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His body is again leaning back at \(30.0^{\circ}\) to the vertical, but now the height at which the rope is held above-but still parallel to - the ground is varied. The tension in the rope in front of the competitor \(\left(T_{1}\right)\) is measured as a function of the shortest distance between the rope and the ground (the holding height). Tension \(T_{1}\) is found to decrease as the holding height increases. What could explain this observation? As the holding height increases, (a) the moment arm of the rope about his feet decreases due to the angle that his body makes with the vertical; (b) the moment arm of the weight about his feet decreases due to the angle that his body makes with the vertical; (c) a smaller tension in the rope is needed to produce a torque sufficient to balance the torque of the weight about his feet; (d) his center of mass moves down to compensate, so less tension in the rope is required to maintain equilibrium.

Short Answer

Expert verified
The tension in the rope decreases as the holding height increases because of two reasons: First, the moment arm of the rope about his feet decreases due to the angle that his body makes with the vertical, necessitating less torque to maintain balance. Secondly, a smaller tension in the rope is needed to produce sufficient torque to balance the torque of the weight about his feet.

Step by step solution

01

Understanding the situation

The competitor is leaning back, holding a rope. As the height at which the rope is held increases, it was observed that the tension in the rope decreases. Various factors could possibly explain this observation.
02

Analyzing option (a)

In option (a), it is suggested that as the holding height of the rope increases, the moment arm of the rope about his feet decreases due to the angle that his body makes with the vertical. The moment arm is the perpendicular distance from the axis of rotation to the line along which the force acts. If this distance decreases, for the same force, the torque would decrease. Therefore this option offers a plausible explanation.
03

Analyzing option (b)

In option (b), the suggestion is that as the height increases, the moment arm of the weight about his feet decreases due to the angle that his body makes with the vertical. However, if the body position doesn't change, there's no reason to believe that the moment arm of the weight changes. Thus, option (b) is not a valid explanation.
04

Analyzing option (c)

Option (c) suggests that a smaller tension in the rope is needed to produce a torque sufficient to balance the torque of the weight about his feet as the height increases. This is true, because as the angle increases and the moment arm decreases, it requires less force (or tension) to balance out the torques, that is, to maintain equilibrium. Thus, option (c) also presents a valid explanation.
05

Analyzing option (d)

Option (d) suggests that as the height increases, his center of mass moves down to compensate, so less tension in the rope is required to maintain equilibrium. It implies that the competitor changes his body position (or posture) as the holding height changes. This option could be valid if the competitor changes his posture to maintain equilibrium he'll have to apply less tension in the rope. However, without additional information that the competitor is indeed changing posture, this option remains speculative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque and Equilibrium
Imagine playing on a seesaw. When both players are equally distant from the pivot and have similar weights, the seesaw remains level. This is a simple example of equilibrium. In physics, equilibrium occurs when all the forces and torques, or rotational forces, acting on a system cancel each other out.

Torque is what causes objects to rotate and depends not only on the force applied but also on where the force is applied and the angle at which it is applied. It can be calculated using the mathematical formula \( \tau = r \times F \times \sin(\theta) \), where \( \tau \) is the torque, \( r \) is the moment arm, \( F \) is the applied force, and \( \theta \) is the angle between the force and the lever arm. In the case of the competitor holding the rope, achieving a state of equilibrium means that the torque he generates by leaning back must exactly match the torque from the weight of his body to prevent rotation. This balance is what allows him to stay in one position without tipping over.

Any shift in the holding height of the rope affects the length of the moment arm and, consequently, the torque. As the competitor increases the holding height, the moment arm shortens, reducing the required tension to balance the torques. This helps maintain equilibrium with less effort, which provides one plausible explanation for why the tension \( T_1 \) decreases.
Moment Arm
The moment arm is a key concept to understand when looking into rotational motion and torque. Think of it as the handle of a door. When you push on a door handle, the door swings open. Now imagine if you had to push at a point closer to the hinges – it would be harder because you would have less leverage.

