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Two uniform spheres, each with mass \(M\) and radius \(R\), touch each other. What is the magnitude of their gravitational force of attraction?

Short Answer

Expert verified
The magnitude of the gravitational force of attraction between the two spheres is \(F = G * M^2 / 4R^2\).

Step by step solution

01

Identify known variables

From the problem statement, we know the mass (\(M\)) of the two spheres, the radius (\(R\)) of the spheres, and the gravitational constant (\(G\)). Here the distance between the centers of the two spheres is \(2R\) because the spheres are touching each other.
02

Substitute known variables into the formula

Next, we can substitute the known variables into the formula for gravitational force. This gives us \(F = G * (M * M) / (2R)^2\).
03

Simplify the equation

By simplifying the equation, we get \(F = G * M^2 / 4R^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's law of universal gravitation
Understanding Newton's law of universal gravitation is central to grasping the fundamental forces that govern celestial bodies. This law posits that every mass exerts an attractive force on every other mass. The strength of this gravitational pull is directly proportional to the product of the two masses and inversely proportional to the square of the distance between their centers.

This concept is neatly captured by the formula: \[ F = G \frac{m_1 m_2}{r^2} \] Here, \( F \) is the gravitational force, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses, and \( r \) is the distance between the centers of the two masses. When studying the gravitational attraction between two objects, this law allows us to predict the force with which they will draw each other closer.
Gravitational constant
The gravitational constant, symbolized as \( G \), is a key factor in calculating gravitational forces. It is a universal value that determines the strength of gravity in the equation of Newton's law of universal gravitation.

The gravitational constant has been experimentally measured to be approximately \( 6.674 \times 10^{-11} \text{Nm}^2/\text{kg}^2 \). Although this number seems very small, it's crucial to understand that the effects of gravity become significant over large masses or over short distances. Whenever we use the formula for gravitational force, the constant \( G \) helps us to ensure that we get the force value in newtons, providing consistency and reliability in calculations across all gravitational problems.
Mass and radius relation
The relationship between mass and radius in the context of gravitational force is vital to comprehend. This relation comes into play when we're dealing with spherical objects, where the mass distribution is assumed to be uniform.

An important point to note is that the gravitational force does not depend on the surface area of the spheres but rather on the radius—or distance to the center—where all the mass can be assumed to be concentrated for the purpose of these calculations. This principle dramatically simplifies the calculations for gravitational force between spherical bodies, because we can treat them as point masses located at their centers, as long as we are only concerned with the gravitational forces they exert on each other.
Force between uniform spheres
When it comes to calculating the gravitational force between two uniform spheres, such as in our given problem, it is important to apply Newton's law with the understanding that the distance used in the computation is the distance between the spheres' centers.

In our exercise, since the spheres are touching, the distance \( r \) is equal to twice the radius \( R \), or \( 2R \). Subsequently, because the spheres are uniform and identical with mass \( M \), our formula simplifies to \[ F = G \frac{M^2}{(2R)^2} = G \frac{M^2}{4R^2} \]. This simplified expression underscores the inverse square relation of the force to the distance between the centers of the two spheres. The calculation demonstrates how an increase in distance would decrease the gravitational force, illuminating the delicate balance of gravitational interactions in our universe.

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Most popular questions from this chapter

Rhea, one of Saturn's moons, has a radius of \(764 \mathrm{~km}\) and an acceleration due to gravity of \(0.265 \mathrm{~m} / \mathrm{s}^{2}\) at its surface. Calculate its mass and average density.

A uniform, spherical, \(1000.0 \mathrm{~kg}\) shell has a radius of \(5.00 \mathrm{~m} .\) (a) Find the gravitational force this shell exerts on a \(2.00 \mathrm{~kg}\) point mass placed at the following distances from the center of the shell: (i) \(5.01 \mathrm{~m}\). (ii) \(4.99 \mathrm{~m},\) (iii) \(2.72 \mathrm{~m}\). (b) Sketch a qualitative graph of the magnitude of the gravitational force this sphere exerts on a point mass \(m\) as a function of the distance \(r\) of \(m\) from the center of the sphere. Include the region from \(r=0\) to \(r \rightarrow \infty\)

DATA For a spherical planet with mass \(M,\) volume \(V,\) and radius \(R,\) derive an expression for the acceleration due to gravity at the planet's surface, \(g\), in terms of the average density of the planet, \(\rho=M / V,\) and the planet's diameter, \(D=2 R .\) The table gives the values of \(D\) and \(g\) for the eight major planets: $$ \begin{array}{lrc} \text { Planet } & D(\mathrm{~km}) & g\left(\mathrm{~m} / \mathrm{s}^{2}\right) \\ \hline \text { Mercury } & 4879 & 3.7 \\ \text { Venus } & 12,104 & 8.9 \\ \text { Earth } & 12,756 & 9.8 \\ \text { Mars } & 6792 & 3.7 \\ \text { Jupiter } & 142,984 & 23.1 \\ \text { Saturn } & 120,536 & 9.0 \\ \text { Uranus } & 51,118 & 8.7 \\ \text { Neptune } & 49.528 & 11.0 \end{array} $$ (a) Treat the planets as spheres. Your equation for \(g\) as a function of \(\rho\) and \(D\) shows that if the average density of the planets is constant, a graph of \(g\) versus \(D\) will be well represented by a straight line. Graph 8 as a function of \(D\) for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of \(g\) at Saturn's surface?

Binary Star-Equal Masses. Two identical stars with mass \(M\) orbit around their center of mass. Each orbit is circular and has radius \(R,\) so that the two stars are always on opposite sides of the circle. (a) Find the gravitational force of one star on the other. (b) Find the orbital speed of each star and the period of the orbit. (c) How much energy would be required to separate the two stars to infinity?

Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was \(2.87 \times 10^{6} \mathrm{~km}\) from the earth and traveling at \(1.20 \times 10^{4} \mathrm{~km} / \mathrm{h}\) relative to the earth. At this time, what were (a) the spacecraft's kinetic energy relative to the earth and (b) the potential energy of the earthspacecraft system?

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