/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A \(0.180 \mathrm{~kg}\) cube of... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(0.180 \mathrm{~kg}\) cube of ice (frozen water) is floating in glycerin. The gylcerin is in a tall cylinder that has inside radius \(3.50 \mathrm{~cm} .\) The level of the glycerin is well below the top of the cylinder. If the ice completely melts, by what distance does the height of liquid in the cylinder change? Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerin before the ice melted?

Short Answer

Expert verified
The height of the glycerin that the water from the melted ice occupies (\(h_f\)) is smaller than the height of the glycerin displaced by the ice (\(h_i\)). Therefore, the liquid level in the cylinder falls after the ice melts.

Step by step solution

01

Calculate the volume of the gylcerin displaced by the ice

The ice floats in the glycerin, so the weight of the ice is equal to the weight of the glycerin it displaces, according to Archimedes' Principle. The weight of an object is its mass times the acceleration due to gravity, so the weight of the ice is \(0.180 \mathrm{~kg}\) times \(9.80 \mathrm{~m/s}^2\). Let's call the volume of the gylcerin displaced by the ice as \(V_i\). The weight of this volume of glycerin is the volume times the density of glycerin times the gravity. So, by equating the two weights, we can then solve for \(V_i\) knowing that the density of the glycerin is \(\approx 1260 \mathrm{~kg/m}^3\).
02

Find the height of the glycerin that corresponds to \(V_i\)

The volume of a portion of the cylinder that the glycerin occupies is the cross-sectional area of the cylinder times the height that the liquid fills. The cross-sectional area is \(\pi\) times the radius squared, which we know is \(3.5 \mathrm{~cm}\) or \(0.035 \mathrm{~m}\). By equating the volume \(V_i\) to the product of the area and the height (denoted as \(h_i\)), we can solve for \(h_i\).
03

Calculate the volume occupied by the melted ice

When the ice melts, it turns into water and its volume changes. The mass of the melted ice remains the same, but the density changes to that of water, which is \(\approx 1000 \mathrm{~kg/m}^3\). We can determine the volume of the melted ice (now water) by dividing the mass of the ice by the density of water.
04

Determine the height of the glycerin equivalent to the volume of the melted ice

Using a similar approach as in Step 2, equate the volume of the melted ice to the product of the cross-sectional area of the cylinder and the height \(h_f\). Solving for \(h_f\) will give us the height of the glycerin that the water from the melted ice will occupy.
05

Determine whether the liquid level rises or falls

We can determine whether the liquid level rises or falls after the ice melts by comparing \(h_i\) and \(h_f\). If \(h_i\) is higher than \(h_f\), then the liquid level falls. Otherwise, the liquid level rises.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyancy
Buoyancy is the force that allows objects to float or rise when submerged in a fluid, such as water or air. This force is crucial in understanding why objects like ships float and why hot air balloons rise. Archimedes' Principle states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. Imagine you're holding a ball under water; the buoyant force is the 'push' you feel on the ball from the water. This is why balloons filled with helium gas float up into the sky - the density of helium is lower than that of atmospheric air, resulting in a buoyant force that propels the balloon upward.

Improving comprehension of buoyancy involves visualizing this concept. Picture a cube of ice floating in a glass of water; the ice receives an upward push from the water which is equal to the weight of the water displaced by the submerged part of the ice cube. In the case of our exercise, we consider the ice cube in glycerin, where the same principle applies. By understanding buoyancy, one can better grasp why, when the ice melts, the level of glycerin in our cylinder will adjust based on the volume the ice originally displaced.
Density
Density, fundamentally, is the measure of how much mass is contained within a certain volume of a substance and is usually expressed in units such as \( \mathrm{kg/m}^3 \). It's a vital concept when discussing buoyancy and fluid mechanics, as the density of an object compared to the density of the fluid it's in, determines whether it will sink or float. For instance, ice is less dense than liquid water, which is why it floats. This principle is employed when solving our exercise, considering the densities of ice, glycerin and water.

When the density of the object is less than the density of the fluid, buoyancy can support the object, and it floats. Conversely, an object denser than the fluid will sink. Comprehending density requires understanding that it's a ratio; a small object can be denser than a larger one if it has much more mass packed in its volume. Applying this to our exercise, knowing the densities of ice, water and glycerin helps predict the changes in the liquid's height in the cylinder after the ice has melted.
Fluid Mechanics
Fluid mechanics is the branch of physics that studies the behavior of fluids (liquids and gases) and the forces on them. It's a vast field with applications ranging from designing water supply systems to studying weather patterns to explaining how blood flows through the body. For our exercise, we leverage fluid mechanics to determine the interaction between the ice (a solid) and glycerin (a liquid).

The concepts of pressure, density, and buoyancy are all part of fluid mechanics. Pressure in a fluid increases with depth due to the weight of the fluid above. This is why the buoyant force, which depends on the volume of fluid displaced, acts upwards against gravity. Emphasizing real-world examples, such as why certain objects float in a swimming pool while others sink, can enhance understanding of fluid mechanics. When the ice melts in our scenario, fluid mechanics principles guide us to understand how the glycerin level shifts in response to the dissolved ice now evenly distributed throughout the cylinder.

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Most popular questions from this chapter

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