The moment arm is the perpendicular distance from the axis of rotation to the line of action of the force. The greater the distance, the less force needed to create the same torque. In the textbook exercise, as the height where the rope is held increases, the competitor's body leans back, creating a smaller angle with the vertical. As a result, the moment arm – the distance from his feet where the force of the tension acts – decreases. The relationship between the length of the moment arm and the tension in the rope is inversely proportional which means that as one decreases, the other one does as well. Therefore, a shortened moment arm requires less tension to produce the same balancing torque. This concept explains why less tension is needed when the holding height is greater.
Center of Mass
The center of mass of an object is the point where mass is evenly distributed in all directions. It's similar to the balancing point of an object. For humans, the center of mass is typically located around the hips, but it shifts with body position. When standing upright, if you were holding a heavy object in front of you, your body would naturally lean backward to keep your center of mass over your feet and maintain balance.

In the scenario presented in the exercise, the competitor is leaning back at an angle, suggesting a shift in his center of mass as he attempts to counterbalance his weight against the tension in the rope. If the competitor was to increase the height at which he holds the rope, one could speculate that his center of mass would lower closer to his feet due to the changes in angles and the necessary adjustments in posture to maintain equilibrium. This lowering of the center of mass could reduce the amount of tension needed in the rope, since the overall system would require less effort to balance. Therefore, a shift in the center of mass, if occurring, aligns with the concept that a smaller tension is necessary to maintain equilibrium as the holding height increases, offering a possible, albeit less certain, explanation for the decrease in rope tension.

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Most popular questions from this chapter

The compressive strength of our bones is important in everyday life. Young's modulus for bone is about \(1.4 \times 10^{10} \mathrm{~Pa}\). Bone can take only about a \(1.0 \%\) change in its length before fracturing. (a) What is the maximum force that can be applied to a bone whose minimum cross-sectional area is \(3.0 \mathrm{~cm}^{2} ?\) (This is approximately the cross-sectional area of a tibia, or shin bone, at its narrowest point.) (b) Estimate the maximum height from which a \(70 \mathrm{~kg}\) man could jump and not fracture his tibia. Take the time between when he first touches the floor and when he has stopped to be \(0.030 \mathrm{~s}\), and assume that the stress on his two legs is distributed equally.

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A relaxed biceps muscle requires a force of \(25.0 \mathrm{~N}\) for an elongation of \(3.0 \mathrm{~cm} ;\) the same muscle under maximum tension requires a force of \(500 \mathrm{~N}\) for the same elongation. Find Young's modulus for the muscle tissue under each of these conditions if the muscle is assumed to be a uniform cylinder with length \(0.200 \mathrm{~m}\) and cross- sectional area \(50.0 \mathrm{~cm}^{2}\).

A uniform rod is \(2.00 \mathrm{~m}\) long and has mass \(1.80 \mathrm{~kg} .\) A \(2.40 \mathrm{~kg}\) clamp is attached to the rod. How far should the center of gravity of the clamp be from the left-hand end of the rod in order for the center of gravity of the composite object to be \(1.20 \mathrm{~m}\) from the left-hand end of the rod?

A therapist tells a \(74 \mathrm{~kg}\) patient with a broken leg that he must have his leg in a cast suspended horizontally. For minimum discomfort, the leg should be supported by a vertical strap attached at the center of mass of the leg-cast system (Fig. \(\mathbf{P} 11.55\) ). To comply with these instructions, the patient consults a table of typical mass distributions and finds that both upper legs (thighs) together typically account for \(21.5 \%\) of body weight and the center of mass of each thigh is \(18.0 \mathrm{~cm}\) from the hip joint. The patient also reads that the two lower legs (including the feet) are \(14.0 \%\) of body weight, with a center of mass \(69.0 \mathrm{~cm}\) from the hip joint. The cast has a mass of \(5.50 \mathrm{~kg}\), and its center of mass is \(78.0 \mathrm{~cm}\) from the hip joint. How far from the hip joint should the supporting strap be attached to the cast?

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