as how it will behave under different initial displacements.
Exploring Angular Displacement
Angular displacement is the measure of the angle through which an object has rotated or moved from a specific starting point. In the context of a pendulum, it's the initial angle at which the pendulum is released from rest. This angle influences how the pendulum swings.
For the monkey wrench example, the initial angular displacement is given as 0.400 radians. This initial angle affects the potential energy at the start. As the pendulum swings towards the equilibrium position, this angle decreases until it reaches zero.
By understanding the concept of angular displacement, you can predict and calculate the behavior of the pendulum throughout its swinging motion, such as determining the maximum speed at different points during the swing.
Principles of Energy Conservation
Energy conservation is a foundational principle in physics, highlighting that within an isolated system, energy cannot be created or destroyed, only transformed. In our pendulum scenario, the transformation occurs between potential and kinetic energy.
Initially, when the wrench is displaced from its equilibrium position, it has maximum potential energy due to its height relative to the pivot. This potential energy is given by \[m \cdot g \cdot d \cdot \theta_i\] As the pendulum swings towards equilibrium, this potential energy transforms into kinetic energy, which is expressed as \[\frac{1}{2}Iw^2\] Here:
  • \(\theta_i\) is the initial angular displacement.
  • \(w\) is the angular speed.
By equating these two expressions and solving for the unknowns, such as the angular speed at the equilibrium, we apply the conservation of energy principle. This conversion process is key in predicting how fast the pendulum will move as it passes through its lowest point, where it possesses maximum kinetic and zero potential energy.

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Most popular questions from this chapter

You want to find the moment of inertia of a complicated machine part about an axis through its center of mass. You suspend it from a wire along this axis. The wire has a torsion constant of \(0.450 \mathrm{~N} \cdot \mathrm{m} / \mathrm{rad}\). You twist the part a small amount about this axis and let it go, timing 165 oscillations in \(265 \mathrm{~s}\). What is its moment of inertia?

The jerk is defined to be the time rate of change of the acceleration. (a) If the velocity of an object undergoing SHM is given by \(v_{x}=-\omega A \sin (\omega t),\) what is the equation for the \(x\) -component of the jerk as a function of time? (b) What is the value of \(x\) for the object when the \(x\) -component of the jerk has its largest positive value? (c) What is \(x\) when the \(x\) -component of the jerk is most negative? (d) When it is zero? (e) If \(v_{x}\) equals \(-0.040 \mathrm{~s}^{2}\) times the \(x\) -component of the jerk for all \(t,\) what is the period of the motion?

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You are watching an object that is moving in SHM. When the object is displaced \(0.600 \mathrm{~m}\) to the right of its equilibrium position, it has a velocity of \(2.20 \mathrm{~m} / \mathrm{s}\) to the right and an acceleration of \(8.40 \mathrm{~m} / \mathrm{s}^{2}\) to the left. How much farther from this point will the object move before it stops momentarily and then starts to move back to the left?

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